Pattern Matching When $haystack _may_ be an array

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  • jerrygarciuh
    #1

    Pattern Matching When $haystack _may_ be an array

    Hello,

    I am converting a large scale app from Perl TemplateToolkit and
    Class::DBI to PHP.

    TemplateToolkit has elegant ways of coping with variables that may be
    a scalar or may be an array. So my predecessor has a number of vars
    that are ambiguous in this way.

    My question to you is whether, given this ambiguity, there is a better
    way to do this in PHP than my current solution?

    // $a is sometimes an array
    $a = array('foo', 'bar', 'kermit ruffins');

    if (is_array($a)) {
    foreach($a as $b) {
    if (preg_match('/ruffin/', $b)) {
    echo 'ruffin found';
    }
    }
    } else {
    if (preg_match('/ruffin/', $a)) {
    echo 'ruffin found';
    }
    }

    Much obliged for any help!

    Peace,

    JG

    Tags: None
    • ZeldorBlat
      #2
      Re: Pattern Matching When $haystack _may_ be an array

      On Jun 8, 1:33 pm, jerrygarciuh <jerrygarc...@g mail.comwrote:
      Hello,
      >
      I am converting a large scale app from Perl TemplateToolkit and
      Class::DBI to PHP.
      >
      TemplateToolkit has elegant ways of coping with variables that may be
      a scalar or may be an array. So my predecessor has a number of vars
      that are ambiguous in this way.
      >
      My question to you is whether, given this ambiguity, there is a better
      way to do this in PHP than my current solution?
      >
      // $a is sometimes an array
      $a = array('foo', 'bar', 'kermit ruffins');
      >
      if (is_array($a)) {
      foreach($a as $b) {
      if (preg_match('/ruffin/', $b)) {
      echo 'ruffin found';
      }
      }
      } else {
      if (preg_match('/ruffin/', $a)) {
      echo 'ruffin found';
      }
      }
      >
      Much obliged for any help!
      >
      Peace,
      >
      JG
      Just make it an array if it isn't then handle it as an array
      everytime:

      // $a is sometimes an array
      $a = array('foo', 'bar', 'kermit ruffins');

      if(!is_array($a ))
      $a = array($a);

      foreach($a as $b) {
      if (preg_match('/ruffin/', $b)) {
      echo 'ruffin found';
      }
      }

        Comment

        • jerrygarciuh
          #3
          Re: Pattern Matching When $haystack _may_ be an array

          Well I could do that except that it would mean re-writing dozens more
          script than I currently have to. I was more looking to see if anyone
          had a more elegant solution than the one I posted.

          Thanks for the reply!

          JG



          On Jun 8, 3:39 pm, ZeldorBlat <zeldorb...@gma il.comwrote:
          On Jun 8, 1:33 pm, jerrygarciuh <jerrygarc...@g mail.comwrote:
          >
          >
          >
          Hello,
          >
          I am converting a large scale app from Perl TemplateToolkit and
          Class::DBI to PHP.
          >
          TemplateToolkit has elegant ways of coping with variables that may be
          a scalar or may be an array. So my predecessor has a number of vars
          that are ambiguous in this way.
          >
          My question to you is whether, given this ambiguity, there is a better
          way to do this in PHP than my current solution?
          >
          // $a is sometimes an array
          $a = array('foo', 'bar', 'kermit ruffins');
          >
          if (is_array($a)) {
          foreach($a as $b) {
          if (preg_match('/ruffin/', $b)) {
          echo 'ruffin found';
          }
          }
          } else {
          if (preg_match('/ruffin/', $a)) {
          echo 'ruffin found';
          }
          }
          >
          Much obliged for any help!
          >
          Peace,
          >
          JG
          >
          Just make it an array if it isn't then handle it as an array
          everytime:
          >
          // $a is sometimes an array
          $a = array('foo', 'bar', 'kermit ruffins');
          >
          if(!is_array($a ))
          $a = array($a);
          >
          foreach($a as $b) {
          if (preg_match('/ruffin/', $b)) {
          echo 'ruffin found';
          }
          >
          }

            Comment

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