in_array() problem

[Craig Keightley]

I am trying to compare values of a string entered into an array but having
no results, is this possible to achieve:


<?php
$ids = $row_rsProduct['itemList']; // A comma separated list of values
(1,2,3,4,5,6,7, 8)
$list = array($ids);
if (in_array(1, $list)) {
echo "In List";
}
?>

I have no results but i cannot see why

Any help would be grateful

Craig

[Jon Kraft]

Re: in_array() problem

"Craig Keightley" <craig@sitedesi gn.net> wrote:
[color=blue]
> I am trying to compare values of a string entered into an array but
> having no results, is this possible to achieve:
>
>
> <?php
> $ids = $row_rsProduct['itemList']; // A comma separated list of
> values
> (1,2,3,4,5,6,7, 8)
> $list = array($ids);[/color]

Try this instead:
$list = explode(",", $ids);

HTH;
JOn
[color=blue]
> if (in_array(1, $list)) {
> echo "In List";
> }
> ?>
>
> I have no results but i cannot see why[/color]

[Craig Keightley]

Re: in_array() problem

No, that doesn't work either.
Any other suggestions?

Thanks Any way

Craig
"Jon Kraft" <jon@jonux.co.u k> wrote in message
news:Xns94BCA61 2EFDA6jonjonuxc ouk@130.133.1.4 ...[color=blue]
> "Craig Keightley" <craig@sitedesi gn.net> wrote:
>[color=green]
> > I am trying to compare values of a string entered into an array but
> > having no results, is this possible to achieve:
> >
> >
> > <?php
> > $ids = $row_rsProduct['itemList']; // A comma separated list of
> > values
> > (1,2,3,4,5,6,7, 8)
> > $list = array($ids);[/color]
>
> Try this instead:
> $list = explode(",", $ids);
>
> HTH;
> JOn
>[color=green]
> > if (in_array(1, $list)) {
> > echo "In List";
> > }
> > ?>
> >
> > I have no results but i cannot see why[/color][/color]

[Jon Kraft]

Re: in_array() problem

"Craig Keightley" <craig@sitedesi gn.net> wrote:
[color=blue]
> "Jon Kraft" <jon@jonux.co.u k> wrote:[color=green]
>> "Craig Keightley" <craig@sitedesi gn.net> wrote:
>>[color=darkred]
>> > I am trying to compare values of a string entered into an array but
>> > having no results, is this possible to achieve:
>> >
>> >
>> > <?php
>> > $ids = $row_rsProduct['itemList']; // A comma separated list of
>> > values
>> > (1,2,3,4,5,6,7, 8)
>> > $list = array($ids);[/color]
>>
>> Try this instead:
>> $list = explode(",", $ids);[/color]
>
> No, that doesn't work either.
> Any other suggestions?[/color]

Have you echoed $ids? Is it really a comma separated list? What is the
output?

JOn

[Craig Keightley]

Re: in_array() problem

I tried echoing the output and it works
Does it matter that the field being called out from the database is a in
text format?
The text field is a comma separated list e.g. column a = 1,3,2,5,6

"Jon Kraft" <jon@jonux.co.u k> wrote in message
news:Xns94BCA9D 229256jonjonuxc ouk@130.133.1.4 ...[color=blue]
> "Craig Keightley" <craig@sitedesi gn.net> wrote:
>[color=green]
> > "Jon Kraft" <jon@jonux.co.u k> wrote:[color=darkred]
> >> "Craig Keightley" <craig@sitedesi gn.net> wrote:
> >>
> >> > I am trying to compare values of a string entered into an array but
> >> > having no results, is this possible to achieve:
> >> >
> >> >
> >> > <?php
> >> > $ids = $row_rsProduct['itemList']; // A comma separated list of
> >> > values
> >> > (1,2,3,4,5,6,7, 8)
> >> > $list = array($ids);
> >>
> >> Try this instead:
> >> $list = explode(",", $ids);[/color]
> >
> > No, that doesn't work either.
> > Any other suggestions?[/color]
>
> Have you echoed $ids? Is it really a comma separated list? What is the
> output?
>
> JOn[/color]

