Parsing space delimited records

[=?Utf-8?B?TTFpUw==?=]

I’m trying to parse out Amazon S3 server logs which are space delimited.
However date fields are in the following form:

[28/Oct/2008:21:44:21 +0000]

When I try to use the following code to split the record on the spaces it
also splits date field:

string[] fields = record.Split(' ');

What can I do to get around this?

Scott

[Stanimir Stoyanov]

Re: Parsing space delimited records

Hi Scott,

I personally would use Regular Expressions to split the words in a smart
way. Below is a sample console application to demonstrate it. The regular
expression \[.*\]\s*|.+ means that it can select from two alternatives:

a) Text wrapped inside [ and ]
b) Any other text (your actual server log)

using System;
using System.Text.Reg ularExpressions ;

class Program
{
static void Main(string[] args)
{
string expr = @"\[.*\]\s*|.+";
string line = "[28/Oct/2008:21:44:21 +0000] Test with p~nctuat!ion
word goes here!";

Regex regex = new Regex(expr);

foreach (Match m in regex.Matches(l ine))
{
string value = m.Value.Trim();

if (value.StartsWi th("[") && value.EndsWith( "]"))
{
// This is part of the timestamp
Console.WriteLi ne("TEST: time = " + value);
}
else
{
// This is an actual slice of the result
Console.WriteLi ne("TEST: word = " + value);
}
}

Console.Read();
}
}

"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
news:81E4AA72-53B2-482A-8B4B-719C2E2CDFC3@mi crosoft.com...

I’m trying to parse out Amazon S3 server logs which are space delimited.
However date fields are in the following form:
>
[28/Oct/2008:21:44:21 +0000]
>
When I try to use the following code to split the record on the spaces it
also splits date field:
>
string[] fields = record.Split(' ');
>
What can I do to get around this?
>
Scott
>

[=?Utf-8?B?TTFpUw==?=]

Re: Parsing space delimited records

I was hoping to avoid taking the time to create a regular expression as there
are 17 fields per S3 record. It took me a while but here is what I ended up
with:

(.*?)(\s+)(.*?) (\s+)(\[.*?\])(\s+)((?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))(?![\d])(\s+)(.*?)(\s+ )(.*?)(\s+)(.*? )(\s+)(.*)(\s+) (".*?")(\s+)(.* ?)(\s+)(.*?)(\s +)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(".*?")(\ s+)(".*?")

Yuck, I'd rather being doing about a million other things, but oh well
problem solved.



"Stanimir Stoyanov" wrote:

Hi Scott,
>
I personally would use Regular Expressions to split the words in a smart
way. Below is a sample console application to demonstrate it. The regular
expression \[.*\]\s*|.+ means that it can select from two alternatives:
>
a) Text wrapped inside [ and ]
b) Any other text (your actual server log)
>
using System;
using System.Text.Reg ularExpressions ;
>
class Program
{
static void Main(string[] args)
{
string expr = @"\[.*\]\s*|.+";
string line = "[28/Oct/2008:21:44:21 +0000] Test with p~nctuat!ion
word goes here!";
>
Regex regex = new Regex(expr);
>
foreach (Match m in regex.Matches(l ine))
{
string value = m.Value.Trim();
>
if (value.StartsWi th("[") && value.EndsWith( "]"))
{
// This is part of the timestamp
Console.WriteLi ne("TEST: time = " + value);
}
else
{
// This is an actual slice of the result
Console.WriteLi ne("TEST: word = " + value);
}
}
>
Console.Read();
}
}
>
"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
news:81E4AA72-53B2-482A-8B4B-719C2E2CDFC3@mi crosoft.com...

I’m trying to parse out Amazon S3 server logs which are space delimited.
However date fields are in the following form:

[28/Oct/2008:21:44:21 +0000]

When I try to use the following code to split the record on the spaces it
also splits date field:

string[] fields = record.Split(' ');

What can I do to get around this?

Scott

>

[Stanimir Stoyanov]

Re: Parsing space delimited records

I am sure there is *more* elegant solution to the problem, can you post a
sample log output, and do you want to get the individual words out of the
log?

