preg_replace question

[Sam]

Hi

Can anyone help me with this problem please?

I have a long string that I would like to split into paragraphed
sentences. I would like to replace every full-stop or period ('.')
with the HTML tags "</p><p>", however, the string also contains
decimal numbers such as 2.4 and some sentences end with a number. But
no sentences starts with a number.

I am guessing I need to use preg_replace() ?

Thanks in advance.

Sam

[Pedro Graca]

Re: preg_replace question

Sam wrote:[color=blue]
> Hi
>
> Can anyone help me with this problem please?
>
> I have a long string that I would like to split into paragraphed
> sentences. I would like to replace every full-stop or period ('.')
> with the HTML tags "</p><p>", however, the string also contains
> decimal numbers such as 2.4 and some sentences end with a number. But
> no sentences starts with a number.
>
> I am guessing I need to use preg_replace() ?
>
> Thanks in advance.
>
> Sam[/color]

Wouldn't it be enough to replace all ". " with ".</p><p>"?

<?php
$new_text = preg_replace('@ \.\s@', '.</p><p>', $text);
?>


This way you'll get what you intend with

- The cat is here. The dog is there.
- Please see point 4. Or 5, I don't remember.

The last period in these examples isn't followed by white space and does
not get replaced with the snippet above. I think that's ok for the end
of the string or you'd end up with "</p><p></p>" in your HTML.
--
--= my mail box only accepts =--
--= Content-Type: text/plain =--
--= Size below 10001 bytes =--

[Sam]

Re: preg_replace question

Thanks for your reply, but I forgot to mention (sorry) that there are
no spaces after the periods! Is there a way to match a period in
between 2 letters and not between 2 numbers and then replace the
period with '.</p><p>' ?



[color=blue]
>
> Wouldn't it be enough to replace all ". " with ".</p><p>"?
>
> <?php
> $new_text = preg_replace('@ \.\s@', '.</p><p>', $text);
> ?>
>
>[/color]

[John Dunlop]

Re: preg_replace question

Sam wrote upsidedown:
[color=blue]
> Is there a way to match a period in between 2 letters and not between
> 2 numbers and then replace the period with '.</p><p>' ?[/color]

$string = preg_replace(
'`(?<=[a-z])\.(?=[a-z])`i',
'.</p><p>',
$string)

You'd have to add other characters to the character class if you need
them.

So tell me, why are you doing this?

--
Jock

[Sam]

Re: preg_replace question

My solution:

function _insertP($str){
$str[0] = str_replace("." ,".</p><p>",$str[0]);
return $str[0];
}

$text_new = preg_replace_ca llback('@\.[A-Z]@','_insertP',$ text);