How do I debug this error?

[Hamimah]

I'm a beginner and this is my class assignment.
PHP reports the following error when tried to run the program,
Parse error: syntax error, unexpected T_IF in C:\xampp\htdocs \untitled.php on line 118.

How do I debug the error?

Here's a snippet of the code:

<p>&nbsp;</p>
<table width="800" border="1" align="center" bordercolor="#0 00000">

<tr bgcolor="#DD355 7">
<th colspan="2" class="style12" scope="col">And our comments for this conversion are as follow: </th>
</tr>
<tr>
<td width="50%"><sp an class="style27" >Great than or equal <?= $greaterthanore qual ?> </span></td>
<td width="50%">
<?=
LINE 118 --> if ($conversion >= $greaterthanore qual)
{
echo "<font color=#FF0000>$ comment1</font>";
}
else
{
echo "$comment1" ;
}
?>

</td>
</tr>
<tr>
<td><span class="style27" >Between <?= $between1 ?> to <?= $betweeen2 ?> </span></td>
<td>
<?=
if(($conversion >= $between1) and ($converted <= $between2))
{
echo "<font color=#FF0000>$ comment2</font>";
}
else
{
echo "$comment2" ;
}
?>

</td>
</tr>
<tr>
<td><span class="style27" >Less than or equal <?= $lessthanorequa l ?></span></td>
<td>
<?=
if($conversion <= $lessthanorequa l)
{
echo "<font color=#FF0000>$ comment3</font>";
}
else
{
echo "$comment3" ;
}
?>

</td>
</tr>
</table>

[Markus]

When posting please use code tags.
Revise your code and do so.

Also, it would be helpful to know what line 118 is.

The error is that you do this:
[php]
<?=
if( ...
[/php]
You cant use that short tag in that situation: <?= is used to echo a variable - nothing else.

[php]
<?= $variable?> // works
<?= if($foo == $bar) ... ?> // wont work.
[/php]