E.g. if the log line is
[28/Oct/2008:21:44:21 +0000] Test with p~nctuat!ion word goes here!
would you like to have the timestamp, "Test", "with", etc as separate
matches? If so, you could split the text using string.Split() once you have
the actual log text (see my previous code example for the 'log text' case).

--
Stanimir Stoyanov
http://stoyanoff.info

"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
news:7144B06E-3E70-4281-A367-0D871786348C@mi crosoft.com...

>I was hoping to avoid taking the time to create a regular expression as
>there
are 17 fields per S3 record. It took me a while but here is what I ended
up
with:
>
(.*?)(\s+)(.*?) (\s+)(\[.*?\])(\s+)((?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))(?![\d])(\s+)(.*?)(\s+ )(.*?)(\s+)(.*? )(\s+)(.*)(\s+) (".*?")(\s+)(.* ?)(\s+)(.*?)(\s +)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(".*?")(\ s+)(".*?")
>
Yuck, I'd rather being doing about a million other things, but oh well
problem solved.
>
>
>
"Stanimir Stoyanov" wrote:
>

>Hi Scott,
>>
>I personally would use Regular Expressions to split the words in a smart
>way. Below is a sample console application to demonstrate it. The regular
>expression \[.*\]\s*|.+ means that it can select from two alternatives:
>>
>a) Text wrapped inside [ and ]
>b) Any other text (your actual server log)
>>
>using System;
>using System.Text.Reg ularExpressions ;
>>
>class Program
>{
> static void Main(string[] args)
> {
> string expr = @"\[.*\]\s*|.+";
> string line = "[28/Oct/2008:21:44:21 +0000] Test with
>p~nctuat!ion
>word goes here!";
>>
> Regex regex = new Regex(expr);
>>
> foreach (Match m in regex.Matches(l ine))
> {
> string value = m.Value.Trim();
>>
> if (value.StartsWi th("[") && value.EndsWith( "]"))
> {
> // This is part of the timestamp
> Console.WriteLi ne("TEST: time = " + value);
> }
> else
> {
> // This is an actual slice of the result
> Console.WriteLi ne("TEST: word = " + value);
> }
> }
>>
> Console.Read();
> }
>}
>>
>"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
>news:81E4AA7 2-53B2-482A-8B4B-719C2E2CDFC3@mi crosoft.com...

I’m trying to parse out Amazon S3 server logs which are space
delimited.
However date fields are in the following form:
>
[28/Oct/2008:21:44:21 +0000]
>
When I try to use the following code to split the record on the spaces
it
also splits date field:
>
string[] fields = record.Split(' ');
>
What can I do to get around this?
>
Scott
>

>>

[Mark S. Milley]

Re: Parsing space delimited records

Unless you're somehow married to the format, just drop the time zone:

string[] fields = record.Replace( ' +0000','',Split (' ');


"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
news:81E4AA72-53B2-482A-8B4B-719C2E2CDFC3@mi crosoft.com...

I’m trying to parse out Amazon S3 server logs which are space delimited.
However date fields are in the following form:
>
[28/Oct/2008:21:44:21 +0000]
>
When I try to use the following code to split the record on the spaces it
also splits date field:
>
string[] fields = record.Split(' ');
>
What can I do to get around this?
>
Scott
>

[Mark S. Milley]

Re: Parsing space delimited records

Er, make that:

string[] fields = record.Replace( ' +0000','').Spli t(' ');

"Mark S. Milley" <mark.milley@bi naryswitch.comw rote in message
news:90C93CA7-2648-47D5-958E-A1A2E9B89E18@mi crosoft.com...

Unless you're somehow married to the format, just drop the time zone:
>
string[] fields = record.Replace( ' +0000','',Split (' ');
>
>
"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
news:81E4AA72-53B2-482A-8B4B-719C2E2CDFC3@mi crosoft.com...

>I’m trying to parse out Amazon S3 server logs which are space delimited.
>However date fields are in the following form:
>>
>[28/Oct/2008:21:44:21 +0000]
>>
>When I try to use the following code to split the record on the spaces it
>also splits date field:
>>
>string[] fields = record.Split(' ');
>>
>What can I do to get around this?
>>
>Scott
>>

>

[Jesse Houwing]

Re: Parsing space delimited records

Hello Stanimir,

If you do a Regex.Match with the following regex:

^((\[(?<result>[^\]]*)\]|(?<result>[^ ]*))([ ]|$)*

Should get you a Match object with 1 named group and 17 captures in there.
Exactly what you need...

