Image Column in Windows Application

[krishnaneeraja]

Hi,
Iam working on windows based application.In that i dont know how to add image in grid view column. I want to add image column in grid view.Image path will be stored in Ms-Access database.I want to retrieve path from database and place image in gridview column.

Please help me.

Thanks & Regards
Neeraja.

[Prathap]

Here i've used picturebox.

Imports System.Data.SqlClient
Imports System.Data
Imports System.IO
 
 Public Class Form1
    Dim str As String = "Data Source=NET3\SQLEXPRESS;Initial Catalog=RestPos;Persist Security Info=True;User ID=sa;Password=password"
    Dim con As New SqlClient.SqlConnection

    'To open an image from computer
    '-------------------------------
    Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
        OpenFileDialog1.Title = "Please select a file"
        OpenFileDialog1.InitialDirectory = "c:temp"
        OpenFileDialog1.ShowDialog()
        TextBox2.Text = OpenFileDialog1.FileName.ToString  '--->To Show the file path in textbox2
        PictureBox1.ImageLocation = TextBox2.Text  '--->To show selected image in picturebox
    End sub
   
   'To insert selected image into database
   'The datatype of the column in table to store image should be <image>  
   '--------------------------------------------------------------------
    Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click
        con.ConnectionString = str
        Dim ms As New IO.MemoryStream()
        PictureBox1.Image.Save(ms, PictureBox1.Image.RawFormat)
        Dim arrimage() As Byte = ms.GetBuffer
        Dim cmd As New SqlCommand("insert into image (Emp_Image)values(@picture)", con)
        cmd.Parameters.Add(New SqlParameter("@Picture", SqlDbType.Image)).Value = arrimage
        con.Open()
        cmd.ExecuteNonQuery()
        con.Close()
    End Sub
    
    'We have successfully inserted the image into database.
    'Now we want to Retrieve the image from database.
    '-------------------------------------------------
    Private Sub Button4_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button4.Click
        Dim stream As New IO.MemoryStream()
        con.Open()
        Dim command As New SqlCommand("select Emp_Image from Image where Emp_Id='" + TextBox3.Text + "'", con) '--->You can give Emp_id instead of Textbox value.
        Dim image As Byte() = DirectCast(command.ExecuteScalar(), Byte())
        stream.Write(image, 0, image.Length)
        con.Close()
        Dim bitmap As New Bitmap(stream)
        PictureBox2.Image = bitmap '--->I have used another picturebox to display image from database.
    End Sub
    'Thats all, You can place a linklabel below the picturebox if you to change photo and update it in database.

Regards,
Prathap