PHP 4.3.3

[Wayne]

Ok I hope someone can clear this up for me because my laptop is going
in the bin or across the room soon.

I have installed versions:

MySQL 4.0.15
Apache 2.0.47
PHP 4.3.3

I have put the php4ts.dll in c:\winnt\system 32\
I have changed the php.ini in c:\winnt\
I have changed the httpd.conf in c:\Program FIles\Apache
Group\Apache2\c onf\

I have done bloody everything...

Apache I know works I can get the page up when I go localhost on
browser.
MySQL works because I have tried examples.
PHP seems to work with most things, but not with IF () statements!

for example:

<?php
if ($submit == "Go") {
echo("you wrote ".$you_wrot e);
echo("<br>You could have written");
exit;
}
?>
<form action="<?php echo($PHP_SELF) ?>" method="POST" >
<p>Input a word <input type="text" size="20" name="you_wrote ">
<input type="submit" name="Submit" value="Go"></p>
</form>

If I save this as php file and go to browser and call it up, I get
notice come up

"Notice: Undefined variable: submit in C:\Program Files\Apache
Group\Apache2\h tdocs\test0.php on line 2"

Line being if ($submit == "Go") {

Can someone please tell me what needs doing please....

[Bert]

Re: PHP 4.3.3

On 30 Sep 2003 07:32:18 -0700, w.bristow@rchl. org.uk (Wayne) wrote:
[color=blue]
>Ok I hope someone can clear this up for me because my laptop is going
>in the bin or across the room soon.
>
>I have installed versions:
>
>MySQL 4.0.15
>Apache 2.0.47
>PHP 4.3.3
>
>I have put the php4ts.dll in c:\winnt\system 32\
>I have changed the php.ini in c:\winnt\
>I have changed the httpd.conf in c:\Program FIles\Apache
>Group\Apache2\ conf\
>
>I have done bloody everything...
>
>Apache I know works I can get the page up when I go localhost on
>browser.
>MySQL works because I have tried examples.
>PHP seems to work with most things, but not with IF () statements!
>
>for example:
>
><?php
>if ($submit == "Go") {
> echo("you wrote ".$you_wrot e);
> echo("<br>You could have written");
> exit;
>}
>?>
><form action="<?php echo($PHP_SELF) ?>" method="POST" >
><p>Input a word <input type="text" size="20" name="you_wrote ">
><input type="submit" name="Submit" value="Go"></p>
></form>
>
>If I save this as php file and go to browser and call it up, I get
>notice come up
>
>"Notice: Undefined variable: submit in C:\Program Files\Apache
>Group\Apache2\ htdocs\test0.ph p on line 2"
>
>Line being if ($submit == "Go") {
>
>Can someone please tell me what needs doing please....[/color]


Not sure, but did you try if ($_POST['submit'] == "Go") {...
B.

[Bert]

Re: PHP 4.3.3

On Tue, 30 Sep 2003 14:40:12 GMT, Bert <bert@pandora.i nvalid> wrote:


[color=blue]
>
>Not sure, but did you try if ($_POST['submit'] == "Go") {...
>B.[/color]

and change $PHP_SELF to $_SERVER['PHP_SELF'] while you're at it :)
B.

[Justin Koivisto]

Re: PHP 4.3.3

Bert wrote:
[color=blue]
> On Tue, 30 Sep 2003 14:40:12 GMT, Bert <bert@pandora.i nvalid> wrote:
>
>
>
>[color=green]
>>Not sure, but did you try if ($_POST['submit'] == "Go") {...
>>B.[/color]
>
>
> and change $PHP_SELF to $_SERVER['PHP_SELF'] while you're at it :)
> B.
>[/color]

Or if you don't want to edit tons of files, in php.ini:
register_global s = On

--
Justin Koivisto - spam@koivi.com
PHP POSTERS: Please use comp.lang.php for PHP related questions,
alt.php* groups are not recommended.

[Phil Roberts]

Re: PHP 4.3.3

With total disregard for any kind of safety measures
w.bristow@rchl. org.uk (Wayne) leapt forth and uttered:
[color=blue]
> Ok I hope someone can clear this up for me because my laptop is
> going in the bin or across the room soon.
>
> I have installed versions:
>
> MySQL 4.0.15
> Apache 2.0.47
> PHP 4.3.3
>
> I have put the php4ts.dll in c:\winnt\system 32\
> I have changed the php.ini in c:\winnt\
> I have changed the httpd.conf in c:\Program FIles\Apache
> Group\Apache2\c onf\
>
> I have done bloody everything...
>
> Apache I know works I can get the page up when I go localhost on
> browser.
> MySQL works because I have tried examples.
> PHP seems to work with most things, but not with IF ()
> statements!
>
> for example:
>
> <?php
> if ($submit == "Go") {
> echo("you wrote ".$you_wrot e);
> echo("<br>You could have written");
> exit;
> }
> ?>
> <form action="<?php echo($PHP_SELF) ?>" method="POST" >
> <p>Input a word <input type="text" size="20" name="you_wrote ">
> <input type="submit" name="Submit" value="Go"></p>
> </form>
>
> If I save this as php file and go to browser and call it up, I
> get notice come up
>
> "Notice: Undefined variable: submit in C:\Program Files\Apache
> Group\Apache2\h tdocs\test0.php on line 2"
>
> Line being if ($submit == "Go") {
>
> Can someone please tell me what needs doing please....[/color]

You need to set the error reporting to suppress notices, it
explains how in php.ini

--
There is no signature.....