You should also be able to use the Log parser class that the IIS team once
published... but I cannot find a link at the moment...

Jesse

I am sure there is *more* elegant solution to the problem, can you
post a sample log output, and do you want to get the individual words
out of the log?
>
E.g. if the log line is
[28/Oct/2008:21:44:21 +0000] Test with p~nctuat!ion word goes here!
would you like to have the timestamp, "Test", "with", etc as separate
matches? If so, you could split the text using string.Split() once you
have
the actual log text (see my previous code example for the 'log text'
case).
--
Stanimir Stoyanov
http://stoyanoff.info
"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
news:7144B06E-3E70-4281-A367-0D871786348C@mi crosoft.com...
>

>I was hoping to avoid taking the time to create a regular expression
>as
>there
>are 17 fields per S3 record. It took me a while but here is what I
>ended
>up
>with:
>(.*?)(\s+)(.*? )(\s+)(\[.*?\])(\s+)((?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-
>9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))(?![\d])(\s+)
>(.*?)(\s+)(.*? )(\s+)(.*?)(\s+ )(.*)(\s+)(".*? ")(\s+)(.*?)(\s +)(.*?)(\s
>+)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(".*?")(\ s+)(".*?")
>>
>Yuck, I'd rather being doing about a million other things, but oh
>well problem solved.
>>
>"Stanimir Stoyanov" wrote:
>>

>>Hi Scott,
>>>
>>I personally would use Regular Expressions to split the words in a
>>smart way. Below is a sample console application to demonstrate it.
>>The regular expression \[.*\]\s*|.+ means that it can select from
>>two alternatives:
>>>
>>a) Text wrapped inside [ and ]
>>b) Any other text (your actual server log)
>>using System;
>>using System.Text.Reg ularExpressions ;
>>class Program
>>{
>>static void Main(string[] args)
>>{
>>string expr = @"\[.*\]\s*|.+";
>>string line = "[28/Oct/2008:21:44:21 +0000] Test with
>>p~nctuat!io n
>>word goes here!";
>>Regex regex = new Regex(expr);
>>>
>>foreach (Match m in regex.Matches(l ine))
>>{
>>string value = m.Value.Trim();
>>if (value.StartsWi th("[") && value.EndsWith( "]"))
>>{
>>// This is part of the timestamp
>>Console.Write Line("TEST: time = " + value);
>>}
>>else
>>{
>>// This is an actual slice of the result
>>Console.Write Line("TEST: word = " + value);
>>}
>>}
>>Console.Read( );
>>}
>>}
>>"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
>>news:81E4AA 72-53B2-482A-8B4B-719C2E2CDFC3@mi crosoft.com...
>>>
>>>I’m trying to parse out Amazon S3 server logs which are space
>>>delimited.
>>>However date fields are in the following form:
>>>[28/Oct/2008:21:44:21 +0000]
>>>>
>>>When I try to use the following code to split the record on the
>>>spaces
>>>it
>>>also splits date field:
>>>string[] fields = record.Split(' ');
>>>>
>>>What can I do to get around this?
>>>>
>>>Scott
>>>>

--
Jesse Houwing
jesse.houwing at sogeti.nl

[=?Utf-8?B?TTFpUw==?=]

Re: Parsing space delimited records

Below is an example of what is in a log file. I'm just trying to read the
logs and dump the fields into a database.

