Question about 'sizeof'

[SM]

Hello,
I have another simple question about an array in PHP and a variable in
PHP.

This is the array:

$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);


$thumbs_cat_2 = array(
'hello',
'goodbye'
);


This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4

$item_total = sizeof($thumbs_ cat_2);
output: 2


Now, i want to replace the parameter in 'sizeof' by a variable

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

Thanks
Marco

[Piotr]

Re: Question about 'sizeof'

SM wrote:

Hello,
I have another simple question about an array in PHP and a variable in
PHP.
>
This is the array:
>
$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);
>
>
$thumbs_cat_2 = array(
'hello',
'goodbye'
);
>
>
This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4
>
$item_total = sizeof($thumbs_ cat_2);
output: 2
>
>
Now, i want to replace the parameter in 'sizeof' by a variable
>
$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1
>
$item_total = sizeof($item);
output: Nothing!
>
How do i pass a variable to the 'sizeof' function?

You should use variable variable:
$item_total = sizeof($$item);

Mark double $$
This is true in any situation, not only with sizeof

best regards
Piotr N

[ELINTPimp]

Re: Question about 'sizeof'

On May 8, 11:15 am, SM <servandomont.. .@gmail.comwrot e:

Hello,
I have another simple question about an array in PHP and a variable in
PHP.
>
This is the array:
>
$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);
>
$thumbs_cat_2 = array(
'hello',
'goodbye'
);
>
This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4
>
$item_total = sizeof($thumbs_ cat_2);
output: 2
>
Now, i want to replace the parameter in 'sizeof' by a variable
>
$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1
>
$item_total = sizeof($item);
output: Nothing!
>
How do i pass a variable to the 'sizeof' function?
>
Thanks
Marco

Marco,

You should be getting a return of 1 (integer) for a string passed to
the count() function. (sizeof is an alias of count)

To get the length of a string, you would traditionally use
strlen($item), which would return the length of a string.

Regards,

Steve

[ELINTPimp]

Re: Question about 'sizeof'

On May 8, 11:36 am, ELINTPimp <smsi...@gmail. comwrote:

On May 8, 11:15 am, SM <servandomont.. .@gmail.comwrot e:
>
>
>

Hello,
I have another simple question about an array in PHP and a variable in
PHP.

>

This is the array:

>

$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);

>

$thumbs_cat_2 = array(
'hello',
'goodbye'
);

>

This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4

>

$item_total = sizeof($thumbs_ cat_2);
output: 2

>

Now, i want to replace the parameter in 'sizeof' by a variable

>

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

>

$item_total = sizeof($item);
output: Nothing!

>

How do i pass a variable to the 'sizeof' function?

>

Thanks
Marco

>
Marco,
>
You should be getting a return of 1 (integer) for a string passed to
the count() function. (sizeof is an alias of count)
>
To get the length of a string, you would traditionally use
strlen($item), which would return the length of a string.
>
Regards,
>
Steve

Ahhh, now i understand after reading Pitor's reply. Yes, he is
correct, I read the question differently.

Steve

[Piotr]

Re: Question about 'sizeof'

>$thumb = 1;

>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
>$thumbs_cat_ 1
>>
>$item_total = sizeof($item);
>output: Nothing!
>>
>How do i pass a variable to the 'sizeof' function?

>
You should use variable variable:
$item_total = sizeof($$item);
>
Mark double $$
This is true in any situation, not only with sizeof

Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';

best regards
Piotr N

[SM]

Re: Question about 'sizeof'

On May 8, 11:36 am, ELINTPimp <smsi...@gmail. comwrote:

On May 8, 11:15 am, SM <servandomont.. .@gmail.comwrot e:
>
>
>

Hello,
I have another simple question about an array in PHP and a variable in
PHP.

>

This is the array:

>

$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);

>

$thumbs_cat_2 = array(
'hello',
'goodbye'
);

>

This will work:
$item_total = sizeof($thumbs_ cat_1);
output: 4

>

$item_total = sizeof($thumbs_ cat_2);
output: 2

>

Now, i want to replace the parameter in 'sizeof' by a variable

>

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

>

$item_total = sizeof($item);
output: Nothing!

