preg_replace question

[julianmlp@gmail.com]

I'm fairly new to regex code, and I'm trying to find a way to replace
any text after "///" (three slashes) and before a "\n" character.


I've tried with:

$filen = preg_replace("///./\n$", "", $filen);
The pattern would mean:
"string that has three "/" followed by any characters and which ends
with \n"


$filen = preg_replace("//{2}.\n$", "", $filen);
The pattern would mean:
"string that has one "/" followed two "/", then followed by any
character and which ends with \n"


What's wrong with these patterns?

regards - julian

[Rik]

Re: preg_replace question

julianmlp@gmail .com wrote:[color=blue]
> I'm fairly new to regex code, and I'm trying to find a way to replace
> any text after "///" (three slashes) and before a "\n" character.
>
>
> I've tried with:
>
> $filen = preg_replace("///./\n$", "", $filen);
> The pattern would mean:
> "string that has three "/" followed by any characters and which ends
> with \n"
>
>
> $filen = preg_replace("//{2}.\n$", "", $filen);
> The pattern would mean:
> "string that has one "/" followed two "/", then followed by any
> character and which ends with \n"
>
>
> What's wrong with these patterns?[/color]

1. The first character (in this case '/') is considered the pattern
delimiter, which never closes here...
2. . should match zero or more characters I presume?
3. $ will match only the end on the string without any modifiers, not every
newline.

Possibilities:
$filen = preg_replace("|/{3}.*?$|m", "", $filen);
$filen = preg_replace("|/{3}.*?\n|", "", $filen);

Grtz,
--
Rik Wasmus

[lorento]

Re: preg_replace question

Try this :

<?php
$str = "Hello World ///World Hello\n";
$str .= "Helllooooo o ///allohhhaaaa\n";

echo "<b>Before : </b><br>$str<br>< br>";

echo "<b>After:</b><br>";
echo preg_replace ("/\/\/\/(.*)/", "", $str);

?>

regards,

Lorento
--

http://www.mastervb.net

http://www.padbuilder.com

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[julian_m]

Re: preg_replace question


lorento wrote:[color=blue]
> Try this :
>
> <?php
> $str = "Hello World ///World Hello\n";
> $str .= "Helllooooo o ///allohhhaaaa\n";
>
> echo "<b>Before : </b><br>$str<br>< br>";
>
> echo "<b>After:</b><br>";
> echo preg_replace ("/\/\/\/(.*)/", "", $str);
>
> ?>[/color]


Great. Just a small detail which I cant't achieve even though both you
and Rik gave me excelent advice:

Your code output is:

After:
Hello World Hellloooooo

whereas I would like to get

Hello World
Hellloooooo

So I thought it would be esay to solve just changing[color=blue][color=green][color=darkred]
>>>echo preg_replace ("/\/\/\/(.*)/", "", $str);[/color][/color][/color]
to[color=blue][color=green][color=darkred]
>>>echo preg_replace ("/\/\/\/(.*)/", "/n", $str);[/color][/color][/color]

Note the "/n"
But it actually doesn't work at all.
What's wrong? Why "/n" doesn't do anything?

regards - julian

[Rik]

Re: preg_replace question

Rik wrote:[color=blue]
> Possibilities:
> $filen = preg_replace("|/{3}.*?$|m", "", $filen);
> $filen = preg_replace("|/{3}.*?\n|", "", $filen);[/color]

julian_m wrote:[color=blue]
> Your code output is:
>
> After:
> Hello World Hellloooooo
>
> whereas I would like to get
>
> Hello World
> Hellloooooo[/color]


$filen = preg_replace("|/{3}.*?$|m", "\n", $filen);
$filen = preg_replace("|/{3}.*?\n|", "\n", $filen);

or:[color=blue][color=green][color=darkred]
>>>echo preg_replace ("/\/\/\/(.*)/", "\n", $str);[/color][/color][/color]

Not "/n" :-)

Grtz,
--
Rik Wasmus

[julian_m]

Re: preg_replace question


Rik wrote:
[color=blue][color=green][color=darkred]
> >>>echo preg_replace ("/\/\/\/(.*)/", "\n", $str);[/color][/color]
>
> Not "/n" :-)
>[/color]

I don't know what I was thinking about ;)

Thanks Rik.

regards - julian