how to display an array variable

[webandwe]

Hi,

In my script the {$a[0]}"; does not want to assing to $p1 at the $p1="{$a[0]}";
line.


[PHP]
$result = mysql_query("SE LECT * FROM hole ORDER BY a5");

$i = 0;
$a = array();
while($row = mysql_fetch_arr ay($result))
{
$a[$i] = $row['a5'];
++$i;
}

mysql_close($co n);

echo "{$a[0]} {$a[1]} {$a[2]} {$a[8]}";

/////////// hole 1 ////////////
$p1="{$a[0]}"; //// ************ HELP******
if ($p1=="on") /////Show not taken
$p1="on"; /////show taken
else
$p1="off";
[/PHP]

[webandwe]

I thin I got the problem...Just checking

[PHP]
$p1="{$a[0]}"; ////Check hole
if ($p1=="{$a[0]}") /////Show not taken
$p1="15"; /////show taken
else
$p1="off";
[/PHP]

[Markus]

I thin I got the problem...Just checking

[PHP]
$p1="{$a[0]}"; ////Check hole
if ($p1=="{$a[0]}") /////Show not taken
$p1="15"; /////show taken
else
$p1="off";
[/PHP]

You dont always have to use quotes and curly brackets.
[php]
$p1 = $a[0];
if($p1 == $a[0])
$p1 = "15";
else
$p1 = "off";
[/php]

[ronverdonk]

Variable not working can in no way be considered a meaningful title. Since when does a variable 'work'??

Please remember to provide a meaningful Title for any threads started (see the FAQ entry Use a Good Thread Title).

This helps to ensure that other members, and also the general public, will have a better chance of finding answers to any similar questions.

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