PHP function question

[Tony]

When writing a function that takes in a variable number of parameters and
processing it using func_get_args or a similar technique, I'm assuming that
one is only able to use the pass by value method of parameter passing. Can
someone confirm or deny this for me?

Below is a trivial example of what I'm talking about. I'm assuming the
function below does nothing useful.

<?php

function squares( )
{
$params=functio n_get_args();
$numparams= func_num_args() ;
for ($i=0;$i<$numpa rams;$i++)
$params[$i]*=$params[$i];
}

?>

[Pedro Graca]

Re: PHP function question

["Followup-To:" header set to comp.lang.php.]
Tony wrote:[color=blue]
> When writing a function that takes in a variable number of parameters and
> processing it using func_get_args or a similar technique, I'm assuming that
> one is only able to use the pass by value method of parameter passing. Can
> someone confirm or deny this for me?[/color]

I think you're right.
[color=blue]
> Below is a trivial example of what I'm talking about. I'm assuming the
> function below does nothing useful.
>
><?php
>
> function squares( )
> {
> $params=functio n_get_args();
> $numparams= func_num_args() ;
> for ($i=0;$i<$numpa rams;$i++)
> $params[$i]*=$params[$i];
> }
>
> ?>[/color]


But you can use the $GLOBALS variable to pretend you're passing by
reference.

Here's a way

<?php
function squares() {
$parms = func_get_args() ;
$nparms = func_num_args() ;
$retval = array(); // return array

for ($i = 0; $i < $nparms; ++$i)
if ($parms[$i]{0} == '$')
$GLOBALS[substr($parms[$i], 1)] *=
$GLOBALS[substr($parms[$i], 1)];
else $retval[] = $parms[$i] * $parms[$i];
return $retval;
}

$a = 6; $b = 7; $c = 8;
$res = squares($a, "$b", '$c');

print_r($res);
echo $c;
?>
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