4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:44:21 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
AAE9C2CCFFE5E6D B REST.GET.ACL - "GET /?acl HTTP/1.1" 200 - 556 - 488 - "-" "-"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:44:24 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
66FB31B05AFA84E 9 REST.GET.LOGGIN G_STATUS - "GET /?logging HTTP/1.1" 200 - 244
- 171 - "-" "-"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:44:56 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
40AC4747CFF7ACF D REST.GET.BUCKET - "GET / HTTP/1.1" 200 - 1298 - 15 12 "-"
"Amazon S3 CSharp Library"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:44:56 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
5938B6855868E04 0 REST.HEAD.BUCKE T - "HEAD / HTTP/1.1" 200 - 1298 - 642 473
"-" "Amazon S3 CSharp Library"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:45:33 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
16F565F75362B5A 8 REST.HEAD.BUCKE T - "HEAD / HTTP/1.1" 200 - 1298 - 508 293
"-" "Amazon S3 CSharp Library"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:45:33 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
D61C9201C46617C F REST.PUT.OBJECT testFile.zip "PUT /testFile.zip HTTP/1.1"
200 - - 17428 334 11 "-" "Amazon S3 CSharp Library"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:45:34 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
B2FEB30917A1F05 0 REST.GET.BUCKET - "GET / HTTP/1.1" 200 - 1634 - 181 15 "-"
"Amazon S3 CSharp Library"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:45:34 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
B41FCF38CD59056 2 REST.HEAD.BUCKE T - "HEAD / HTTP/1.1" 200 - 1634 - 15 13 "-"
"Amazon S3 CSharp Library"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:46:11 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
C42BF5C887E61F1 8 REST.HEAD.BUCKE T - "HEAD / HTTP/1.1" 200 - 1634 - 476 299
"-" "Amazon S3 CSharp Library"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:46:12 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
A590228971F1608 1 REST.PUT.OBJECT testFile.zip "PUT /testFile.zip HTTP/1.1"
200 - - 1487163 20298 48 "-" "Amazon S3 CSharp Library"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:46:32 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
6528418F2CCABB5 9 REST.HEAD.BUCKE T - "HEAD / HTTP/1.1" 200 - 1969 - 312 309
"-" "Amazon S3 CSharp Library"
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887 testBucket
[28/Oct/2008:21:46:33 +0000] 127.0.0.1
4c54d3704f3a825 92af823f518a644 3186e92168fe07c dcdb20cfc2a2165 5887
EE65B98BD633E32 C REST.GET.BUCKET - "GET / HTTP/1.1" 200 - 1969 - 16 14 "-"
"Amazon S3 CSharp Library"


"Stanimir Stoyanov" wrote:

I am sure there is *more* elegant solution to the problem, can you post a
sample log output, and do you want to get the individual words out of the
log?
>
E.g. if the log line is
[28/Oct/2008:21:44:21 +0000] Test with p~nctuat!ion word goes here!
would you like to have the timestamp, "Test", "with", etc as separate
matches? If so, you could split the text using string.Split() once you have
the actual log text (see my previous code example for the 'log text' case).
>
--
Stanimir Stoyanov
http://stoyanoff.info
>
"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
news:7144B06E-3E70-4281-A367-0D871786348C@mi crosoft.com...

I was hoping to avoid taking the time to create a regular expression as
there
are 17 fields per S3 record. It took me a while but here is what I ended
up
with:

(.*?)(\s+)(.*?) (\s+)(\[.*?\])(\s+)((?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))(?![\d])(\s+)(.*?)(\s+ )(.*?)(\s+)(.*? )(\s+)(.*)(\s+) (".*?")(\s+)(.* ?)(\s+)(.*?)(\s +)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(".*?")(\ s+)(".*?")

Yuck, I'd rather being doing about a million other things, but oh well
problem solved.



"Stanimir Stoyanov" wrote:

Hi Scott,
>
I personally would use Regular Expressions to split the words in a smart
way. Below is a sample console application to demonstrate it. The regular
expression \[.*\]\s*|.+ means that it can select from two alternatives:
>
a) Text wrapped inside [ and ]
b) Any other text (your actual server log)
>
using System;
using System.Text.Reg ularExpressions ;
>
class Program
{
static void Main(string[] args)
{
string expr = @"\[.*\]\s*|.+";
string line = "[28/Oct/2008:21:44:21 +0000] Test with
p~nctuat!ion
word goes here!";
>
Regex regex = new Regex(expr);
>
foreach (Match m in regex.Matches(l ine))
{
string value = m.Value.Trim();
>
if (value.StartsWi th("[") && value.EndsWith( "]"))
{
// This is part of the timestamp
Console.WriteLi ne("TEST: time = " + value);
}
else
{
// This is an actual slice of the result
Console.WriteLi ne("TEST: word = " + value);
}
}
>
Console.Read();
}
}
>
"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
news:81E4AA72-53B2-482A-8B4B-719C2E2CDFC3@mi crosoft.com...
I’m trying to parse out Amazon S3 server logs which are space
delimited.
However date fields are in the following form:

[28/Oct/2008:21:44:21 +0000]

When I try to use the following code to split the record on the spaces
it
also splits date field:

string[] fields = record.Split(' ');

What can I do to get around this?

