[XSL] Obtaining an attribute from self or ancestor

[Ebenezer]

Hello!

Let's suppose we have an XML with some nested NODE nodes:

<root attr="first">
<node id="1" attr="mike">
<node id="2" />
<node id="3" attr="dave" />
</node>
<node id="4">
<node id="5" attr="peter" />
</node>
</root>

What I want to achieve is to have an XSL that:
- takes a $id variable externally from a PHP script
- finds the node with @id=$id
- outputs the value "@attr" attribute IF PRESENT, otherwise the parent's
"@attr" attribute IF PRESENT, otherwise the grandparent's.. . recursively
traversing from parent to parent, until an @attr value is found

This won't work for some nodes:

<?xml version="1.0"?>
<xsl:styleshe et version="1.0">
<xsl:output method="html" />
<xsl:template match="root">
<xsl:apply-templates select="//node[@id=$id]" />
</xsl:template>
<xsl:template match="node">
<xsl:choose>
<xsl:when test="not(@attr )"><xsl:appl y-templates ".." /></xsl:when>
<xsl:otherwise> <xsl:value-of select="@attr" /></xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>

[Martin Honnen]

Re: [XSL] Obtaining an attribute from self or ancestor

Ebenezer wrote:

What I want to achieve is to have an XSL that:
- takes a $id variable externally from a PHP script
- finds the node with @id=$id
- outputs the value "@attr" attribute IF PRESENT, otherwise the parent's
"@attr" attribute IF PRESENT, otherwise the grandparent's.. . recursively
traversing from parent to parent, until an @attr value is found
>
This won't work for some nodes:
>
<?xml version="1.0"?>
<xsl:styleshe et version="1.0">
<xsl:output method="html" />

You need to define the id parameter
<xsl:param name="id"/>

<xsl:template match="root">
<xsl:apply-templates select="//node[@id=$id]" />
</xsl:template>
<xsl:template match="node">
<xsl:choose>
<xsl:when test="not(@attr )"><xsl:appl y-templates ".."
/></xsl:when>

That is not the correct syntax, you need
<xsl:apply-templates select=".."/>
Also it is not clear what you want to do if you do not find a 'node'
ancestor element with an 'attr' attribute.
If you walk up to the 'root element then the template matching that will
lead to infinite recursion. So perhaps you should better use
<xsl:apply-templates select="parent: :node"/>
Or if you want to walk up to the 'root' element as well you need a mode e.g.
<xsl:apply-templates select=".." mode="attribute-check"/>

and then you need to add that mode parameter to the template e.g.


<xsl:template match="root">
<xsl:apply-templates select="//node[@id=$id]"
mode="attribute-check" />
</xsl:template>
<xsl:template match="node | root" mode="attribute-check">
<xsl:choose>
<xsl:when test="not(@attr )"><xsl:appl y-templates
select="parent: :*" /></xsl:when>
<xsl:otherwise> <xsl:value-of select="@attr" /></xsl:otherwise>
</xsl:choose>
</xsl:template>




--

Martin Honnen
http://JavaScript.FAQTs.com/

[Ebenezer]

Re: [XSL] Obtaining an attribute from self or ancestor

Martin Honnen ha scritto:

Ebenezer wrote:
>

>What I want to achieve is to have an XSL that:
>- takes a $id variable externally from a PHP script
>- finds the node with @id=$id
>- outputs the value "@attr" attribute IF PRESENT, otherwise the
>parent's "@attr" attribute IF PRESENT, otherwise the grandparent's.. .
>recursively traversing from parent to parent, until an @attr value is
>found
>>
>This won't work for some nodes:
>>
><?xml version="1.0"?>
><xsl:styleshee t version="1.0">
> <xsl:output method="html" />

>
You need to define the id parameter
<xsl:param name="id"/>

Are you sure? I don't know if it's a standard behaviour, but other
stylesheet's I've made take the parameters with no effort or definition...

That is not the correct syntax, you need
<xsl:apply-templates select=".."/>

Sorry, that was my mistake in pasting the code, it's with "select" indeed...

Also it is not clear what you want to do if you do not find a 'node'
ancestor element with an 'attr' attribute.
If you walk up to the 'root element then the template matching that will
lead to infinite recursion. So perhaps you should better use
<xsl:apply-templates select="parent: :node"/>

Yes! There was an infinite recursion indeed but I didn't find a clue on
it...

Or if you want to walk up to the 'root' element as well you need a mode
e.g.
<xsl:apply-templates select=".." mode="attribute-check"/>
>
and then you need to add that mode parameter to the template e.g.

This info was really valuable. Thanks a lot and excuse me for the multipost.

