Assoc Arrays

[David]

I have a script which retrives a list of files then reads the first
two lines of each one of these files.
Code:
function retrieve_header s($username)
{
if(!file_exists ('c:/'.$username))
return false;
$directory = opendir("c:/$username//");
$ary=array();
while($file = readdir($direct ory))
{
if(!(is_dir($fi le) || ($file=='.') || ($file =='..')))
{
$fp = fopen("c:/$username/$file", "r");
$recip = fgets($fp);
$sender = fgets($fp);
array_push($ary ,"$recip$sender ");
fclose($fp);
}
}
return $ary;
}
The idea is I want an array with $recip as the key and $sender as the
value.
Unfortunently the above code outputs an array like this:
Code:
0 => foo bar
1 => foo bar
2 => foo bar
Any idea how I could go about this?

[CountScubula]

Re: Assoc Arrays

"David" <biffta@hotmail .com> wrote in message
news:3eb239cb.0 401301013.72139 8a5@posting.goo gle.com...[color=blue]
>...[/color]
[color=blue]
> $fp = fopen("c:/$username/$file", "r");
> $recip = fgets($fp);
> $sender = fgets($fp);
> array_push($ary ,"$recip$sender ");
> fclose($fp);
> ....
> The idea is I want an array with $recip as the key and $sender as the
> value.[/color]


change:
array_push($ary ,"$recip$sender ");
to:
$ary[$recip] = $sender;
--

Mike Bradley
http://www.gzentools.com -- free online php tools

[David]

Re: Assoc Arrays

> change:[color=blue]
> array_push($ary ,"$recip$sender ");
> to:
> $ary[$recip] = $sender;[/color]

That works but it removes all duplicates which I do not want. Is there
a way to do this without removing duplicate values?

[steven mestdagh]

Re: Assoc Arrays

David <biffta@hotmail .com> wrote:[color=blue][color=green]
> > change:
> > array_push($ary ,"$recip$sender ");
> > to:
> > $ary[$recip] = $sender;[/color]
>
> That works but it removes all duplicates which I do not want. Is there
> a way to do this without removing duplicate values?[/color]

the key of an array element is unique. wouldn't it be easier to
fill two arrays? or fill the array with two-element arrays, if you
need everything inside one array.

steven.