I have the following query I run to pull some data from the db. The
sql (when run on the db) returns 2 elements. However, if I var dump my
variable ($aidlook) then the first element in the array does not show
up.
$getaid = mysql_query("SE LECT a_uid FROM `answers` WHERE `qid` =
$qid", $db);
$aidlook = mysql_fetch_arr ay($getaid,MYSQ L_NUM);
Doing a var dump returns: array(1) { [0]= string(1) "4" }
I should be getting 2 elements (4 and 5).
I am totally baffled. code as follows:
*************** ******
if (!is_array($aid look)) $aidlook = array($aidlook) ; // Check for the
existence of the array in case of null returns
if (!in_array($use rid,$aidlook)) // Look for our element which in
this case is "5"
{
if ($qstatus === 1) // Do a status check
{
}
answer_box($qid ,$answ); // additional function being run
} else
{
echo "Your Text Here";
}
}
../JLK
sql (when run on the db) returns 2 elements. However, if I var dump my
variable ($aidlook) then the first element in the array does not show
up.
$getaid = mysql_query("SE LECT a_uid FROM `answers` WHERE `qid` =
$qid", $db);
$aidlook = mysql_fetch_arr ay($getaid,MYSQ L_NUM);
Doing a var dump returns: array(1) { [0]= string(1) "4" }
I should be getting 2 elements (4 and 5).
I am totally baffled. code as follows:
*************** ******
if (!is_array($aid look)) $aidlook = array($aidlook) ; // Check for the
existence of the array in case of null returns
if (!in_array($use rid,$aidlook)) // Look for our element which in
this case is "5"
{
if ($qstatus === 1) // Do a status check
{
}
answer_box($qid ,$answ); // additional function being run
} else
{
echo "Your Text Here";
}
}
../JLK
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