Arrays and references

[TMN]

Hi

I would like to append stuff to an array but doing it by reference -
this is not working - can anyone help ?

$anArray[]= "";

$ref = &$anArray[];

$ref = "a";
$ref = "b";
$ref = "c";

anArray now contains a,b and c

Thanks
Tim

[Rik]

Re: Arrays and references

On Thu, 15 Feb 2007 15:52:28 +0100, TMN <nash.rsa@gmail .comwrote:

I would like to append stuff to an array but doing it by reference -
this is not working - can anyone help ?
>
$anArray[]= "";
>
$ref = &$anArray[];
>
$ref = "a";
$ref = "b";
$ref = "c";
>
anArray now contains a,b and c

This cannot be done like that. $anArray[] is not 'the mystical place where
variables go to be added to an array'. It's a construct that appends
something as a last item to an array, and any reference to it will result
in the actual value added at that point, not a 'new' array value.

Just use $anArray[] = 'foo';, or possibly:

$mainArray = array('foo' =bar,'foz'= array());
$anArray = &$mainArray['foz'];
$anArray[] = 'foo';
$anArray[] = 'bar';

Or even the array_push()/array_unshift() functions.


What is the actual problem you're trying to solve here?
--
Rik Wasmus

[Toby A Inkster]

Re: Arrays and references

TMN wrote:

$anArray[]= "";
>
$ref = &$anArray[];
>
$ref = "a";
$ref = "b";
$ref = "c";

$anArray[]= "";
$ref = &$anArray[];
$ref[] = "a";
$ref[] = "b";
$ref[] = "c";

--
Toby A Inkster BSc (Hons) ARCS
Contact Me ~ http://tobyinkster.co.uk/contact
Geek of ~ HTML/SQL/Perl/PHP/Python*/Apache/Linux

* = I'm getting there!

[TMN]

Re: Arrays and references

On Feb 15, 6:40 pm, Toby A Inkster <usenet200...@t obyinkster.co.u k>
wrote:

TMN wrote:

$anArray[]= "";

>

$ref = &$anArray[];

>

$ref = "a";
$ref = "b";
$ref = "c";

>
$anArray[]= "";
$ref = &$anArray[];
$ref[] = "a";
$ref[] = "b";
$ref[] = "c";
>
--
Toby A Inkster BSc (Hons) ARCS
Contact Me ~http://tobyinkster.co.uk/contact
Geek of ~ HTML/SQL/Perl/PHP/Python*/Apache/Linux
>
* = I'm getting there!

What I am trying to do is get a reference to an array so I can add
elements to arrays via the ref.

tim

[Kimmo Laine]

Re: Arrays and references

"TMN" <nash.rsa@gmail .comwrote in message
news:1171628462 .501867.158990@ t69g2000cwt.goo glegroups.com.. .

On Feb 15, 6:40 pm, Toby A Inkster <usenet200...@t obyinkster.co.u k>
wrote:

>TMN wrote:

$anArray[]= "";

>>

$ref = &$anArray[];

>>

$ref = "a";
$ref = "b";
$ref = "c";

>>
>$anArray[]= "";
>$ref = &$anArray[];
>$ref[] = "a";
>$ref[] = "b";
>$ref[] = "c";
>>
>--
>Toby A Inkster BSc (Hons) ARCS
>Contact Me ~http://tobyinkster.co.uk/contact
>Geek of ~ HTML/SQL/Perl/PHP/Python*/Apache/Linux
>>
>* = I'm getting there!

>
What I am trying to do is get a reference to an array so I can add
elements to arrays via the ref.

You have to use the [] construct, there's no way around it. Yo can create a
reference to the array, but you still need the [].

--
"Ohjelmoija on organismi joka muuttaa kofeiinia koodiksi" - lpk
http://outolempi.net/ahdistus/ - Satunnaisesti päivittyvä nettisarjis
spam@outolempi. net | rot13(xvzzb@bhg byrzcv.arg)

[TMN]

Re: Arrays and references

$anArray[]= "";
$ref = &$anArray[];
$ref[] = "a";
$ref[] = "b";
$ref[] = "c";

But with this I am ending up with an array inside $anArray not just
a,b and c ?

Thanks
Tim

[Kimmo Laine]

Re: Arrays and references

"TMN" <nash.rsa@gmail .comwrote in message
news:1171633666 .200970.46200@t 69g2000cwt.goog legroups.com...

$anArray[]= "";
$ref = &$anArray[];
$ref[] = "a";
$ref[] = "b";
$ref[] = "c";
>
But with this I am ending up with an array inside $anArray not just
a,b and c ?

$anArray = array();
$ref = &$anArray; // No [] here

$ref[] = "a";
$ref[] = "b";
$ref[] = "c";

--
"Ohjelmoija on organismi joka muuttaa kofeiinia koodiksi" - lpk
http://outolempi.net/ahdistus/ - Satunnaisesti päivittyvä nettisarjis
spam@outolempi. net | rot13(xvzzb@bhg byrzcv.arg)

[TMN]

Re: Arrays and references

On Feb 16, 3:51 pm, "Kimmo Laine" <s...@outolempi .netwrote:

"TMN" <nash....@gmail .comwrote in message
>
news:1171633666 .200970.46200@t 69g2000cwt.goog legroups.com...
>

$anArray[]= "";
$ref = &$anArray[];
$ref[] = "a";
$ref[] = "b";
$ref[] = "c";

>

But with this I am ending up with an array inside $anArray not just
a,b and c ?

>
$anArray = array();
$ref = &$anArray; // No [] here
>
$ref[] = "a";
$ref[] = "b";
$ref[] = "c";
>
--
"Ohjelmoija on organismi joka muuttaa kofeiinia koodiksi" - lpkhttp://outolempi.net/ahdistus/- Satunnaisesti päivittyvä nettisarjis
s...@outolempi. net | rot13(x...@bhgb yrzcv.arg)

Thank you thank you !!!!!!!
Tim