Carriage returns

[Dan Pearce]

I am formatting a plain text file into HTML and trying to find the
carriage returns with little success...

<?php
$s = file_get_conten ts('./test.txt')
$search = array ('\n\n');
$replace = array ('<p></p>');
echo preg_replace($s earch, $replace, $s);
?>

I have also tried \n, \r, \n\r etc... in place of \n\n but to no avail.


Can anyone help me with this? I know text files aren't an ideal format
and a database would be easier, but the site will be used by people
with no computer knowledge what so ever, and it is easier to show them
how to use notepad :¬)

Thanks in advance

Dan

[Andy Jeffries]

Re: Carriage returns

On Wed, 21 Jun 2006 08:15:50 -0700, Dan Pearce wrote:[color=blue]
> $search = array ('\n\n');
>
> I have also tried \n, \r, \n\r etc... in place of \n\n but to no avail.[/color]

Two things:

1) I'd try "\r\n\r\n", Windows users (which I'd imagine your
no-computer-knowledge people are) using notepad inserts \r\n for a
carriage return.

2) Use double quotes instead of single quotes. Try the following script
using PHP CLI:

<?php
print "Two blanks lines with double quotes:";
print "\n\n";
print "Two blanks lines with single quotes:";
print '\n\n';
?>

$ php test2.php
Two blanks lines with double quotes:

Two blanks lines with single quotes:\n\n

\n's aren't interpreted within single quotes, so it searches for the
literal string slash-n not a newline char.
[color=blue]
> Can anyone help me with this?[/color]

I hope the above helps. In future though, rather than guessing at line
endings using a hex editor may help ;-)

Cheers,


Andy


--
Andy Jeffries MBCS CITP ZCE | gPHPEdit Lead Developer
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