Can't work out reason behind "unexpected T_VARIABLE" error

[Cleverbum@hotmail.com]

Hi,
been scratching my head for a while on this one and was wondering how
what was going wrong. I dont mind at this stage if the actual thing I'm
trying to do, just why on earth it wont accept that the variable is a
string and get on with it!!
the code is below, with the problem line highlighted.

<?
$myCounter=0;
$tabStr="";
$outStr[0]="";

myScanDir(".");

print_r($outStr );


function myScanDir($dir) {
global $myCounter, $mytabStr, $outStr, $tablength;
$fileslist= scandir($dir);
for($i=0;$i<cou nt($fileslist); $i++){
if(is_dir($file slist[$i])){
$outStr[$myCounter]= $tabStr . $fileslist;
$myCounter ++;
$tabStr .= "&nbsp;&nbs p;";
$myScandir($fil eslist[$i])
// the line below is the one which causes the errors.
$tabStr = substr($tabStr, 0, strlen($tabStr)-12);
}else{
$outStr[$myCounter]=$tabStr . $fileslist;
$myCounter++;
}
}
}
?>

[Oli Filth]

Re: Can't work out reason behind &quot;unexpecte d T_VARIABLE&quot ; error

Cleverbum@hotma il.com wrote:[color=blue]
> Hi,
> been scratching my head for a while on this one and was wondering how
> what was going wrong. I dont mind at this stage if the actual thing I'm
> trying to do, just why on earth it wont accept that the variable is a
> string and get on with it!!
> the code is below, with the problem line highlighted.
>[/color]
<...SNIP CODE...>

Semi-colons......... ..


--
Oli

[Cleverbum@hotmail.com]

Re: Can't work out reason behind &quot;unexpecte d T_VARIABLE&quot ; error

thanks, sorry for such a stupid post, i was sure that was the first
thing i checked!