Assigning values to arrays

[Ched]

Hi,

I am performing a MySQL SELECT (which returns multiple rows) to
$result and then extracting the results with
mysql_fetch_arr ay($result).
I then want to build a number of arrays using the fields of each row.
Here is the relevant code:
<snip>
$result =
$i = 1;
while ($row = mysql_fetch_arr ay($result))
{
extract($row); /* break the row into its fields */
$array0[$i] = $row[0]; /* 1st Field of Row */
$array1[$i] = $row[1]; /* 2nd Field of Row */
$array2[$i] = $row[2]; /* 3rd Field of Row */
$i++;
}
</snip>

Should this work? I am getting unexpected results when I try this.

Thanks.

[Pedro Graca]

Re: Assigning values to arrays

Ched wrote:[color=blue]
> I am performing a MySQL SELECT (which returns multiple rows) to
> $result and then extracting the results with
> mysql_fetch_arr ay($result).
> I then want to build a number of arrays using the fields of each row.
> Here is the relevant code:
> <snip>
> $result =
> $i = 1;
> while ($row = mysql_fetch_arr ay($result))
> {
> extract($row); /* break the row into its fields */[/color]

Why??? You're not using the isolated variables ...
If $row is an array like
array('id'=>3, 'name'=>'pedro' , 'email'=>'hexki d@hotpop.com')

that extract() call will create
$id = 3;
$name = 'pedro';
$email = 'hexkid@hotpop. com';
[color=blue]
> $array0[$i] = $row[0]; /* 1st Field of Row */[/color]

You set $i to 1; arrays usually start at 0.
[color=blue]
> $array1[$i] = $row[1]; /* 2nd Field of Row */
> $array2[$i] = $row[2]; /* 3rd Field of Row */
> $i++;
> }
></snip>
>
> Should this work?[/color]

Yes.
[color=blue]
> I am getting unexpected results when I try this.[/color]

What did you expect?
What happens differently?

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