Pointer in PHP

Re: Pointer in PHP

Denis Crespe wrote:[color=blue]
> Hi,
>
> Is it possible to keep a pointer to an object in a PHP variable? I'd like to
> do this :
>
> $obj1 = new myClass(...);
> $obj2 = $obj1;
> $obj1->name = "foo";
> $obj2->name = "bar";
>
> echo $obj1->name;
>
> Which would display "bar" instead of "foo" with the current PHP behavior.
>
> Thanks a lot,
> Denis[/color]
$obj2 = &$obj1;

--
John Downey

http://delusive.dyn.ee

http://sage.dev.box.sk

http://blacksun.box.sk

Re: Pointer in PHP

Awesome! It's what I wanted :-)

Denis

"rush" <pipa@rush.aval on.hr> a écrit dans le message de news:
bnh4b3$e4u$1@ls 219.htnet.hr...[color=blue]
> "Denis Crespe" <a@a.com> wrote in message
> news:bnh2mc$1p2 $1@news.tiscali .fr...[color=green]
> > $obj1 = new myClass(...);
> > $obj2 = $obj1;
> > $obj1->name = "foo";
> > $obj2->name = "bar";
> >
> > echo $obj1->name;
> >
> > Which would display "bar" instead of "foo" with the current PHP[/color][/color]
behavior.[color=blue]
>
> you can not get the pointer, but you can get the reference:
>
> $obj2 = & $obj1;
>
> rush
> --
> http://www.templatetamer.com/
>
>
>[/color]

Re: Pointer in PHP

"Denis Crespe" <a@a.com> wrote in message
news:bnh2mc$1p2 $1@news.tiscali .fr...[color=blue]
> $obj1 = new myClass(...);
> $obj2 = $obj1;
> $obj1->name = "foo";
> $obj2->name = "bar";
>
> echo $obj1->name;
>
> Which would display "bar" instead of "foo" with the current PHP behavior.[/color]

you can not get the pointer, but you can get the reference:

$obj2 = & $obj1;

rush
--

http://www.templatetamer.com/

Hi,

Is it possible to keep a pointer to an object in a PHP variable? I'd like to
do this :

$obj1 = new myClass(...);
$obj2 = $obj1;
$obj1->name = "foo";
$obj2->name = "bar";

echo $obj1->name;

Which would display "bar" instead of "foo" with the current PHP behavior.

Thanks a lot,
Denis