[Markus Ernst]

Re: in_array() problem

"Jon Kraft" <jon@jonux.co.u k> schrieb im Newsbeitrag
news:Xns94BCA9D 229256jonjonuxc ouk@130.133.1.4 ...[color=blue]
> "Craig Keightley" <craig@sitedesi gn.net> wrote:
>[color=green]
> > "Jon Kraft" <jon@jonux.co.u k> wrote:[color=darkred]
> >> "Craig Keightley" <craig@sitedesi gn.net> wrote:
> >>
> >> > I am trying to compare values of a string entered into an array but
> >> > having no results, is this possible to achieve:
> >> >
> >> >
> >> > <?php
> >> > $ids = $row_rsProduct['itemList']; // A comma separated list of
> >> > values
> >> > (1,2,3,4,5,6,7, 8)
> >> > $list = array($ids);
> >>
> >> Try this instead:
> >> $list = explode(",", $ids);[/color]
> >
> > No, that doesn't work either.
> > Any other suggestions?[/color]
>
> Have you echoed $ids? Is it really a comma separated list? What is the
> output?[/color]

Maybe it is a string/integer problem? If the list comes out of a database it
would likely be a string, so it is to be translated as:

$list = array("1,2,3,4, 5,6,7,8");

which produces an index array with one value ([0] => "1,2,3,4,5,6,7, 8").

With the explode solution you produce an array such as: ([0] => "1", [1] =>
"2" ....). This should work if 1="1" is true; I think that should be the
case in PHP, but to be sure you could convert the needle argument of
in_array to a string:

$list = explode(",", $ids);

if (in_array("1", $list)) {
echo "In List";
}

or:
if (in_array(strva l(1), $list)) {
echo "In List";
}

HTH
Markus

[Craig Keightley]

Re: in_array() problem

Excellent
The use of strval has worked a treat

many thanks

Craig

"Markus Ernst" <derernst@NO#SP #AMgmx.ch> wrote in message
news:406a7fab$0 $4097$afc38c87@ news.easynet.ch ...[color=blue]
> "Jon Kraft" <jon@jonux.co.u k> schrieb im Newsbeitrag
> news:Xns94BCA9D 229256jonjonuxc ouk@130.133.1.4 ...[color=green]
> > "Craig Keightley" <craig@sitedesi gn.net> wrote:
> >[color=darkred]
> > > "Jon Kraft" <jon@jonux.co.u k> wrote:
> > >> "Craig Keightley" <craig@sitedesi gn.net> wrote:
> > >>
> > >> > I am trying to compare values of a string entered into an array but
> > >> > having no results, is this possible to achieve:
> > >> >
> > >> >
> > >> > <?php
> > >> > $ids = $row_rsProduct['itemList']; // A comma separated list[/color][/color][/color]
of[color=blue][color=green][color=darkred]
> > >> > values
> > >> > (1,2,3,4,5,6,7, 8)
> > >> > $list = array($ids);
> > >>
> > >> Try this instead:
> > >> $list = explode(",", $ids);
> > >
> > > No, that doesn't work either.
> > > Any other suggestions?[/color]
> >
> > Have you echoed $ids? Is it really a comma separated list? What is the
> > output?[/color]
>
> Maybe it is a string/integer problem? If the list comes out of a database[/color]
it[color=blue]
> would likely be a string, so it is to be translated as:
>
> $list = array("1,2,3,4, 5,6,7,8");
>
> which produces an index array with one value ([0] => "1,2,3,4,5,6,7, 8").
>
> With the explode solution you produce an array such as: ([0] => "1", [1][/color]
=>[color=blue]
> "2" ....). This should work if 1="1" is true; I think that should be the
> case in PHP, but to be sure you could convert the needle argument of
> in_array to a string:
>
> $list = explode(",", $ids);
>
> if (in_array("1", $list)) {
> echo "In List";
> }
>
> or:
> if (in_array(strva l(1), $list)) {
> echo "In List";
> }
>
> HTH
> Markus
>
>[/color]