adding a day to time_t

[Abubakar]

Hi,
Lets say I have three integers (date, month, and year) as part of a struct
lets say like
struct mydate{ int day, month, year};
I want to add x number of days to this date. And it should be a real date
calculation thing. Like if the date is 31st december 2008, when i add 1 to
this, it should become 1st feb 2009.
This of course may require converting the above struct values to some data
type that crt's date functons can understand. I want to do that but havent
been able to yet. Thanks for help.
I'm using visual c++ 2k5.
Regards,

...ab

[Doug Harrison [MVP]]

Re: adding a day to time_t

On Mon, 19 May 2008 09:57:01 +0500, "Abubakar" <q@y.comwrote :

>Hi,
>Lets say I have three integers (date, month, and year) as part of a struct
>lets say like
>struct mydate{ int day, month, year};
>I want to add x number of days to this date. And it should be a real date
>calculation thing. Like if the date is 31st december 2008, when i add 1 to
>this, it should become 1st feb 2009.
>This of course may require converting the above struct values to some data
>type that crt's date functons can understand. I want to do that but havent
>been able to yet. Thanks for help.

The mktime function takes a broken-down local time value represented as a
struct tm, normalizes the struct fields, and returns a time_t.

--
Doug Harrison
Visual C++ MVP

[Abubakar]

Re: adding a day to time_t

yes but how can it help me add days to my own specified date ?

...ab

"Doug Harrison [MVP]" <dsh@mvps.orgwr ote in message
news:c73234hvl8 o5m5bru76onif2k 3fb8ddi93@4ax.c om...

On Mon, 19 May 2008 09:57:01 +0500, "Abubakar" <q@y.comwrote :
>

>>Hi,
>>Lets say I have three integers (date, month, and year) as part of a struct
>>lets say like
>>struct mydate{ int day, month, year};
>>I want to add x number of days to this date. And it should be a real date
>>calculation thing. Like if the date is 31st december 2008, when i add 1 to
>>this, it should become 1st feb 2009.
>>This of course may require converting the above struct values to some data
>>type that crt's date functons can understand. I want to do that but havent
>>been able to yet. Thanks for help.

>
The mktime function takes a broken-down local time value represented as a
struct tm, normalizes the struct fields, and returns a time_t.
>
--
Doug Harrison
Visual C++ MVP

[Doug Harrison [MVP]]

Re: adding a day to time_t

On Mon, 19 May 2008 10:56:16 +0500, "Abubakar" <q@y.comwrote :

>The mktime function takes a broken-down local time value represented as a
>struct tm, normalizes the struct fields, and returns a time_t.

>
>yes but how can it help me add days to my own specified date ?

For example, add x number of days to the tm_mday field before calling
mktime. Although your thread subject mentions time_t, your original post
talked about a broken down time in your own format, which you can easily
express as a struct tm for use with mktime. If you actually have time_t
values, you can convert them to struct tm with localtime or gmtime.

--
Doug Harrison
Visual C++ MVP

[David Wilkinson]

Re: adding a day to time_t

Abubakar wrote:

Hi,
Lets say I have three integers (date, month, and year) as part of a struct
lets say like
struct mydate{ int day, month, year};
I want to add x number of days to this date. And it should be a real date
calculation thing. Like if the date is 31st december 2008, when i add 1 to
this, it should become 1st feb 2009.
This of course may require converting the above struct values to some data
type that crt's date functons can understand. I want to do that but havent
been able to yet. Thanks for help.
I'm using visual c++ 2k5.
Regards,

ab:

time_t measures time in seconds, so to add a day you add 86400.

--
David Wilkinson
Visual C++ MVP

[Abubakar]

Re: adding a day to time_t

I have written something like:

void AddDate (int day, int month, int year, int daystoadd)
{
tm mt;
mt.tm_sec = 1;
mt.tm_min = 1;
mt.tm_hour = 1;
mt.tm_wday = day;
mt.tm_mon = month - 1;
mt.tm_year = year - 1900;
mt.tm_mday = day;

time_t tmptime = mktime (&mt);
tm * srctime = localtime (&tmptime);

char buf[100];
strftime (buf, 100, "%d/%m/%Y", srctime);
printf("%s + %d = ", buf, daystoadd);
// add days ...
srctime->tm_mday += daystoadd;
time_t finaldate = mktime (srctime);

strftime (buf, 100, "%d/%m/%Y", localtime (&finaldate)) ;
printf("%s", buf);

}

If there are any problems with the code please let me know.

