pasing part of an URL to commandline php

[Heinz]

Hi All

I have an URL like this

http://system/web/htdocs/graphthis.php?csv=/tmp/data.cvs&dir=/web/htdocs/stress&monitor=aaa

I would like to call now the command line php like this:

php graphthis.php '?csv=/tmp/data.cvs&dir=/web/htdocs/stress&monitor= aaa'

The question is can php translate this parameter string into the $_GET[]
aray somehow, so I don't have to rewrite the script ?

Thanks in advance
Heinz

[Nikolai Chuvakhin]

Re: pasing part of an URL to commandline php

"Heinz" <lullundlall@ya hoo.com> wrote in message
news:<2ms3dsFpm p92U1@uni-berlin.de>...[color=blue]
>
> I have an URL like this
>
> http://system/web/htdocs/graphthis.p...ss&monitor=aaa
>
> I would like to call now the command line php like this:
>
> php graphthis.php '?csv=/tmp/data.cvs&dir=/web/htdocs/stress&monitor= aaa'
>
> The question is can php translate this parameter string into the $_GET[]
> aray somehow, so I don't have to rewrite the script ?[/color]

Most likely, you will have to add a few things to your script.
In the command-line mode, arguments are stored in the $argv
variable (also accessible via $_SERVER['argv']).

Note also that you can recognize the mode in which PHP is running
by calling the php_sapi_name() function.

Cheers,
NC