can i put the same data in the two different drop box?

Re: can i put the same data in the two different drop box?

ywan_ip@hotmail .com (Krista) wrote in message
news:<eb97c972. 0312311133.6587 b063@posting.go ogle.com>...[color=blue]
>
> Hi, can i load the same table in the two drop-down list?[/color]

Yes, and there doesn't have to be two queries, either:

$Query = "select * from Parts";
$result = mysql_query ($Query);
echo '<select name="dropdown1 ">';
while ($record = mysql_fetch_arr ay ($result)) {
// the first drop-down list is output here...
}
echo '</select>';
mysql_data_seek ($result, 0); // rewind the data pointer
echo '<select name="dropdown2 ">';
while ($record = mysql_fetch_arr ay ($result)) {
// the second drop-down list is output here...
}
echo '</select>';

Cheers,
NC

Re: can i put the same data in the two different drop box?

Krista wrote:[color=blue]
> Hi, can i load the same table in the two drop-down list?
> $DBName = Krista;
> $Query = "select * from Parts";
> $ResultPart0 = mysql_db_query( $DBName, $QueryPart, $linkID);[/color]
What is $QueryPart? _______________ ______^^^^^^^^^ ^__

Other than that, I think it should work; but haven't tested your code.

To avoid such problems (if this is it) in the future put
<?php
error_reporting (E_ALL)
ini_set('displa y_errors', '1');
?>

at the very beginning of your scripts so that PHP complains about much
more than usual :)
--
--= my mail box only accepts =--
--= Content-Type: text/plain =--
--= Size below 10001 bytes =--

Hi, can i load the same table in the two drop-down list?
$DBName = Krista;
$Query = "select * from Parts";
$ResultPart0 = mysql_db_query( $DBName, $QueryPart, $linkID);
$ResultPart1 = mysql_db_query( $DBName, $QueryPart, $linkID);
.........
<tr><td>Part Number 0 from Inventory:</td>
<td><select name =\"Assembled_Pa rt\">");
$count = 0;
while($Row0 = mysql_fetch_arr ay($ResultPart0 )){
$count++;
print("<option value =\"$count\">$Ro w0[Part_Number]</option>");
}
print(" </select></td></tr>

<tr><td>Part Number 1 from Inventory:</td>

<td><select name =\"Assembled_Pa rt1\">");
$count1 = 0;
while($Row1 = mysql_fetch_arr ay($ResultPart1 )){
$count1++;
print("<option value =\"$count1\">$R ow1[Part_Number]</option>");
}
print(" </select></td></tr>
............... .....
............... ....

when i do like this, i can load from the table , but i cannot get the
result after i click the submit button. eg.
print $_GET['Assembled_Part 0'];
print $_GET['Assembled_Part 1'];
it can only show the first one result, do u guys have any idea for me
to solve it? I want to get both of them. Thanks
krista