Populate picklist from directory and return file name

[Mike Brashars]

Hi all,

I have been searching for a week and am unable to find and example to
"Populate picklist from directory and return file name".

I have a php script that reads a log file and plots a graph. Right now, the
log name is hard coded. The logs are archived each day in the form of say
ddmmyy.log and I would like to put a drop down list in the script that would
allow my script to run off the "log" picked or default to the current "hard
coded" name.

I thought this would be a really common thing but I guess not.

I would be open to a javascript or asp script as long as I could "feed"

the file name to my php script.

Can anyone point me to a script like this??

Thanks a million!

[Sandman]

Re: Populate picklist from directory and return file name

In article <rInVe.14457$ct 5.12705@fed1rea d04>,
"Mike Brashars" <mike@apayrolls ervice.com> wrote:
[color=blue]
> Hi all,
>
> I have been searching for a week and am unable to find and example to
> "Populate picklist from directory and return file name".
>
> I have a php script that reads a log file and plots a graph. Right now, the
> log name is hard coded. The logs are archived each day in the form of say
> ddmmyy.log and I would like to put a drop down list in the script that would
> allow my script to run off the "log" picked or default to the current "hard
> coded" name.
>
> I thought this would be a really common thing but I guess not.
>
> I would be open to a javascript or asp script as long as I could "feed"
>
> the file name to my php script.
>
> Can anyone point me to a script like this??
>
> Thanks a million![/color]

<?
# Directory
$dir = "/path/to/a/dir/";

print "<select name='file'>";
while (false !== ($file = readdir($dir))) {
if (in_array($file , array(".", ".."))) continue;
print "<option value='$file'>$ file</option>";
}
print "</select>";

?>



--
Sandman[.net]

[sunbum]

Re: Populate picklist from directory and return file name

Thanks Sandman!

It seems it doesn't quite like the print statements ......

Parse error: parse error, unexpected T_STRING in line 5, also in 7, it
doesn't like the "." in the array statement .... unexpected "."

Using php 4.3, IIS5

Thank you!

[Sandman]

Re: Populate picklist from directory and return file name

In article <1126620330.013 385.212480@g43g 2000cwa.googleg roups.com>,
"sunbum" <mbrashars@gmai l.com> wrote:
[color=blue]
> Thanks Sandman!
>
> It seems it doesn't quite like the print statements ......
>
> Parse error: parse error, unexpected T_STRING in line 5, also in 7, it
> doesn't like the "." in the array statement .... unexpected "."
>
> Using php 4.3, IIS5
>
> Thank you![/color]


I'm terribly sorry, one line was missing. This:

$dir = opendir($dir);

Should go before the while loop.

--
Sandman[.net]

[sunbum]

Re: Populate picklist from directory and return file name

Here is what I have now ... (without the line numbers)

1)<?
2) # Directory
3) $dir = "\inetpub\wwwro ot\templogs\";
4)
5) print "<select name='file'>";
6) $dir = opendir($dir);
7) while (false !== ($file = readdir($dir))) {
8) if (in_array($file , array(".", ".."))) continue;
9) print "<option value='$file'>$ file</option>";
10) }
11) print "</select>";
12)
13)
14)?>

Still gives "Parse error: parse error, unexpected T_STRING in (script)
on line 5

:(

Mike

[sunbum]

Re: Populate picklist from directory and return file name

Found it!

oh dummy me, it was the "\" in my path needed to be $dir =
"/inetpub/wwwroot/templogs/";

now it works perfectly!!! Thank you!!

One last thing to bug you..... what holds the final selection of the
file? is it $file[select] ?

and what would signal that I am done selecting and want to do something
with the value?

Thanks so very much again!!

Mike

[Steve]

Re: Populate picklist from directory and return file name

[color=blue]
> One last thing to bug you..... what holds the final selection of the
> file? is it $file[select] ?[/color]
[color=blue]
> and what would signal that I am done selecting and want to do something
> with the value?[/color]

Make it into a form, with a submit button. See any HTML forms tutorial
for details.

---
Steve

[Sandman]

Re: Populate picklist from directory and return file name

In article <1126621984.221 410.309530@g44g 2000cwa.googleg roups.com>,
"sunbum" <mbrashars@gmai l.com> wrote:
[color=blue]
> Here is what I have now ... (without the line numbers)
>
> 1)<?
> 2) # Directory
> 3) $dir = "\inetpub\wwwro ot\templogs\";
> 4)
> 5) print "<select name='file'>";
> 6) $dir = opendir($dir);
> 7) while (false !== ($file = readdir($dir))) {
> 8) if (in_array($file , array(".", ".."))) continue;
> 9) print "<option value='$file'>$ file</option>";
> 10) }
> 11) print "</select>";
> 12)
> 13)
> 14)?>
>
> Still gives "Parse error: parse error, unexpected T_STRING in (script)
> on line 5[/color]

Strange. It works like a charm for me. Maybe you got some strange invisible
character caught on that line?

--
Sandman[.net]

[sunbum]

Re: Populate picklist from directory and return file name

No, it worked great!

I think our messages just crossed.

