dont know how to get rid of syntax error, unexpected T_VARIABLE

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  • ashraf02
    New Member
    • Feb 2008
    • 53
    #1

    dont know how to get rid of syntax error, unexpected T_VARIABLE

    i have check the code thoroughly to find the error i am still getting the following error: Parse error: syntax error, unexpected T_VARIABLE in C:\wamp\www\Cat alogue.php on line 23
    [php]
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dt d">
    <?php
    $conn = mysql_connect(" localhost","roo t","")
    or die (mysql_error()) ;
    mysql_select_db ("Shop_Test",$c onn) or die (mysql_error()) ;

    $display_block = "<h1>Categories </h1>
    <p>Select Category</p>";

    $get_cat = "SELECT Cat_ID, cat_title, cat_description FROM Store_Categorie s ORDER BY cat_title";
    $get_cat_result = mysql_query ($get_cat) or die (mysql_error()) ;

    if (mysql_num_rows ($get_cat_resul t) < 1) {
    $display_block = "<p><em>I'm sorry nothing to browse.</em></p>";
    } else {

    while ($cat = mysql_fetch_arr ay($get_cat_res ult)) {
    $Cat_ID = $cat[Cat_ID];
    $cat_title = strtoupper (stripslashes($ cat[cat_title]));
    $cat_desc = stripslashes ($cat[cat_description]);

    $display_block .= "<p><a
    href=\ "$_SERVER['PHP_SELF']?Cat_ID=$Cat_ID \">$cat_titl e</a><br>$cat_desc </p>";

    if ($_GET[Cat_ID] == $Cat_ID) {
    $get_items = "SELECT Store_ID, Item_title, Item_Price FROM
    Store_Items WHERE Cat_ID = $Cat_ID
    ORDER BY Item_Title";
    $get_item_resul ts = mysql_query ($get_items) or die (mysql_error()) ;

    if (mysql_num_rows ($get_item_resu lts) < 1 {
    $display_block = "<p><em>Sor ry No Items</em></p>";
    } else {

    $display_block .= "<ul>";

    while ($items = mysql_fetch_arr ay ($get_items_res ults)) {
    $item_id = $items [Store_ID];
    $item_title = stripslashes ($items[Item_Title]);
    $item_price = $items[Item_Price];

    $display_block .= "<li><a href=\ "showitem.php?i tem_id=$item_id \ ">$item_tit le</a>
    /</strong> (\$$item_price) ";
    }

    $display_block .= "<ul>";
    }
    }
    }
    }
    ?>[/php]
    sorry bout the layout. i have specified the part which says has an error
    really appreciate the help.

    To make it more clear enclose any code within the proper code tags. - moderator
    Last edited by ronverdonk; Feb 25 '08, 11:05 PM. Reason: code within appropriate tags
    Tags: None
    • Markus
      Recognized Expert Expert
      • Jun 2007
      • 6092
      #2
      Change it to:
      [php]
      $display_block .= "<p><a
      href=\
      "" . $_SERVER['PHP_SELF'] . "?Cat_ID=$Cat_I D\">$cat_titl e</a><br>$cat_desc </p>";
      [/php]
      Welcome to theScripts.

      Please remember to post code using the code tags, if you want to keep posting here.

        Comment

        • ashraf02
          New Member
          • Feb 2008
          • 53
          #3
          i have check the code thoroughly to find the error i am still getting the following error: Parse error: syntax error, unexpected T_VARIABLE in C:\wamp\www\Cat alogue.php on line 23

          [PHP]<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dt d">
          <?php
          $conn = mysql_connect(" localhost","roo t","")
          or die (mysql_error()) ;
          mysql_select_db ("Shop_Test",$c onn) or die (mysql_error()) ;

          $display_block = "<h1>Categories </h1>
          <p>Select Category</p>";