>

How do i pass a variable to the 'sizeof' function?

>

Thanks
Marco

>
Marco,
>
You should be getting a return of 1 (integer) for a string passed to
the count() function. (sizeof is an alias of count)
>
To get the length of a string, you would traditionally use
strlen($item), which would return the length of a string.
>
Regards,
>
Steve

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = '$thumbs_cat_' . $thumb;
$item_total = count($item);

Thanks again
Marco

[SM]

Re: Question about 'sizeof'

On May 8, 11:42 am, Piotr <s...@poczta.on et.plwrote:

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

>

$item_total = sizeof($item);
output: Nothing!

>

How do i pass a variable to the 'sizeof' function?

>

You should use variable variable:
$item_total = sizeof($$item);

>

Mark double $$
This is true in any situation, not only with sizeof

>
Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';
>
best regards
Piotr N

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($item);

Thanks again
Marco

[SM]

Re: Question about 'sizeof'

On May 8, 11:42 am, Piotr <s...@poczta.on et.plwrote:

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

>

$item_total = sizeof($item);
output: Nothing!

>

How do i pass a variable to the 'sizeof' function?

>

You should use variable variable:
$item_total = sizeof($$item);

>

Mark double $$
This is true in any situation, not only with sizeof

>
Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';
>
best regards
Piotr N

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);

Thanks again
Marco

[SM]

Re: Question about 'sizeof'

On May 8, 11:50 am, SM <servandomont.. .@gmail.comwrot e:

On May 8, 11:42 am, Piotr <s...@poczta.on et.plwrote:
>
>
>

>$thumb = 1;
>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
>$thumbs_cat_ 1

>

>$item_total = sizeof($item);
>output: Nothing!

>

>How do i pass a variable to the 'sizeof' function?

>

You should use variable variable:
$item_total = sizeof($$item);

>

Mark double $$
This is true in any situation, not only with sizeof

>

Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';

>

best regards
Piotr N

>
I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!
>
Heres the final code:
>
$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);
>
Thanks again
Marco

Maybe i should open a new post for this one, but here it goes:

I'm stock! When i want to reference that variable in a echo statment,
it does't work. Any suggestions?
Thanks

<li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
$category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
alt="" /></a></li>

[Piotr]

Re: Question about 'sizeof'

SM wrote:

On May 8, 11:50 am, SM <servandomont.. .@gmail.comwrot e:

>On May 8, 11:42 am, Piotr <s...@poczta.on et.plwrote:
>>
>>
>>

>>>>$thumb = 1;
>>>>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
>>>>$thumbs_cat _1
>>>>$item_tot al = sizeof($item);
>>>>output: Nothing!
>>>>How do i pass a variable to the 'sizeof' function?
>>>You should use variable variable:
>>>$item_tota l = sizeof($$item);
>>>Mark double $$
>>>This is true in any situation, not only with sizeof
>>Forgot about one small detail:
>>$item = 'thumbs_cat_' . $thumb; //this outputs a string:
>>---------^ loose the '$';
>>best regards
>>Piotr N

>I don't need the length of the string , just the actual variable. But
>i did like the fact that sizeof is an alias of count. So i will use
>count instead.
>I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!
>>
>Heres the final code:
>>
>$thumb = 1;
>$item = 'thumbs_cat_' . $thumb;
>$item_total = count($$item);
>>
>Thanks again
>Marco

>
Maybe i should open a new post for this one, but here it goes:
>
I'm stock! When i want to reference that variable in a echo statment,
it does't work. Any suggestions?
Thanks
>
<li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
$category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
alt="" /></a></li>

:)
It should look like this. Mark the { and }
echo ${$item[$i]};

As a side note, is this really best way to access needed data this way ?
Cant you keep original values in the array instead of the variable names ?

best regards
Piotr N

[SM]

