Form in 2 steps - Preserving button radio

[elia]

Hello. Yes, already ask but no answers for this little problem.
I've got a form and 3 steps or page for the same form. If we come back
to the first page, the states of button radio are lost.

First page (form1.php)
<?
$gender=$_POST['gender'];
if(isset($_POST['gender'])){
$statusm="";
$statusf="";
if($_POST['gender']=="M"){$statusm ="checked"}
else{$statusf=" checked"}
?>

<Form... action="form2.p hp">
....
<input name="gender" type="radio" id="male" value="M"<?php echo
$statusm
?>M
<input name="gender" type="radio" id="female" value="F"<?php echo
$statusf ?>>F
....
</Form>

Second page (form2.php)
<?
$Gender=$_POST['gender'];
?>

<Form... action="form1.p hp">
....
<input name="gender" type="hidden" id="gender" value="<? echo $gender ?

>" />

....
</Form>

But it doesn't work!!!

A solution could be with "session_start( )" and $_cookie but I don't
know how to do it!

If anybody could write me all I need on the two pages with a little
exemple?? (The same problem come with the checkox or choise with
dynamic menu!) Thanks, pascal

[Arjen]

Re: Form in 2 steps - Preserving button radio

elia schreef:

Hello. Yes, already ask but no answers for this little problem.
I've got a form and 3 steps or page for the same form. If we come back
to the first page, the states of button radio are lost.

A solution could be with "session_start( )" and $_cookie but I don't
know how to do it!

One way to do it.

foreach ($_POST as $key=>$val)
{
echo '<input type = "hidden" name="'.htmlent ities($key).'"
value="'.htmlen tities($val).'" />';
}

--
Arjen
http://www.hondenpage.com - Mijn site over honden

[elia]

Re: Form in 2 steps - Preserving button radio

Thanks but it's doesn't work for button radio... pascal

[Captain Paralytic]

Re: Form in 2 steps - Preserving button radio

On 22 Feb, 07:45, "elia" <jos...@pcl.chw rote:

Hello. Yes, already ask but no answers for this little problem.
I've got a form and 3 steps or page for the same form. If we come back
to the first page, the states of button radio are lost.
>
First page (form1.php)
<?
$gender=$_POST['gender'];
if(isset($_POST['gender'])){
$statusm="";
$statusf="";
if($_POST['gender']=="M"){$statusm ="checked"}
else{$statusf=" checked"}
?>
>
<Form... action="form2.p hp">
...
<input name="gender" type="radio" id="male" value="M"<?php echo
$statusm
?>M
<input name="gender" type="radio" id="female" value="F"<?php echo
$statusf ?>>F
...
</Form>
>
Second page (form2.php)
<?
$Gender=$_POST['gender'];
?>
>
<Form... action="form1.p hp">
...
<input name="gender" type="hidden" id="gender" value="<? echo $gender ?>" />
>
...
</Form>
>
But it doesn't work!!!
>
A solution could be with "session_start( )" and $_cookie but I don't
know how to do it!
>
If anybody could write me all I need on the two pages with a little
exemple?? (The same problem come with the checkox or choise with
dynamic menu!) Thanks, pascal

When re-writing the button code on form1 include CHECKED on the one
that should be selected

[Arjen]

Re: Form in 2 steps - Preserving button radio

elia schreef:

Thanks but it's doesn't work for button radio... pascal

offcourse it does.


on page 1
echo '<input type = "radio name="gender" value="female" />';
echo '<input type = "radio name="gender" value="male" />';

on page 2
foreach ($_POST as $key=>$val)
{
echo '<input type = "hidden" name="'.htmlent ities($key).'"
value="'.htmlen tities($val).'" />';
}


on page 3
// do this any way u like. This will give an error in safe mode.
$checked[$_POST['gender']]='checked="chec ked"';
echo '<input type = "radio" name="gender" value="female"
'.$checked['female'].'/>';
echo '<input type = "radio" name="gender" value="male"
'.$checked['male'].'/>';
echo 'Your gender is'.$_POST['gender'];

if it doen't work post the output of var_dump($_POST ); did you set your
form right ?

--
Arjen
http://www.hondenpage.com - Mijn site over honden

[Jerry Stuckle]

Re: Form in 2 steps - Preserving button radio

elia wrote:

Hello. Yes, already ask but no answers for this little problem.
I've got a form and 3 steps or page for the same form. If we come back
to the first page, the states of button radio are lost.
>
First page (form1.php)
<?
$gender=$_POST['gender'];
if(isset($_POST['gender'])){
$statusm="";
$statusf="";
if($_POST['gender']=="M"){$statusm ="checked"}
else{$statusf=" checked"}
?>
>
<Form... action="form2.p hp">
...
<input name="gender" type="radio" id="male" value="M"<?php echo
$statusm
?>M
<input name="gender" type="radio" id="female" value="F"<?php echo
$statusf ?>>F
...
</Form>
>
Second page (form2.php)
<?
$Gender=$_POST['gender'];
?>
>
<Form... action="form1.p hp">
...
<input name="gender" type="hidden" id="gender" value="<? echo $gender ?

>" />

...
</Form>
>
But it doesn't work!!!
>
A solution could be with "session_start( )" and $_cookie but I don't
know how to do it!
>
If anybody could write me all I need on the two pages with a little
exemple?? (The same problem come with the checkox or choise with
dynamic menu!) Thanks, pascal
>

Look at your source code. I think you'll find this comes out to

<input name="gender" type="radio" id="male" value="M"CHECKE DM

Note the lack of a space between "M" and CHECKED.

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===

[elia]

Re: Form in 2 steps - Preserving button radio

Extra!! All is ok, I had the same problem for the selected menu but is
ok now with the same code, thanks a lot for all!! Pascal