Help with US Holidays

[News]

All,
These are some functions I am using to calculate holidays, however,
Grandparents Day seems to be giving me some trouble.
This is what I am using to determine Labor Day (since GP day is the Sunday
after):

echo "Labor Day Observed (First Monday in September) = " . get_holiday( $y,
9, 1, 1 );
//Grandparents' Day, Sunday after Labor Day
echo "Grandparen ts' Day (Sunday after Labor Day) = " . get_holiday( ?, ?, ?,
? );

Using these functions, is it possible to determine GP day ?

function format_date( $year, $month, $day )
{
if ( strlen( $month ) == 1 ) {
$month = "0" . $month;
}
if ( strlen( $day ) == 1 ) {
$day = "0" . $day;
}
// $date = $year . "-" . $month . "-" . $day; //YYYY-MM-DD
$date = $month . "-" . $day . "-" . $year; //MM-DD-YYYY

return $date;
}

function get_holiday( $year, $month, $day_of_week, $week = "" )
{
if ( ( ( $week != "" ) && ( ( $week > 5 ) || ( $week < 1 ) ) ) || (
$day_of_week > 6 ) || ( $day_of_week < 0 ) ) {
// $day_of_week must be between 0 and 6 (Sun=0, ... Sat=6); $week must be
between 1 and 5
return false;
} else {
if ( !$week || ( $week == "" ) ) {
$lastday = date( "t", mktime( 0, 0, 0, $month, 1, $year ) );
$temp = ( date( "w", mktime( 0, 0, 0, $month, $lastday, $year ) ) -
$day_of_week ) % 7;
} else {
$temp = ( $day_of_week - date( "w", mktime( 0, 0, 0, $month, 1,
$year ) ) ) % 7;
}

if ( $temp < 0 ) {
$temp += 7;
}

if ( !$week || ( $week == "" ) ) {
$day = $lastday - $temp;
} else {
$day = ( 7 * $week ) - 6 + $temp;
}

return format_date( $year, $month, $day );
}
}

[Jochen Daum]

Re: Help with US Holidays

Hi News,

On Wed, 10 Mar 2004 15:48:55 -0900, "News" <news@news.co m> wrote:
[color=blue]
>All,
>These are some functions I am using to calculate holidays, however,
>Grandparents Day seems to be giving me some trouble.
>This is what I am using to determine Labor Day (since GP day is the Sunday
>after):
>
>echo "Labor Day Observed (First Monday in September) = " . get_holiday( $y,
>9, 1, 1 );
>//Grandparents' Day, Sunday after Labor Day
>echo "Grandparen ts' Day (Sunday after Labor Day) = " . get_holiday( ?, ?, ?,
>? );
>
>Using these functions, is it possible to determine GP day ?
>[/color]
If you have a database handy,

make an Excel sheet with all days for the next 10 years and fill in
the LAbour Days into a column as 1. You can then much more easily find
out what 'fetaures' a day has, and its easy to debug.

HTH, Jochen
--
Jochen Daum - Cabletalk Group Ltd.
PHP DB Edit Toolkit -- PHP scripts for building
database editing interfaces.

http://sourceforge.net/projects/phpdbedittk/

[StinkFinger]

Re: Help with US Holidays

echo "<li>Labor Day Observed (First Monday in September) = " .
get_holiday( $y, 9, 1, 1 );
//Grandparents' Day, Sunday after Labor Day
$lbday = get_holiday( $y, 9, 1, 1 ); //09-06-2004
list($lmonth,$l day,$lyear) = explode("-",$lbday);
$gptimestamp = mktime(0, 0, 0, $lmonth, $lday + 6, $lyear);
$gpday = date("m-d-Y", $gptimestamp);
echo "<li>Grandparen ts' Day (Sunday after Labor Day) = " . $gpday;

"News" <news@news.co m> wrote in message
news:104vdrpep8 8eh6e@corp.supe rnews.com...[color=blue]
> All,
> These are some functions I am using to calculate holidays, however,
> Grandparents Day seems to be giving me some trouble.
> This is what I am using to determine Labor Day (since GP day is the Sunday
> after):
>
> echo "Labor Day Observed (First Monday in September) = " . get_holiday([/color]
$y,[color=blue]
> 9, 1, 1 );
> //Grandparents' Day, Sunday after Labor Day
> echo "Grandparen ts' Day (Sunday after Labor Day) = " . get_holiday( ?, ?,[/color]
?,[color=blue]
> ? );
>
> Using these functions, is it possible to determine GP day ?
>
> function format_date( $year, $month, $day )
> {
> if ( strlen( $month ) == 1 ) {
> $month = "0" . $month;
> }
> if ( strlen( $day ) == 1 ) {
> $day = "0" . $day;
> }
> // $date = $year . "-" . $month . "-" . $day; //YYYY-MM-DD
> $date = $month . "-" . $day . "-" . $year; //MM-DD-YYYY
>
> return $date;
> }
>
> function get_holiday( $year, $month, $day_of_week, $week = "" )
> {
> if ( ( ( $week != "" ) && ( ( $week > 5 ) || ( $week < 1 ) ) ) || (
> $day_of_week > 6 ) || ( $day_of_week < 0 ) ) {
> // $day_of_week must be between 0 and 6 (Sun=0, ... Sat=6); $week must[/color]
be[color=blue]
> between 1 and 5
> return false;
> } else {
> if ( !$week || ( $week == "" ) ) {
> $lastday = date( "t", mktime( 0, 0, 0, $month, 1, $year ) );
> $temp = ( date( "w", mktime( 0, 0, 0, $month, $lastday, $year ) ) -
> $day_of_week ) % 7;
> } else {
> $temp = ( $day_of_week - date( "w", mktime( 0, 0, 0, $month, 1,
> $year ) ) ) % 7;
> }
>
> if ( $temp < 0 ) {
> $temp += 7;
> }
>
> if ( !$week || ( $week == "" ) ) {
> $day = $lastday - $temp;
> } else {
> $day = ( 7 * $week ) - 6 + $temp;
> }
>
> return format_date( $year, $month, $day );
> }
> }
>
>[/color]