hide image if image does not exist

[developing]

hey,

im sorta new to php but it seems easy enough...what i wanna do is have php check mysql db to see if a field is empty (got that part covered).

if, the field is empty then hide an image on the page and move everything else up. If not, then resize the frame to the image's proprtions

thanks a lot

[pbmods]

Heya, developing.

I take it you are storing images in the DB?

Easier way to think about it is that you *don't* output the image unless the field is not empty. Browsers will also automatically determine the proper size of the image.

[developing]

Heya, developing.

I take it you are storing images in the DB?

Easier way to think about it is that you *don't* output the image unless the field is not empty. Browsers will also automatically determine the proper size of the image.

well no, im not a big fan of DBing the images, so the db only contains the link to the image rather than the image itself....the image is hosted on my server (same as the site)...

[code green]

well no, im not a big fan of DBing the images, so the db only contains the link to the image rather than the image itself

Excellent. I believe in this myself. Using BLOB fields swell the database unnecessarily.

if, the field is empty then hide an image on the page and move everything else up. If not, then resize the frame to the image's proprtions

Why not test the variable in php and create or don't create the image HTML depending whether the variable is empty
[PHP]if(!empty($row['picture']))
echo HTML to display picture[/PHP]

[pbmods]

Heya, developing.

Please do not double-post. Thanks!

[developing]

woops! my bad, couldnt find this one...

but thanks for your replies guys...i already had the if statement to check for image existance, including the html made life waay easier....pure genius