[Pavel Lepin]

Re: [XSL] Obtaining an attribute from self or ancestor


Ebenezer <vaciapairat@sp am.comwrote in
<bRgLk.86409$Ca .20678@twister2 .libero.it>:

<root attr="first">
<node id="1" attr="mike">
<node id="2" />
<node id="3" attr="dave" />
</node>
<node id="4">
<node id="5" attr="peter" />
</node>
</root>
>
What I want to achieve is to have an XSL that:
- takes a $id variable externally from a PHP script
- finds the node with @id=$id
- outputs the value "@attr" attribute IF PRESENT,
otherwise the parent's "@attr" attribute IF PRESENT,
otherwise the grandparent's.. . recursively traversing from
parent to parent, until an @attr value is found

<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:param name="id"/>
<xsl:template match="/">
<xsl:value-of select=
"(//node[@id=$id]/ancestor-or-self::*/@attr)[last()]"
/>
</xsl:template>
</xsl:stylesheet>

HTH, HAND.

--
If we want the average quality of computer programs to rise
by 1000%, all we have to do is carefully to select 90% of
the world's programmers, and shoot them. --Richard
Heathfield in <Sfedncgr46kOPm DanZ2dnUVZ8vCdn Z2d@bt.com>

[Dimitre Novatchev]

Re: [XSL] Obtaining an attribute from self or ancestor

Actually, this can be achieved with a single XPath one-liner (even without
XSLT being involved).

Use:

//node[@id = $id]/ancestor-or-self::*[@attr][1]/@attr


Cheers,
Dimitre Novatchev


"Ebenezer" <vaciapairat@sp am.comwrote in message
news:bRgLk.8640 9$Ca.20678@twis ter2.libero.it. ..

Hello!
>
Let's suppose we have an XML with some nested NODE nodes:
>
<root attr="first">
<node id="1" attr="mike">
<node id="2" />
<node id="3" attr="dave" />
</node>
<node id="4">
<node id="5" attr="peter" />
</node>
</root>
>
What I want to achieve is to have an XSL that:
- takes a $id variable externally from a PHP script
- finds the node with @id=$id
- outputs the value "@attr" attribute IF PRESENT, otherwise the parent's
"@attr" attribute IF PRESENT, otherwise the grandparent's.. . recursively
traversing from parent to parent, until an @attr value is found
>
This won't work for some nodes:
>
<?xml version="1.0"?>
<xsl:styleshe et version="1.0">
<xsl:output method="html" />
<xsl:template match="root">
<xsl:apply-templates select="//node[@id=$id]" />
</xsl:template>
<xsl:template match="node">
<xsl:choose>
<xsl:when test="not(@attr )"><xsl:appl y-templates ".." /></xsl:when>
<xsl:otherwise> <xsl:value-of select="@attr" /></xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>

[Richard Tobin]

Re: [XSL] Obtaining an attribute from self or ancestor

In article <490139f9$0$170 67$6e1ede2f@rea d.cnntp.org>,
Dimitre Novatchev <dnovatchev@cnn tp.orgwrote:

>Actually, this can be achieved with a single XPath one-liner (even without
>XSLT being involved).
>
>Use:
>
//node[@id = $id]/ancestor-or-self::*[@attr][1]/@attr

Or, if you find it clearer not to repeat @attr:

(//node[@id = $id]/ancestor-or-self::*/@attr)[last()]

-- Richard
--
Please remember to mention me / in tapes you leave behind.

[Dimitre Novatchev]

Re: [XSL] Obtaining an attribute from self or ancestor


"Richard Tobin" <richard@cogsci .ed.ac.ukwrote in message
news:gdsk17$2hb q$1@pc-news.cogsci.ed. ac.uk...

In article <490139f9$0$170 67$6e1ede2f@rea d.cnntp.org>,
Dimitre Novatchev <dnovatchev@cnn tp.orgwrote:
>

>>Actually, this can be achieved with a single XPath one-liner (even without
>>XSLT being involved).
>>
>>Use:
>>
> //node[@id = $id]/ancestor-or-self::*[@attr][1]/@attr

>
Or, if you find it clearer not to repeat @attr:
>
(//node[@id = $id]/ancestor-or-self::*/@attr)[last()]
>

This may be "clearer" but risks to be less efficient.

Using [1] in a reverse axis is a strong optimization hint and a clever XPath
engine will not traverse the whole way up -- it wil just stop on the first
self-or-ancestor element found that has an "attr" attribute.

Cheers,
Dimitre Novatchev

[Richard Tobin]

Re: [XSL] Obtaining an attribute from self or ancestor

In article <490386ab$0$170 66$6e1ede2f@rea d.cnntp.org>,
Dimitre Novatchev <dnovatchev@cnn tp.orgwrote:

> (//node[@id = $id]/ancestor-or-self::*/@attr)[last()]

>This may be "clearer" but risks to be less efficient.
>
>Using [1] in a reverse axis is a strong optimization hint and a clever XPath
>engine will not traverse the whole way up -- it wil just stop on the first
>self-or-ancestor element found that has an "attr" attribute.

True, but unlikely to be significant when the axis is ancestor-or-self,
because XML documents tend to be much shallower than they are wide.
For preceding-sibling it would be much more likely to make a difference.

-- Richard
--
Please remember to mention me / in tapes you leave behind.