Question about delimiters.

[starlight849]

I'm using the printf function to display some textual information. It is possible that the string may contain different symbols such as $#%^&* somewhere within the text.

I know that to handle the % that I need to use a %% to make the string evaluate correctly.
for example:

printf "strin%%g";

will display as strin%g

My question is are there any other symbols that will give me issue using printf like % does? and if so, how do I handle them?


Thanks so much!

[RonB]

I know that to handle the % that I need to use a %% to make the string evaluate correctly.

That would not work in Perl. Perl uses the backslash to escape special chars.

Why are you using printf without a format specification?

If you don't need to use a format, then use print instead of printf.

If you don't what to interpolate, then use single quotes instead of double quotes.

[sathishkumar88]

This can be useful for you
use strict;
use warnings;
print "strin\%g";