Re: Question about 'sizeof'

On May 8, 12:31 pm, Piotr <s...@poczta.on et.plwrote:

SM wrote:

On May 8, 11:50 am, SM <servandomont.. .@gmail.comwrot e:

On May 8, 11:42 am, Piotr <s...@poczta.on et.plwrote:

>

>>>$thumb = 1;
>>>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
>>>$thumbs_cat_ 1
>>>$item_tota l = sizeof($item);
>>>output: Nothing!
>>>How do i pass a variable to the 'sizeof' function?
>>You should use variable variable:
>>$item_total = sizeof($$item);
>>Mark double $$
>>This is true in any situation, not only with sizeof
>Forgot about one small detail:
>$item = 'thumbs_cat_' . $thumb; //this outputs a string:
>---------^ loose the '$';
>best regards
>Piotr N
I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

>

Heres the final code:

>

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);

>

Thanks again
Marco

>

Maybe i should open a new post for this one, but here it goes:

>

I'm stock! When i want to reference that variable in a echo statment,
it does't work. Any suggestions?
Thanks

>

<li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
$category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
alt="" /></a></li>

>
:)
It should look like this. Mark the { and }
echo ${$item[$i]};
>
As a side note, is this really best way to access needed data this way ?
Cant you keep original values in the array instead of the variable names ?
>
best regards
Piotr N

I've tried it, It doesn't work. When i look at the source code, i see
empty an empty string:
<img src="images/" alt="" />

Here's what im trying to do:
-From a list, the user selects the type of discography (either
original, compilation, tributes, other)
-Each type of discography is associated with an array that contains
the name of the cd cover.
-Then i show a thumbnail (using a loop) of all the cd covers depending
on the array.

my arrays look like this
$thumbs_cat_1 = array('moonligh t.jpg'', shadow.jpg', 'luna');
$thumbs_cat_2 = array(...);
$thumbs_cat_3 = array(...);
$thumbs_cat_4 = array(...);

the thumbs look like this:
for($i=0; ...){
....<img src="images/discography/thumbs/<?php echo $thumbs_cat_1[$i]; ?

>" alt="" />

}

All of this , works for the first array.
That's why i have a variable that contains the selection from the
user:
$thumb = $_GET['cat'];
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);
.... and so on

That's why i need to create images according to the user selection

Any ideas what's wrong with the code?
Thanks
Marco

[SM]

Re: Question about 'sizeof'

On May 8, 12:31 pm, Piotr <s...@poczta.on et.plwrote:

SM wrote:

On May 8, 11:50 am, SM <servandomont.. .@gmail.comwrot e:

On May 8, 11:42 am, Piotr <s...@poczta.on et.plwrote:

>

>>>$thumb = 1;
>>>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
>>>$thumbs_cat_ 1
>>>$item_tota l = sizeof($item);
>>>output: Nothing!
>>>How do i pass a variable to the 'sizeof' function?
>>You should use variable variable:
>>$item_total = sizeof($$item);
>>Mark double $$
>>This is true in any situation, not only with sizeof
>Forgot about one small detail:
>$item = 'thumbs_cat_' . $thumb; //this outputs a string:
>---------^ loose the '$';
>best regards
>Piotr N
I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

>

Heres the final code:

>

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);

>

Thanks again
Marco

>

Maybe i should open a new post for this one, but here it goes:

>

I'm stock! When i want to reference that variable in a echo statment,
it does't work. Any suggestions?
Thanks

>

<li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
$category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
alt="" /></a></li>

>
:)
It should look like this. Mark the { and }
echo ${$item[$i]};
>
As a side note, is this really best way to access needed data this way ?
Cant you keep original values in the array instead of the variable names ?
>
best regards
Piotr N

I've tried it, It doesn't work. When i look at the source code, i see
empty an empty string:
<img src="images/" alt="" />

Here's what im trying to do:
-From a list, the user selects the category of discography (either
original, compilation, tributes, other)
-Each type of discography is associated with an array that contains
the name of the cd covers.
-Then i show a thumbnail (using a loop) of all the cd covers.

my arrays look like this (one for each category of discography)
$thumbs_cat_1 = array('moonligh t.jpg'', shadow.jpg', 'luna.jpg');
$thumbs_cat_2 = array(...);
$thumbs_cat_3 = array(...);
$thumbs_cat_4 = array(...);

Then i create the thumbs like this:
for($i=0; ...){
....<img src="images/discography/thumbs/<?php echo $thumbs_cat_1[$i]; ?

