joining string

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  • socialism001@yahoo.com

    joining string

    I'm new to php and have read the implode statement on php.net but I
    guess I still don't understand it. Below is what I have:

    $value = implode($disp_c ap," - ",substr($value ,0,300));

    $disp_cap = Office Space
    $value = 3,000 sq.ft. located at the intersection of...

    I need the $value to join the two so I would get
    Office Space - 3,000 sq.ft. located at the...

    I get the error:
    Warning: Wrong parameter count for implode() in
    /home/GQ/public_html/bb/test.php on line 92

    Thanks,
    Chris

  • Dale

    #2
    Re: joining string

    $a = "Hello";
    $b = "world";
    $c = $a." ".$b;

    echo $c;

    "Hello World"

    Is that what you want to do? Use the . "dot" to concat strings.

    Comment

    • John T

      #3
      Re: joining string

      I think maybe you want to do this:

      $value = $disp_cap." - ".substr($value ,0,300);


      <socialism001@y ahoo.com> wrote in message
      news:1118126102 .364080.283710@ o13g2000cwo.goo glegroups.com.. .[color=blue]
      > I'm new to php and have read the implode statement on php.net but I
      > guess I still don't understand it. Below is what I have:
      >
      > $value = implode($disp_c ap," - ",substr($value ,0,300));
      >
      > $disp_cap = Office Space
      > $value = 3,000 sq.ft. located at the intersection of...
      >
      > I need the $value to join the two so I would get
      > Office Space - 3,000 sq.ft. located at the...
      >
      > I get the error:
      > Warning: Wrong parameter count for implode() in
      > /home/GQ/public_html/bb/test.php on line 92
      >
      > Thanks,
      > Chris
      >[/color]


      Comment

      • Alvaro G Vicario

        #4
        Re: joining string

        *** socialism001@ya hoo.com wrote/escribió (6 Jun 2005 23:35:02 -0700):[color=blue]
        > $value = implode($disp_c ap," - ",substr($value ,0,300));[/color]
        [color=blue]
        > Warning: Wrong parameter count for implode() in
        > /home/GQ/public_html/bb/test.php on line 92[/color]



        As you can see, implode() does _not_ have three arguments.

        --
        -- Álvaro G. Vicario - Burgos, Spain
        -- http://bits.demogracia.com - Mi sitio sobre programación web
        -- Don't e-mail me your questions, post them to the group
        --

        Comment

        • Tony

          #5
          Re: joining string

          <socialism001@y ahoo.com> wrote in message
          news:1118126102 .364080.283710@ o13g2000cwo.goo glegroups.com.. .[color=blue]
          > I'm new to php and have read the implode statement on php.net but I
          > guess I still don't understand it. Below is what I have:
          >
          > $value = implode($disp_c ap," - ",substr($value ,0,300));
          >
          > $disp_cap = Office Space
          > $value = 3,000 sq.ft. located at the intersection of...
          >
          > I need the $value to join the two so I would get
          > Office Space - 3,000 sq.ft. located at the...[/color]

          I think simple concatenation would be better for what you want to achieve:

          $finalString = $disp_cap . " - " . $value;



          Comment

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