preg_replace and back reference

[Richard B. Christ]

I wrote the following code and it does NOT seem to work.

$search = array('/<popup[^>]*>/ie');
$replace = array('make_pop up(split_tag(\\ 0))');
preg_replace($s earch, $replace, $someText);

If I try the following code, then the replacing seems to work (I just try to get a
dummy back reference \\1)

$search = array('/<p(op)up[^>]*>/ie');
$replace = array('make_pop up(split_tag(\\ 1))');
preg_replace($s earch, $replace, $someText);

What is wrong in the first part? Thanks and cheers,

richard

[Pedro Graca]

Re: preg_replace and back reference

Richard B. Christ wrote:[color=blue]
> I wrote the following code and it does NOT seem to work.
>
> $search = array('/<popup[^>]*>/ie');
> $replace = array('make_pop up(split_tag(\\ 0))');
> preg_replace($s earch, $replace, $someText);
>
> If I try the following code, then the replacing seems to work (I just try to get a
> dummy back reference \\1)
>
> $search = array('/<p(op)up[^>]*>/ie');
> $replace = array('make_pop up(split_tag(\\ 1))');
> preg_replace($s earch, $replace, $someText);
>
> What is wrong in the first part? Thanks and cheers,[/color]

Why do you need the /e modifier to preg_replace()?

The first snippet will try to evaluate
make_popup(spli t_tag(<popup parm1="value1" parm2="value2"> ))
as if it was php code.

Maybe you want to evaluate
make_popup(spli t_tag('<popup parm1="value1" parm2="value2"> '))
// _______________ ___^___________ _______________ ___________^__
this instead.


The second snippet (which is also wrong!!) will try to evaluate
make_popup(spli t_tag(op))

which php will convert (with a warning) to
make_popup(spli t_tag('op'))



So ... turn on all warnings:
<?php error_reporting (E_ALL); ?>

And check the result of preg_replace without the /e modifier first.



Happy Coding :-)
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