>" alt="" />

}

All of this works perfectly for the first array.


That's why, i think, i need a variable that contains the selection
from the user (the category of discography) so i can select values
from the correct array.
I do it like this:

$cat = $_GET['cat']; //output: 1
$sel_array = 'thumbs_cat_' . $cat;//create the string: thumbs_cat_1




Then i create the thumbs like this:
for($i=0; ...){
....<img src="images/discography/thumbs/<?php echo ${$sel_array[$i]}; ?

>" alt="" />

}
.... and so on

You think my code makes sense? Maybe i'm doing it wrong.
The last part is were im stock...


Any ideas what's wrong?
Thanks again
Marco

[SM]

Re: Question about 'sizeof'

On May 8, 12:31 pm, Piotr <s...@poczta.on et.plwrote:

SM wrote:

On May 8, 11:50 am, SM <servandomont.. .@gmail.comwrot e:

On May 8, 11:42 am, Piotr <s...@poczta.on et.plwrote:

>

>>>$thumb = 1;
>>>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
>>>$thumbs_cat_ 1
>>>$item_tota l = sizeof($item);
>>>output: Nothing!
>>>How do i pass a variable to the 'sizeof' function?
>>You should use variable variable:
>>$item_total = sizeof($$item);
>>Mark double $$
>>This is true in any situation, not only with sizeof
>Forgot about one small detail:
>$item = 'thumbs_cat_' . $thumb; //this outputs a string:
>---------^ loose the '$';
>best regards
>Piotr N
I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

>

Heres the final code:

>

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);

>

Thanks again
Marco

>

Maybe i should open a new post for this one, but here it goes:

>

I'm stock! When i want to reference that variable in a echo statment,
it does't work. Any suggestions?
Thanks

>

<li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
$category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
alt="" /></a></li>

>
:)
It should look like this. Mark the { and }
echo ${$item[$i]};
>
As a side note, is this really best way to access needed data this way ?
Cant you keep original values in the array instead of the variable names ?
>
best regards
Piotr N

I've tried it, It doesn't work. When i look at the source code, i see
an empty string:
<img src="images/" alt="" />

Here's what im trying to do:
-From a list, the user selects the category of discography (either
original, compilation, tributes, other)
-Each type of discography is associated with an array that contains
the name of the cd covers.
-Then i show a thumbnail (using a loop) of all the cd covers.

my arrays look like this (one for each category of discography)
$thumbs_cat_1 = array('moonligh t.jpg'', shadow.jpg', 'luna.jpg');
$thumbs_cat_2 = array(...);
$thumbs_cat_3 = array(...);
$thumbs_cat_4 = array(...);

Then i create the thumbs like this:
for($i=0; ...){
....<img src="images/discography/thumbs/<?php echo $thumbs_cat_1[$i]; ?

>" alt="" />

}

All of this works perfectly for the first array.


That's why, i think, i need a variable that contains the selection
from the user (the category of discography) so i can select values
from the correct array.
I do it like this:

$cat = $_GET['cat']; //output: 1
$sel_array = 'thumbs_cat_' . $cat;//create the string: thumbs_cat_1




Then i create the thumbs like this:
for($i=0; ...){
....<img src="images/discography/thumbs/<?php echo ${$sel_array[$i]}; ?

>" alt="" />

}
.... and so on

You think my code makes sense? Maybe i'm doing it wrong.
The last part is were im stock...