Scott

>

>

[Stanimir Stoyanov]

Re: Parsing space delimited records

One of the following regular expressions might fit better:

\[.*\]|\"[^\"]*\"|[^\s-]+

or

\[.*\]|\"[^\"]*\"|[^\s]+

The difference is that the first omits single dashes as found on some rows
(in between figures), e.g.
200 - 1634 - 181 15

--
Stanimir Stoyanov
http://stoyanoff.info

"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
news:D14E31DB-E0C8-44C2-AAE2-F51EEB9778B5@mi crosoft.com...

Below is an example of what is in a log file. I'm just trying to read the
logs and dump the fields into a database.
>
<SNIPPED>
>
"Stanimir Stoyanov" wrote:
>

>I am sure there is *more* elegant solution to the problem, can you post a
>sample log output, and do you want to get the individual words out of the
>log?
>>
>E.g. if the log line is
>[28/Oct/2008:21:44:21 +0000] Test with p~nctuat!ion word goes here!
>would you like to have the timestamp, "Test", "with", etc as separate
>matches? If so, you could split the text using string.Split() once you
>have
>the actual log text (see my previous code example for the 'log text'
>case).
>>
>--
>Stanimir Stoyanov
>http://stoyanoff.info
>>
>"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
>news:7144B06 E-3E70-4281-A367-0D871786348C@mi crosoft.com...

>I was hoping to avoid taking the time to create a regular expression as
>there
are 17 fields per S3 record. It took me a while but here is what I
ended
up
with:
>
(.*?)(\s+)(.*?) (\s+)(\[.*?\])(\s+)((?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))(?![\d])(\s+)(.*?)(\s+ )(.*?)(\s+)(.*? )(\s+)(.*)(\s+) (".*?")(\s+)(.* ?)(\s+)(.*?)(\s +)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(\d+|-)(\s+)(".*?")(\ s+)(".*?")
>
Yuck, I'd rather being doing about a million other things, but oh well
problem solved.
>
>
>
"Stanimir Stoyanov" wrote:
>
>Hi Scott,
>>
>I personally would use Regular Expressions to split the words in a
>smart
>way. Below is a sample console application to demonstrate it. The
>regular
>expression \[.*\]\s*|.+ means that it can select from two
>alternatives :
>>
>a) Text wrapped inside [ and ]
>b) Any other text (your actual server log)
>>
>using System;
>using System.Text.Reg ularExpressions ;
>>
>class Program
>{
> static void Main(string[] args)
> {
> string expr = @"\[.*\]\s*|.+";
> string line = "[28/Oct/2008:21:44:21 +0000] Test with
>p~nctuat!ion
>word goes here!";
>>
> Regex regex = new Regex(expr);
>>
> foreach (Match m in regex.Matches(l ine))
> {
> string value = m.Value.Trim();
>>
> if (value.StartsWi th("[") && value.EndsWith( "]"))
> {
> // This is part of the timestamp
> Console.WriteLi ne("TEST: time = " + value);
> }
> else
> {
> // This is an actual slice of the result
> Console.WriteLi ne("TEST: word = " + value);
> }
> }
>>
> Console.Read();
> }
>}
>>
>"M1iS" <M1iS@discussio ns.microsoft.co mwrote in message
>news:81E4AA7 2-53B2-482A-8B4B-719C2E2CDFC3@mi crosoft.com...
I’m trying to parse out Amazon S3 server logs which are space
delimited.
However date fields are in the following form:
>
[28/Oct/2008:21:44:21 +0000]
>
When I try to use the following code to split the record on the
spaces
it
also splits date field:
>
string[] fields = record.Split(' ');
>
What can I do to get around this?
>
Scott
>
>>

>>