Array doesn't pass.

[T. Wintershoven]

Hello all,

I have a form with some checkboxes.
The names of these checkboxes come from an array.
When i click the submit button the resultcode doesn't recognize the names
when i want to check wether or not some checkboxes are ticked.

Assume that i tick checkboxes 100, 150 and 200

Below is some code i've used.(between the ****** lines)
*************** *************** *************** ***
if (!isSet($_POST['submit']))
{
ShowForm();
}
else
{
HandleForm();
}

function ShowForm()
{
//normally, these values come out of a database
$question=array ();
$question[0]="100";
$question[1]="125";
$question[2]="150";
$question[3]="175";
$question[4]="200";

echo"<form name='form1' method='post' action='".$_SER VER['PHP_SELF']."'>";

for($i=0; $i<5; $i++)
{
echo "<input type='checkbox' name=$question[$i]This is the
question with ID ". $question[$i]."<br/>";
}
echo "<BR><input type='submit' name='submit' value='Show choice'>";
echo"</form>";
}

function HandleForm()
{
for($i=0; $i<5; $i++)
{
if(isset($_POST[$question[$i]]))
{
echo "Question ".$_POST[$question[$i]]." was
ticked.<br/>";
}
}
}
*************** *************** *************** ***********
Function HandleForm doesn't recognize $_POST[question[$i]]

Can anyone help me solve this problem.

T.i.a.
Regards
Tino Wintershoven
The Netherlands

[Daz]

Re: Array doesn't pass.

T. Wintershoven wrote:

Can anyone help me solve this problem.

Perhaps you might want consider placing this into the HandleForm
function:
echo "<pre>",print_r ($_POST),"</pre>;

This will allow you to see exactly what has been passed back in the
$_POST variable, and what format it's in.

[Daz]

Re: Array doesn't pass.


T. Wintershoven wrote:

Can anyone help me solve this problem.

Another solution might be this:

if (!isSet($_POST['submit']))
{
ShowForm();
}
else
{
HandleForm();
}
// Declare the question array in the global scope.
$question=array ();
$question[0]="100";
$question[1]="125";
$question[2]="150";
$question[3]="175";
$question[4]="200";

function ShowForm() {
global $question;

echo"<form name='form1' method='post'
action='".$_SER VER['PHP_SELF']."'>";

for($i=0; $i<5; $i++) {
// This time we are making a unique name for the checkbox
// (i.e question_1, question_2 etc...).
echo "<input type='checkbox' name=$question_ $iThis is the "
."question with ID ". $question[$i]."<br/>";
}
echo "<BR><input type='submit' name='submit' value='Show
choice'>";
echo"</form>";

}

function HandleForm() {
global $question;

for($i=0; $i<5; $i++) {
// Create the name for the checkbox we can't to check.
$question_name = "question_" .$i;
// This may not be a legit method, but by adding '2' dollar
signs to the beginning
// of the variable, the variable name is correctly parsed as it
should be.
if(isset($_POST[$$question_name])) {
echo "Question ".$_POST[$question[$i]]." was "
."ticked.<br/>";
}
}
}

I haven't tested it, but I hope you get the idea.

[Pedro Graca]

Re: Array doesn't pass.

Daz wrote:

echo "<pre>",print_r ($_POST),"</pre>;

echo "<pre>"; print_r($_POST) ; echo "</pre>";

Will not print the result value of the print_r() call, which is 1. Or
you could do

echo "<pre>",print_r ($_POST, true),"</pre>;

which will make print_r() return a formatted string with the contents
of $_POST instead of the 1 above.
print_r($someth ing, true) *does*not* output anything; the output is
done by the echo.

[Daz]

Re: Array doesn't pass.


Pedro Graca wrote:

Daz wrote:

echo "<pre>",print_r ($_POST),"</pre>;

>
echo "<pre>"; print_r($_POST) ; echo "</pre>";
>
Will not print the result value of the print_r() call, which is 1. Or
you could do
>
echo "<pre>",print_r ($_POST, true),"</pre>;
>
which will make print_r() return a formatted string with the contents
of $_POST instead of the 1 above.
print_r($someth ing, true) *does*not* output anything; the output is
done by the echo.

