Capturing substrings with preg_match_all()

[ngmr80]

Hi,

I'm experiencing a problem when trying to capture substrings with
preg_match_all( ) from strings like

"set('Hello','W orld')"

using the following Regular Expression (PERL syntax):

"/^set\((?:'([^']+)'(?(?!\)),))+ \)$/"

The resulting matches array looks like this:

Array
(
[0] =Array
(
[0] =set('Hello','W orld')
)

[1] =Array
(
[0] =World
)

)

I wonder why "Hello" is not in the matches array. Did I do something
wrong in my Regular Expression?

Thanks in advance.
Ingmar

[gosha bine]

Re: Capturing substrings with preg_match_all( )

On 05.06.2007 17:18 ngmr80 wrote:

Hi,
>
I'm experiencing a problem when trying to capture substrings with
preg_match_all( ) from strings like
>
"set('Hello','W orld')"
>
using the following Regular Expression (PERL syntax):
>
"/^set\((?:'([^']+)'(?(?!\)),))+ \)$/"
>
The resulting matches array looks like this:
>
Array
(
[0] =Array
(
[0] =set('Hello','W orld')
)
>
[1] =Array
(
[0] =World
)
>
)
>
I wonder why "Hello" is not in the matches array. Did I do something
wrong in my Regular Expression?
>
Thanks in advance.
Ingmar
>

Hi Ingmar

grouping is not automatic, to capture N strings you must have N groups
in your expression or use preg_match_all, for example:

$re1 = '/set\( (.*?) \)/x';
$re2 = "/' (?: \\\\. | [^'] )* ' /x";

preg_match($re1 , "set('Hello','W o\'rld')", $m);
preg_match_all( $re2, $m[1], $m);
print_r($m);




--
gosha bine

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