Dynamic Object Function Call in PHP

[aroldao@gmail.com]

Greetings Everyone,

In php it's possible to create a new object based on a name stored
in variable, i.e:

$className = "CSome$name ";
$newclass = new $className();

However is it possible to call a function from a class using a name
stored in a variable? For example:

$funcname = "operation" ;
$func= "\$someclas s->$funcname";

$func( arg1, arg2 );

With the same result as

$someclass->operation( arg1, arg2 );

Any feed-back will be much appreciated.

Cheers,
Roldao

[Chung Leong]

Re: Dynamic Object Function Call in PHP

What you are trying to do isn't possible. PHP treat the variable in
$func() strictly as a text string--not evaluable code. If $func
contains "$someclass->operation" it will just look for a standalone
function called "$someclass->operation."

[Jerry Stuckle]

Re: Dynamic Object Function Call in PHP

aroldao@gmail.c om wrote:[color=blue]
> Greetings Everyone,
>
> In php it's possible to create a new object based on a name stored
> in variable, i.e:
>
> $className = "CSome$name ";
> $newclass = new $className();
>
> However is it possible to call a function from a class using a name
> stored in a variable? For example:
>
> $funcname = "operation" ;
> $func= "\$someclas s->$funcname";
>
> $func( arg1, arg2 );
>
> With the same result as
>
> $someclass->operation( arg1, arg2 );
>
> Any feed-back will be much appreciated.
>
> Cheers,
> Roldao
>[/color]

Hi, Roldao,

Well, you have a problem. To call a non-static method in a class, you must have
an object of the class - not the name of the class.

So, for instance:

class MyClass {
function operation() {
...
}
}

MyClass->operation()

will fail.

However, if you do

$myclass = new MyClass();
$myclass->operation();

You can also call it indirectly, with

$function = "operation" ;

call_user_func( array($myclass) , $function);

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===

[aroldao@gmail.com]

Re: Dynamic Object Function Call in PHP

Thak-you for your feedback, both Jerry Stuckle and Chung Leong. Got it
sorted now.

Roldao


Jerry Stuckle wrote:[color=blue]
> aroldao@gmail.c om wrote:[color=green]
> > Greetings Everyone,
> >
> > In php it's possible to create a new object based on a name stored
> > in variable, i.e:
> >
> > $className = "CSome$name ";
> > $newclass = new $className();
> >
> > However is it possible to call a function from a class using a name
> > stored in a variable? For example:
> >
> > $funcname = "operation" ;
> > $func= "\$someclas s->$funcname";
> >
> > $func( arg1, arg2 );
> >
> > With the same result as
> >
> > $someclass->operation( arg1, arg2 );
> >
> > Any feed-back will be much appreciated.
> >
> > Cheers,
> > Roldao
> >[/color]
>
> Hi, Roldao,
>
> Well, you have a problem. To call a non-static method in a class, you must have
> an object of the class - not the name of the class.
>
> So, for instance:
>
> class MyClass {
> function operation() {
> ...
> }
> }
>
> MyClass->operation()
>
> will fail.
>
> However, if you do
>
> $myclass = new MyClass();
> $myclass->operation();
>
> You can also call it indirectly, with
>
> $function = "operation" ;
>
> call_user_func( array($myclass) , $function);
>
> --
> =============== ===
> Remove the "x" from my email address
> Jerry Stuckle
> JDS Computer Training Corp.
> jstucklex@attgl obal.net
> =============== ===[/color]