PHP4 Object handling vs PHP5

Re: PHP4 Object handling vs PHP5

Phil Roberts <philrob@HOLYfl atnetSHIT.net> wrote in message news:<Xns942F72 61E9772philrobe rts@206.127.4.2 2>...[color=blue]
> With total disregard for any kind of safety measures
> chernyshevsky@h otmail.com (Chung Leong) leapt forth and uttered:
>[color=green]
> > I have always assumed that PHP4 uses a copy-on-write approach,
> > so that when you pass an object to a function by value, PHP
> > doesn't actually create a new copy of that object.
> >[/color]
>
> In PHP4 all variables are passed by value unless you explicitly tell
> it to pass by reference. So unless you use the & when passing an
> object to a function/method PHP4 will create a copy.[/color]

The question is, does it create a physical copy (using up extra
memory) or a virtual copy (a physical copy happens only if one of the
copies is modified)?

Re: PHP4 Object handling vs PHP5

With total disregard for any kind of safety measures
chernyshevsky@h otmail.com (Chung Leong) leapt forth and uttered:
[color=blue]
> I have always assumed that PHP4 uses a copy-on-write approach,
> so that when you pass an object to a function by value, PHP
> doesn't actually create a new copy of that object.
>[/color]

In PHP4 all variables are passed by value unless you explicitly tell
it to pass by reference. So unless you use the & when passing an
object to a function/method PHP4 will create a copy.

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Help me here. I've become a bitconfused about how PHP4 deals with
objects after reading this description of PHP5:

"PHP's handling of objects has been completely rewritten, allowing for
better performance and more features. In previous versions of PHP,
objects were handled like primitive types (for instance integers and
strings). The drawback of this method was that semantically the whole
object was copied when a variable was assigned, or pass as a parameter
to a method. In the new approach, objects are referenced by handle,
and not by value (one can think of a handle as an object's
identifier)."

I have always assumed that PHP4 uses a copy-on-write approach, so that
when you pass an object to a function by value, PHP doesn't actually
create a new copy of that object.