Regards,

...ab

"Doug Harrison [MVP]" <dsh@mvps.orgwr ote in message
news:or52349k4p f81rso7okogomeu io3bnf3nc@4ax.c om...

On Mon, 19 May 2008 10:56:16 +0500, "Abubakar" <q@y.comwrote :
>

>>The mktime function takes a broken-down local time value represented as
>>a
>>struct tm, normalizes the struct fields, and returns a time_t.

>>
>>yes but how can it help me add days to my own specified date ?

>
For example, add x number of days to the tm_mday field before calling
mktime. Although your thread subject mentions time_t, your original post
talked about a broken down time in your own format, which you can easily
express as a struct tm for use with mktime. If you actually have time_t
values, you can convert them to struct tm with localtime or gmtime.
>
--
Doug Harrison
Visual C++ MVP

[Doug Harrison [MVP]]

Re: adding a day to time_t

On Tue, 20 May 2008 19:34:39 +0500, "Abubakar" <q@y.comwrote :

>I have written something like:
>
>void AddDate (int day, int month, int year, int daystoadd)
>{
tm mt;
mt.tm_sec = 1;
mt.tm_min = 1;
mt.tm_hour = 1;
mt.tm_wday = day;
mt.tm_mon = month - 1;
mt.tm_year = year - 1900;
mt.tm_mday = day;
>
time_t tmptime = mktime (&mt);
tm * srctime = localtime (&tmptime);
>
char buf[100];
strftime (buf, 100, "%d/%m/%Y", srctime);
printf("%s + %d = ", buf, daystoadd);
// add days ...
srctime->tm_mday += daystoadd;
time_t finaldate = mktime (srctime);
>
strftime (buf, 100, "%d/%m/%Y", localtime (&finaldate)) ;
printf("%s", buf);
>
>}
>
>If there are any problems with the code please let me know.

There's no point in setting tm_wday, because mktime calculates its value
from the other fields and overwrites it. Also, you need to set tm_isdst to
one of the values documented as meaningful for it.

--
Doug Harrison
Visual C++ MVP

[Abubakar]

Re: adding a day to time_t

Ok cool. Thanks for the help.

...ab

There's no point in setting tm_wday, because mktime calculates its value
from the other fields and overwrites it. Also, you need to set tm_isdst to
one of the values documented as meaningful for it.
>
--
Doug Harrison
Visual C++ MVP

[Ben Voigt [C++ MVP]]

Re: adding a day to time_t

Abubakar wrote:

I have written something like:
>
void AddDate (int day, int month, int year, int daystoadd)
{
tm mt;
mt.tm_sec = 1;
mt.tm_min = 1;
mt.tm_hour = 1;
mt.tm_wday = day;
mt.tm_mon = month - 1;
mt.tm_year = year - 1900;
mt.tm_mday = day;
>
time_t tmptime = mktime (&mt);

So now you have a time_t. If you aren't worried about leap seconds, then
just add 24*60*60 to the time_t (which is measured in seconds) for each day.

tm * srctime = localtime (&tmptime);
>
char buf[100];
strftime (buf, 100, "%d/%m/%Y", srctime);
printf("%s + %d = ", buf, daystoadd);
// add days ...
srctime->tm_mday += daystoadd;
time_t finaldate = mktime (srctime);
>
strftime (buf, 100, "%d/%m/%Y", localtime (&finaldate)) ;
printf("%s", buf);
>
}
>
If there are any problems with the code please let me know.
>
Regards,
>
..ab
>
"Doug Harrison [MVP]" <dsh@mvps.orgwr ote in message
news:or52349k4p f81rso7okogomeu io3bnf3nc@4ax.c om...

>On Mon, 19 May 2008 10:56:16 +0500, "Abubakar" <q@y.comwrote :
>>

>>>The mktime function takes a broken-down local time value
>>>represente d as a
>>>struct tm, normalizes the struct fields, and returns a time_t.
>>>
>>yes but how can it help me add days to my own specified date ?

>>
>For example, add x number of days to the tm_mday field before calling
>mktime. Although your thread subject mentions time_t, your original
>post talked about a broken down time in your own format, which you
>can easily express as a struct tm for use with mktime. If you
>actually have time_t values, you can convert them to struct tm with
>localtime or gmtime. --
>Doug Harrison
>Visual C++ MVP