hai i am senthil.i am using visual studio 2005 .i want to open the file open window when i click the browse button.can you please tell me how it is happen?.thank you.
doubts
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You don't specify what language you are working with, but the OpenFileDialog class should do the job for you. Here are some examples:
In VB.NET:
In C#:Code:Private Sub button1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Dim myStream As Stream = Nothing Dim openFileDialog1 As New OpenFileDialog() openFileDialog1.InitialDirectory = "c:\" openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*" openFileDialog1.FilterIndex = 2 openFileDialog1.RestoreDirectory = True If openFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then Try myStream = openFileDialog1.OpenFile() If (myStream IsNot Nothing) Then ' Insert code to read the stream here. End If Catch Ex As Exception MessageBox.Show("Cannot read file from disk. Original error: " & Ex.Message) Finally ' Check this again, since we need to make sure we didn't throw an exception on open. If (myStream IsNot Nothing) Then myStream.Close() End If End Try End If End Sub
Code:private void button1_Click(object sender, System.EventArgs e) { Stream myStream = null; OpenFileDialog openFileDialog1 = new OpenFileDialog(); openFileDialog1.InitialDirectory = "c:\\" ; openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*" ; openFileDialog1.FilterIndex = 2 ; openFileDialog1.RestoreDirectory = true ; if(openFileDialog1.ShowDialog() == DialogResult.OK) { try { if ((myStream = openFileDialog1.OpenFile()) != null) { using (myStream) { // Insert code to read the stream here. } } } catch (Exception ex) { MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message); } } } -
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