          $get_cat = "SELECT Cat_ID, cat_title, cat_description FROM Store_Categorie s ORDER BY cat_title";
          $get_cat_result = mysql_query ($get_cat) or die (mysql_error()) ;

          if (mysql_num_rows ($get_cat_resul t) < 1) {
          $display_block = "<p><em>I'm sorry nothing to browse.</em></p>";
          } else {

          while ($cat = mysql_fetch_arr ay($get_cat_res ult)) {
          $Cat_ID = $cat[Cat_ID];
          $cat_title = strtoupper (stripslashes($ cat[cat_title]));
          $cat_desc = stripslashes ($cat[cat_description]);

          $display_block .= "<p><a
          href=\ "$_SERVER['PHP_SELF']?Cat_ID=$Cat_ID \">$cat_titl e</a><br>$cat_desc </p>";

          if ($_GET[Cat_ID] == $Cat_ID) {
          $get_items = "SELECT Store_ID, Item_title, Item_Price FROM
          Store_Items WHERE Cat_ID = $Cat_ID
          ORDER BY Item_Title";
          $get_item_resul ts = mysql_query ($get_items) or die (mysql_error()) ;

          if (mysql_num_rows ($get_item_resu lts) < 1 {
          $display_block = "<p><em>Sor ry No Items</em></p>";
          } else {

          $display_block .= "<ul>";

          while ($items = mysql_fetch_arr ay ($get_items_res ults)) {
          $item_id = $items [Store_ID];
          $item_title = stripslashes ($items[Item_Title]);
          $item_price = $items[Item_Price];

          $display_block .= "<li><a href=\ "showitem.php?i tem_id=$item_id \ ">$item_tit le</a>
          /</strong> (\$$item_price) ";
          }

          $display_block .= "<ul>";
          }
          }
          }
          }
          ?>[/PHP]

            Comment

            • ashraf02
              New Member
              • Feb 2008
              • 53
              #4
              Originally posted by markusn00b
              Change it to:
              [php]
              $display_block .= "<p><a
              href=\
              "" . $_SERVER['PHP_SELF'] . "?Cat_ID=$Cat_I D\">$cat_titl e</a><br>$cat_desc </p>";
              [/php]
              Welcome to theScripts.

              Please remember to post code using the code tags, if you want to keep posting here.
              Thanks alot mate i really appreciate it

                Comment

                • ronverdonk
                  Recognized Expert Specialist
                  • Jul 2006
                  • 4259
                  #5
                  One error is in 23
                  [php]$display_block .= "<p><a href=\"{$_SERVE R['PHP_SELF']}?Cat_ID=$Cat_I D\">$cat_titl e</a><br>$cat_desc </p>";[/php]
                  the other one is in stmt 31
                  [php]if (mysql_num_rows ($get_item_resu lts) < 1) {[/php]
                  another in stmt 41[php]$display_block .= "<li><a href=\"showitem .php?item_id=$i tem_id\">$item_ title</a>
                  /</strong> (\$$item_price) ";[/php]Ronald

                    Comment

                    • ashraf02
                      New Member
                      • Feb 2008
                      • 53
                      #6
                      Originally posted by ronverdonk
                      One error is in 23
                      [php]$display_block .= "<p><a href=\"{$_SERVE R['PHP_SELF']}?Cat_ID=$Cat_I D\">$cat_titl e</a><br>$cat_desc </p>";[/php]
                      the other one is in stmt 31
                      [php]if (mysql_num_rows ($get_item_resu lts) < 1) {[/php]
                      another in stmt 41[php]$display_block .= "<li><a href=\"showitem .php?item_id=$i tem_id\">$item_ title</a>
                      /</strong> (\$$item_price) ";[/php]Ronald
                      Thanks alot roger i was gonna post another error but u already pointed it out. really appreciate it.

                        Comment

                        • ashraf02
                          New Member
                          • Feb 2008
                          • 53
                          #7
                          Originally posted by ashraf02
                          Thanks alot roger i was gonna post another error but u already pointed it out. really appreciate it.
                          Ronver sorry !!!! not roger lol

                            Comment

                            • ronverdonk
                              Recognized Expert Specialist
                              • Jul 2006
                              • 4259
                              #8
                              It's okay. Glad to be of help. And see you again.

                              Ronald

                                Comment

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