How to add time

[chaitukdr]

suppose string x=10h.10m
string y=10h.10m
how to add x and y by converting them to double.

because on converting x to double like

double a= convert.todoubl e(x)
it gives result 10.1 which represents 10h.1m

how to convert so that I get result as 10h.10m

h*-Hours
m*- Minutes

[Frinavale]

Since you are working with time I recommend that you use the DateTime structure instead of a Double.

The reason is because of how doubles work verses how time values work.

Here's what happens when you add Doubles:
0.6 + 0.1 = 0.7

However, if these were times that you were adding together you should have:
0.6 + 0.1 = 1.0

See the difference?


If you use the DateTime structure instead of a Double then your addition will be correct.

The important thing to know about adding DateTime structures is that:

A calculation using a DateTime structure, such as Add or Subtract, does not modify the value of the structure. Instead, the calculation returns a new DateTime structure whose value is the result of the calculation.

Check out the article I linked you to about the DateTime structure so that you have a good idea of how to use it to achieve what you're looking to do.

-Frinny

[tlhintoq]

It's also easier to start with something closer in format to your need.

suppose string x=10h.10m

Where is this string coming from? Why is it formated at 10h.10m?
Can this be made to be entered as time, such as 10:10 ? Maybe using a MaskedTextBox? If you can use a DateTimePicker that would be ideal because you then are entering in a DateTimeObject and eliminating the conversion process altogether.

If you process the string "10h.10m" into a recognizable time format then you can use DateTimeParse to turn it into a DateTime object. You can replace "h." with ":" and replace "m" with string.empty to create "10:10"