[Andy Hassall]

Re: PHP 4.3.3

On Tue, 30 Sep 2003 12:14:55 -0500, Phil Roberts <philrob@HOLYfl atnetSHIT.net>
wrote:
[color=blue]
>You need to set the error reporting to suppress notices, it
>explains how in php.ini[/color]

You could also close your eyes, that works too. Don't ignore warnings; they're
there for a reason!

In this case the OP seems to think that global variables will be defined for
form inputs; they aren't, unless you change the configuration, and there's good
reasons why you shouldn't.

Look up 'register_globa ls', the Predefined Variables section of the manual,
and the 4.1.0 and 4.2.0 release announcements on php.net.

--
Andy Hassall (andy@andyh.co. uk) icq(5747695) (http://www.andyh.co.uk)
Space: disk usage analysis tool (http://www.andyhsoftware.co.uk/space)

[medi]

Re: PHP 4.3.3


"Wayne" <w.bristow@rchl .org.uk> wrote in message
news:b4c26164.0 309300632.48fec e3c@posting.goo gle.com...[color=blue]
> Ok I hope someone can clear this up for me because my laptop is going
> in the bin or across the room soon.
>
> I have installed versions:
>
> MySQL 4.0.15
> Apache 2.0.47
> PHP 4.3.3
>
> I have put the php4ts.dll in c:\winnt\system 32\
> I have changed the php.ini in c:\winnt\
> I have changed the httpd.conf in c:\Program FIles\Apache
> Group\Apache2\c onf\
>
> I have done bloody everything...
>
> Apache I know works I can get the page up when I go localhost on
> browser.
> MySQL works because I have tried examples.
> PHP seems to work with most things, but not with IF () statements!
>
> for example:
>
> <?php
> if ($submit == "Go") {
> echo("you wrote ".$you_wrot e);
> echo("<br>You could have written");
> exit;
> }
> ?>
> <form action="<?php echo($PHP_SELF) ?>" method="POST" >
> <p>Input a word <input type="text" size="20" name="you_wrote ">
> <input type="submit" name="Submit" value="Go"></p>
> </form>
>
> If I save this as php file and go to browser and call it up, I get
> notice come up
>
> "Notice: Undefined variable: submit in C:\Program Files\Apache
> Group\Apache2\h tdocs\test0.php on line 2"
>
> Line being if ($submit == "Go") {[/color]

That's because submit buttons never pass their name as variable (POST or
GET).
That's why hidden fields are used. Try this:

<?php

if (isset($_POST['status']))
{
if($_POST['status'] == "Go")
{
echo("you wrote ".$_POST['you_wrote']);
echo("<br>You could have written");
exit;
}
}

?>

<form action="<?php echo($_SERVER['PHP_SELF']) ?>" method="POST">< p>
Input a word <input type="text" size="20" name="you_wrote ">
<input type="submit" name="submit" value="Go">
<input name="status" type="hidden" value="Go">
</form>

Hope this will help....

[Andy Hassall]

Re: PHP 4.3.3

On Tue, 30 Sep 2003 23:36:30 +0200, "medi" <medi@spinter.n et> wrote:
[color=blue][color=green]
>> <input type="submit" name="Submit" value="Go"></p>
>> </form>
>>
>> If I save this as php file and go to browser and call it up, I get
>> notice come up
>>
>> "Notice: Undefined variable: submit in C:\Program Files\Apache
>> Group\Apache2\h tdocs\test0.php on line 2"
>>
>> Line being if ($submit == "Go") {[/color]
>
>That's because submit buttons never pass their name as variable (POST or
>GET).
>That's why hidden fields are used. Try this:[/color]

Named submit controls can be successful controls:

<form method="get" action="">
<input type="submit" name="submitBut ton" value="whatever ">
</form>
<pre>
<?php
var_dump($_GET) ;
?>
</pre>

Submit the form back to itself, output is:

array(1) {
["submitButt on"]=>
string(8) "whatever"
}

http://www.w3.org/TR/html4/interact/forms.html#successful-controls

"If a form contains more than one submit button, only the activated submit
button is successful. "

Therefore a submit button can be successful, and so sends a value.

--
Andy Hassall (andy@andyh.co. uk) icq(5747695) (http://www.andyh.co.uk)
Space: disk usage analysis tool (http://www.andyhsoftware.co.uk/space)