Any ideas what's wrong?
Thanks again
Marco

[Jerry Stuckle]

Re: Question about 'sizeof'

SM wrote:

On May 8, 12:31 pm, Piotr <s...@poczta.on et.plwrote:

>SM wrote:

>>On May 8, 11:50 am, SM <servandomont.. .@gmail.comwrot e:
>>>On May 8, 11:42 am, Piotr <s...@poczta.on et.plwrote:
>>>>>>$thumb = 1;
>>>>>>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
>>>>>>$thumbs_c at_1
>>>>>>$item_tot al = sizeof($item);
>>>>>>output: Nothing!
>>>>>>How do i pass a variable to the 'sizeof' function?
>>>>>You should use variable variable:
>>>>>$item_tota l = sizeof($$item);
>>>>>Mark double $$
>>>>>This is true in any situation, not only with sizeof
>>>>Forgot about one small detail:
>>>>$item = 'thumbs_cat_' . $thumb; //this outputs a string:
>>>>---------^ loose the '$';
>>>>best regards
>>>>Piotr N
>>>I don't need the length of the string , just the actual variable. But
>>>i did like the fact that sizeof is an alias of count. So i will use
>>>count instead.
>>>I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!
>>>Heres the final code:
>>>$thumb = 1;
>>>$item = 'thumbs_cat_' . $thumb;
>>>$item_tota l = count($$item);
>>>Thanks again
>>>Marco
>>Maybe i should open a new post for this one, but here it goes:
>>I'm stock! When i want to reference that variable in a echo statment,
>>it does't work. Any suggestions?
>>Thanks
>><li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
>>$category_thi s; ?>"><img src="images/<?php echo($$item[$i]);?>"
>>alt="" /></a></li>

>:)
>It should look like this. Mark the { and }
>echo ${$item[$i]};
>>
>As a side note, is this really best way to access needed data this way ?
>Cant you keep original values in the array instead of the variable names ?
>>
>best regards
>Piotr N

>
I've tried it, It doesn't work. When i look at the source code, i see
an empty string:
<img src="images/" alt="" />
>
Here's what im trying to do:
-From a list, the user selects the category of discography (either
original, compilation, tributes, other)
-Each type of discography is associated with an array that contains
the name of the cd covers.
-Then i show a thumbnail (using a loop) of all the cd covers.
>
my arrays look like this (one for each category of discography)
$thumbs_cat_1 = array('moonligh t.jpg'', shadow.jpg', 'luna.jpg');
$thumbs_cat_2 = array(...);
$thumbs_cat_3 = array(...);
$thumbs_cat_4 = array(...);
>
Then i create the thumbs like this:
for($i=0; ...){
...<img src="images/discography/thumbs/<?php echo $thumbs_cat_1[$i]; ?

>" alt="" />

}
>
All of this works perfectly for the first array.
>
>
That's why, i think, i need a variable that contains the selection
from the user (the category of discography) so i can select values
from the correct array.
I do it like this:
>
$cat = $_GET['cat']; //output: 1
$sel_array = 'thumbs_cat_' . $cat;//create the string: thumbs_cat_1
>
>
>
>
Then i create the thumbs like this:
for($i=0; ...){
...<img src="images/discography/thumbs/<?php echo ${$sel_array[$i]}; ?

>" alt="" />

}
... and so on
>
You think my code makes sense? Maybe i'm doing it wrong.
The last part is were im stock...
>
>
Any ideas what's wrong?
Thanks again
Marco
>

Why go to all that trouble. Just use a two dimensional array, i.e.

$thumb_cats = array();
$thumb_cats[] = array('moonligh t.jpg'', shadow.jpg', 'luna.jpg');
$thumb_cats[] = array(...);
$thumb_cats[] = array(...);
$thumb_cats[] = array(...);
$thumb_cats[] = array(...);

<img src="images/discography/thumbs/<?php echo $thumb_cats[$sel][$i];?>"
alt="" />

Much cleaner.