It was the back slashes in my file path. Your code was perfect :)

Do you have any pointers on this....
[color=blue]
> One last thing to bug you..... what holds the final selection of the
> file? is it $file[select] ?
> and what would signal that I am done selecting and want to do something
> with the value?[/color]

Thanks for all the patients and great help Sandman! you're the best

Mike

[Sandman]

Re: Populate picklist from directory and return file name

In article <1126636683.912 701.98450@g47g2 000cwa.googlegr oups.com>,
"sunbum" <mbrashars@gmai l.com> wrote:
[color=blue]
> No, it worked great!
>
> I think our messages just crossed.
>
> It was the back slashes in my file path. Your code was perfect :)
>
> Do you have any pointers on this....
>[color=green]
> > One last thing to bug you..... what holds the final selection of the
> > file? is it $file[select] ?
> > and what would signal that I am done selecting and want to do something
> > with the value?[/color][/color]

You are outputting a form, that will look something like this:

<select name='file'>
<option value='bonjour. txt'>bonjour.tx t</option>
<option value='hello.tx t'>hello.txt</option>
</select>

When you submit that form, it will be put in $_GET["file"] on the receiving PHP
script.


--
Sandman[.net]

[sunbum]

Re: Populate picklist from directory and return file name

Thanks Sandman,

Could you glance at this and see if I'm going in the right direction?

<?php
<html>
<head><title>Co oler Log Graph</title></head>
<body>


<form action="coolerl inec.php" method="post">;
# Directory
$dir = "/inetpub/wwwroot/templogs/";

print "<select name='file'>";
$dir = opendir($dir);
while (false !== ($file = readdir($dir))) {
if (in_array($file , array(".", ".."))) continue;
print "<option value='$file'>$ file</option>";
}
print "</select>";


<input type="submit" value="Submit"> ;
</form>

</body>
</html>
?>

Thanks again!

Anyone else is more than welcome to chime in too! The main function is
from "Sandman" and works great, I am now just trying to incorporate it
into a form. Obviously I am greener than grass ;)

Mike

[sunbum]

Re: Populate picklist from directory and return file name

Sorry for replying to my own post.

Here is the latest version and I think it's closer.

Can someone help me clean up the syntax?

Thanks!
------- Code begin (this is NOT in the script ------------------

<?php
if (isset($_POST['file']))
{
// process the data, see if it's valid.
// if it's valid and you're satisfied, do whatever you want with
the data
// if not, start outputting the form

$file = "/inetpub/wwwroot/templogs/"+$_POST['file'];
// Display the Graph
displaygraph();
}

else {
// display the form
displayform();
}

<?php
function displaygraph() {
echo "So far so good, this would draw graph with $file";

}


?>

<?php
function displayform() {


<form name="cooler" action="<?php $server['PHP_SELF']?>"
method=\"post\" >";
$dir = "/inetpub/wwwroot/templogs/";

echo "<select name='file'>";
$dir = opendir($dir);
while (false !== ($file = readdir($dir))) {
if (in_array($file , array(".", ".."))) continue;
print "<option value='$file'>$ file</option>";
}
</select>;


<input type="submit" value="Submit"> ;
</form>

}


?>


?>

------- Code end (this is NOT in the script ------------------

Mike

[Sandman]

Re: Populate picklist from directory and return file name

In article <1126718878.324 648.246160@g49g 2000cwa.googleg roups.com>,
"sunbum" <mbrashars@gmai l.com> wrote:
[color=blue]
> Sorry for replying to my own post.
>
> Here is the latest version and I think it's closer.
>
> Can someone help me clean up the syntax?
>
> Thanks!
> ------- Code begin (this is NOT in the script ------------------
>
> <?php
> if (isset($_POST['file']))
> {
> // process the data, see if it's valid.
> // if it's valid and you're satisfied, do whatever you want with
> the data
> // if not, start outputting the form
>
> $file = "/inetpub/wwwroot/templogs/"+$_POST['file'];
> // Display the Graph
> displaygraph();
> }
>
> else {
> // display the form
> displayform();
> }
>
> <?php
> function displaygraph() {
> echo "So far so good, this would draw graph with $file";
>
> }
>
>
> ?>
>
> <?php
> function displayform() {
>
>
> <form name="cooler" action="<?php $server['PHP_SELF']?>"
> method=\"post\" >";
> $dir = "/inetpub/wwwroot/templogs/";
>
> echo "<select name='file'>";
> $dir = opendir($dir);
> while (false !== ($file = readdir($dir))) {
> if (in_array($file , array(".", ".."))) continue;
> print "<option value='$file'>$ file</option>";
> }
> </select>;
>
>
> <input type="submit" value="Submit"> ;
> </form>
>
> }
>
>
> ?>
>
>
> ?>
>
> ------- Code end (this is NOT in the script ------------------
>
> Mike[/color]


The above is a good start. But you can't just start typing "<form name..."
inside a function block. You need to use

print "<form name='cooler' ....";


I always do my web app logic like this:


<?
while (1){
if ($_POST["file"]){
# Do fancy stufff
break;
}

# output form
$dir = "/inetpub/wwwroot/templogs/";
# ...

break;
}

--
Sandman[.net]