Hi pedro.

I'm sorry, but you are incorrect in one of your statements.
echo "<pre>",print_r ($_POST),"</pre>; will work just fine, I recommend
you try it as I use it all the time. Please note, my use of commas as
opposed to periods.

Best wishes.

Daz.

[Daz]

Re: Array doesn't pass.


Daz wrote:

Pedro Graca wrote:

Daz wrote:

echo "<pre>",print_r ($_POST),"</pre>;

echo "<pre>"; print_r($_POST) ; echo "</pre>";

Will not print the result value of the print_r() call, which is 1. Or
you could do

echo "<pre>",print_r ($_POST, true),"</pre>;

which will make print_r() return a formatted string with the contents
of $_POST instead of the 1 above.
print_r($someth ing, true) *does*not* output anything; the output is
done by the echo.

>
Hi pedro.
>
I'm sorry, but you are incorrect in one of your statements.
echo "<pre>",print_r ($_POST),"</pre>; will work just fine, I recommend
you try it as I use it all the time. Please note, my use of commas as
opposed to periods.
>
Best wishes.
>
Daz.

Sorry Pedro. I misread your post.

[Daz]

Re: Array doesn't pass.


Daz wrote:

T. Wintershoven wrote:

Can anyone help me solve this problem.

>
Perhaps you might want consider placing this into the HandleForm
function:
echo "<pre>",print_r ($_POST),"</pre>;
>
This will allow you to see exactly what has been passed back in the
$_POST variable, and what format it's in.

Please note I accidentally missed a double quote from the end of my
eacho statement. It should have read:

echo "<pre>",print_r ($_POST),"</pre>";

[Pedro Graca]

Re: Array doesn't pass.

Daz wrote:

echo "<pre>",print_r ($_POST),"</pre>; will work just fine

Yes, except that it will print an extra "1" (without the quotes).
The extra "1" is the return value of the print_r() call.

[Kimmo Laine]

Re: Array doesn't pass.

"T. Wintershoven" <twintershoven@ casema.nlwrote in message
news:s7udnRhqqd 0iMNHYRVnygQ@ca sema.nl...

Hello all,
>
I have a form with some checkboxes.
The names of these checkboxes come from an array.
When i click the submit button the resultcode doesn't recognize the names
when i want to check wether or not some checkboxes are ticked.
>
Assume that i tick checkboxes 100, 150 and 200
>
Below is some code i've used.(between the ****** lines)
*************** *************** *************** ***
if (!isSet($_POST['submit']))
{
ShowForm();
}
else
{
HandleForm();
}
>
function ShowForm()
{
//normally, these values come out of a database
$question=array ();
$question[0]="100";
$question[1]="125";
$question[2]="150";
$question[3]="175";
$question[4]="200";
>
echo"<form name='form1' method='post' action='".$_SER VER['PHP_SELF']."'>";
>
for($i=0; $i<5; $i++)
{
echo "<input type='checkbox' name=$question[$i]This is the

^^^^^^^^^^^^^
"$question[$i]" will print literally 'array[1]', not '100' like you
intended. If you want it to work, you gotta denote the array reference with
curly braces:

echo "<input type='checkbox' name='{$questio n[$i]}'This is the...."

Now you'll get '100', '125', etc, which gets us to the second problem:
having plain numbers as field names. Well, perhaps it's not a problem, but
it is something I wouldn't do. The only explanation I can offer for this is
"just because". I'd throw in some alphabets, just in case, name them 'q100',
'q125', etc...

question with ID ". $question[$i]."<br/>";
}
echo "<BR><input type='submit' name='submit' value='Show choice'>";
echo"</form>";
}
>
function HandleForm()
{
for($i=0; $i<5; $i++)
{
if(isset($_POST[$question[$i]]))

Here you reference correctly the field names 100, 125, etc.. but the reason
they are not found is the fields are actually named array[0]..., like I
explained earlier...


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