$("var" . $i) ?

[Jan Rasche]

Hi All,

Please some help about building a var name:

for($i=1;$i<5;$ i++) {
$query=$("var" . $i);
//$var1
//$var2
//$var3
//$var4
}

Thank you in advance!

Jan

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too young to have logged on yet. Here's what I worry about. I worry that
10 or 15 years from now, she will come to me and say 'Daddy, where were
you when they took freedom of the press away from the Internet?'
--
--Mike Godwin, Electronic Frontier Foundation <http://www.eff.org/br/>

[Henk Burgstra]

Re: $(&quot;var&quo t; . $i) ?

On Sat, 17 Apr 2004 20:30:28 +0200, Jan Rasche wrote:
[color=blue]
> Hi All,
>
> Please some help about building a var name:
>
> for($i=1;$i<5;$ i++) {
> $query=$("var" . $i);
> //$var1
> //$var2
> //$var3
> //$var4
> }
>[/color]
for ($i=1; $i<5; $i++) {
$a = "var$i";
$query=$$a;
}

Regards,
Henk Burgstra

[Jan Rasche]

Re: $(&quot;var&quo t; . $i) ?

Henk Burgstra wrote:[color=blue][color=green]
>>[/color]
>
> for ($i=1; $i<5; $i++) {
> $a = "var$i";
> $query=$$a;
> }[/color]

Hi Henk,

Thats it - thank you!

Regards, Jan




'They understood that the future would be built on the free exchange of
information; decentralisatio n; enriching the world's knowledge of
computing by increasing accessibility.'
--Steven Levy, Hackers. Heroes of the Computer Revolution.

[Jeppe Uhd]

Re: $(&quot;var&quo t; . $i) ?

Jan Rasche wrote:[color=blue]
> Hi All,
>
> Please some help about building a var name:
>
> for($i=1;$i<5;$ i++) {
> $query=$("var" . $i);
> //$var1
> //$var2
> //$var3
> //$var4
> }
>[/color]

Either the solution provided by Henk or this:

for($i=1;$i<5;$ i++) {
$query=${"var" . $i};
}

--
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