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===

[SM]

Re: Question about 'sizeof'

On May 8, 4:27 pm, Jerry Stuckle <jstuck...@attg lobal.netwrote:

SM wrote:

On May 8, 12:31 pm, Piotr <s...@poczta.on et.plwrote:

SM wrote:
>On May 8, 11:50 am, SM <servandomont.. .@gmail.comwrot e:
>>On May 8, 11:42 am, Piotr <s...@poczta.on et.plwrote:
>>>>>$thumb = 1;
>>>>>$item = '$thumbs_cat_' . $thumb; //this outputs a string:
>>>>>$thumbs_ca t_1
>>>>>$item_tota l = sizeof($item);
>>>>>output: Nothing!
>>>>>How do i pass a variable to the 'sizeof' function?
>>>>You should use variable variable:
>>>>$item_tot al = sizeof($$item);
>>>>Mark double $$
>>>>This is true in any situation, not only with sizeof
>>>Forgot about one small detail:
>>>$item = 'thumbs_cat_' . $thumb; //this outputs a string:
>>>---------^ loose the '$';
>>>best regards
>>>Piotr N
>>I don't need the length of the string , just the actual variable. But
>>i did like the fact that sizeof is an alias of count. So i will use
>>count instead.
>>I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!
>>Heres the final code:
>>$thumb = 1;
>>$item = 'thumbs_cat_' . $thumb;
>>$item_total = count($$item);
>>Thanks again
>>Marco
>Maybe i should open a new post for this one, but here it goes:
>I'm stock! When i want to reference that variable in a echo statment,
>it does't work. Any suggestions?
>Thanks
><li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
>$category_this ; ?>"><img src="images/<?php echo($$item[$i]);?>"
>alt="" /></a></li>
:)
It should look like this. Mark the { and }
echo ${$item[$i]};

>

As a side note, is this really best way to access needed data this way ?
Cant you keep original values in the array instead of the variable names ?

>

best regards
Piotr N

>

I've tried it, It doesn't work. When i look at the source code, i see
an empty string:
<img src="images/" alt="" />

>

Here's what im trying to do:
-From a list, the user selects the category of discography (either
original, compilation, tributes, other)
-Each type of discography is associated with an array that contains
the name of the cd covers.
-Then i show a thumbnail (using a loop) of all the cd covers.

>

my arrays look like this (one for each category of discography)
$thumbs_cat_1 = array('moonligh t.jpg'', shadow.jpg', 'luna.jpg');
$thumbs_cat_2 = array(...);
$thumbs_cat_3 = array(...);
$thumbs_cat_4 = array(...);

>

Then i create the thumbs like this:
for($i=0; ...){
...<img src="images/discography/thumbs/<?php echo $thumbs_cat_1[$i]; ?

" alt="" />

}

>

All of this works perfectly for the first array.

>

That's why, i think, i need a variable that contains the selection
from the user (the category of discography) so i can select values
from the correct array.
I do it like this:

>

$cat = $_GET['cat']; //output: 1
$sel_array = 'thumbs_cat_' . $cat;//create the string: thumbs_cat_1

>

Then i create the thumbs like this:
for($i=0; ...){
...<img src="images/discography/thumbs/<?php echo ${$sel_array[$i]}; ?

" alt="" />

}
... and so on

>

You think my code makes sense? Maybe i'm doing it wrong.
The last part is were im stock...

>

Any ideas what's wrong?
Thanks again
Marco

>
Why go to all that trouble. Just use a two dimensional array, i.e.
>
$thumb_cats = array();
$thumb_cats[] = array('moonligh t.jpg'', shadow.jpg', 'luna.jpg');
$thumb_cats[] = array(...);
$thumb_cats[] = array(...);
$thumb_cats[] = array(...);
$thumb_cats[] = array(...);
>
<img src="images/discography/thumbs/<?php echo $thumb_cats[$sel][$i];?>"
alt="" />
>
Much cleaner.
>
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstuck...@attgl obal.net
=============== ===

Hey Jeery! Thanks . That help a lot! Much cleaner and nicer.

Marco