printing XML file with XSLT code

[Stu]

Being a newbie with XSLT transformation code please excuse my neivte.
In addition, I am not sure what I want to do can be done with xslt so
I apologize up front for asking anything stupid

I have a shell script that needs to get values from an XML file. What
I want to do is transform the XML into something more KSH friendly so
it can be easy to parsed in my KSH script.

I would like to go through an entire XML document and for every
"element" and "element/attribute" print the associated value in NVP
(name value pair).

Assume the following XML file:

<?xml version="1.0" encoding="UTF-8"?>
<abc>
<def>
<mno>2008-06-11-13:15:59</mno>
<pqr stu="World">Hel lo</pqr>
</def>
<ghi>
<jkl vwx="12345678" </jkl>
</ghi>
</abc>

Below is my desired out. As you can see for each element I print
"element=va lue" and for each attribute within an element I print
"element_attrib ute=value"

mno=2008-06-11-13:15:59
pqr=Hello
pqr_stu=World
jkl_vwx=1234567 8

Can somebody point me in the right direction or provide me with some
sample XSLT transformation code that can do this.

Keep in mind, I would like to keep this as generic as possible. That
is I don't want to reference element or attributes by names. I would
like something like this

for each element
do
if attribute
print element_attribu te=value
else
print element=value
done

As oppose to say search element "pqr" and print value

Thanks to all who answer

[=?ISO-8859-1?Q?J=FCrgen_Kahrs?=]

Re: printing XML file with XSLT code

Stu wrote:

Assume the following XML file:
>
<?xml version="1.0" encoding="UTF-8"?>
<abc>
<def>
<mno>2008-06-11-13:15:59</mno>
<pqr stu="World">Hel lo</pqr>
</def>
<ghi>
<jkl vwx="12345678" </jkl>
</ghi>
</abc>
>
Below is my desired out. As you can see for each element I print
"element=va lue" and for each attribute within an element I print
"element_attrib ute=value"
>
mno=2008-06-11-13:15:59
pqr=Hello
pqr_stu=World
jkl_vwx=1234567 8

The following script in XMLgawk does it:

@load xml
XMLCHARDATA { data = $0 }
XMLSTARTELEM { for (i in XMLATTR) print XMLSTARTELEM "_" i "=" XMLATTR[i] }
XMLENDELEM && data ~ /[:alnum:]/ { print XMLENDELEM "=" data }

It produces the output you wanted (except for a change in sequence).

Can somebody point me in the right direction or provide me with some
sample XSLT transformation code that can do this.
>
Keep in mind, I would like to keep this as generic as possible. That
is I don't want to reference element or attributes by names.

The solution above _is_ generic in the sense you described.
Follow this link to the XMLgawk doc:

http://home.vrweb.de/~juergen.kahrs/gawk/XML/xmlgawk.html

[Peter Flynn]

Re: printing XML file with XSLT code

Stu wrote:

Being a newbie with XSLT transformation code please excuse my neivte.
In addition, I am not sure what I want to do can be done with xslt so
I apologize up front for asking anything stupid
>
I have a shell script that needs to get values from an XML file. What
I want to do is transform the XML into something more KSH friendly so
it can be easy to parsed in my KSH script.
>
I would like to go through an entire XML document and for every
"element" and "element/attribute" print the associated value in NVP
(name value pair).
>
Assume the following XML file:
>
<?xml version="1.0" encoding="UTF-8"?>
<abc>
<def>
<mno>2008-06-11-13:15:59</mno>
<pqr stu="World">Hel lo</pqr>
</def>
<ghi>
<jkl vwx="12345678" </jkl>
</ghi>
</abc>
>
Below is my desired out. As you can see for each element I print
"element=va lue" and for each attribute within an element I print
"element_attrib ute=value"
>
mno=2008-06-11-13:15:59
pqr=Hello
pqr_stu=World
jkl_vwx=1234567 8
>
Can somebody point me in the right direction or provide me with some
sample XSLT transformation code that can do this.
>
Keep in mind, I would like to keep this as generic as possible. That
is I don't want to reference element or attributes by names. I would
like something like this
>
for each element
do
if attribute
print element_attribu te=value
else
print element=value
done
>
As oppose to say search element "pqr" and print value
>
Thanks to all who answer

You could run the onsgmls validating parser to output ESIS (below)
which can trivially be processed by (eg) awk or similar.

?xml version="1.0" encoding="UTF-8"
(abc
-\n\012
(def
-\n\012
(mno
-2008-06-11-13:15:59
)mno
-\n\012
Astu CDATA World
(pqr
-Hello
)pqr
-\n\012
)def
-\n\012
(ghi
-\n\012
Avwx CDATA 12345678
(jkl
-
)jkl
-\n\012
)ghi
-\n\012
)abc

///Peter

[David Carlisle]

Re: printing XML file with XSLT code

$ saxon l.xml l.xsl

mno=2008-06-11-13:15:59
pqr_stu=World
pqr=Hello
jkl_vwx=1234567 8

is produced by:

<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:strip-space elements="*"/>
<xsl:template match="text()">
<xsl:value-of select="concat( ' ',name(..),'= ',.)"/>
</xsl:template>
<xsl:template match="@*">
<xsl:value-of select="concat( ' ',name(..),'_ ',name(.),'=',. )"/>
</xsl:template>
<xsl:template match="*">
<xsl:apply-templates select="@*|node ()"/>
</xsl:template>
</xsl:stylesheet>

David

--

http://dpcarlisle.blogspot.com

[Hermann Peifer]

Re: printing XML file with XSLT code

Jürgen Kahrs wrote:

Stu wrote:
>

>Assume the following XML file:
>>
><?xml version="1.0" encoding="UTF-8"?>
><abc>
> <def>
> <mno>2008-06-11-13:15:59</mno>
> <pqr stu="World">Hel lo</pqr>
> </def>
> <ghi>
> <jkl vwx="12345678" </jkl>
> </ghi>
></abc>
>>
>Below is my desired out. As you can see for each element I print
>"element=value " and for each attribute within an element I print
>"element_attri bute=value"
>>
>mno=2008-06-11-13:15:59
>pqr=Hello
>pqr_stu=Worl d
>jkl_vwx=123456 78

>
The following script in XMLgawk does it:
>
@load xml
XMLCHARDATA { data = $0 }
XMLSTARTELEM { for (i in XMLATTR) print XMLSTARTELEM "_" i "=" XMLATTR[i] }
XMLENDELEM && data ~ /[:alnum:]/ { print XMLENDELEM "=" data }
>
It produces the output you wanted (except for a change in sequence).

[:alnum:] delivers correct results with the given test data, but I guess you meant:

XMLENDELEM && data ~ /[[:alnum:]]/ ...

Hermann

[=?ISO-8859-1?Q?J=FCrgen_Kahrs?=]

Re: printing XML file with XSLT code

Hermann Peifer schrieb:

>The following script in XMLgawk does it:
>>
>@load xml
>XMLCHARDATA { data = $0 }
>XMLSTARTELEM { for (i in XMLATTR) print XMLSTARTELEM "_" i "="
>XMLATTR[i] }
>XMLENDELEM && data ~ /[:alnum:]/ { print XMLENDELEM "=" data }
>>
>It produces the output you wanted (except for a change in sequence).

>
[:alnum:] delivers correct results with the given test data, but I guess
you meant:
XMLENDELEM && data ~ /[[:alnum:]]/ ...

No, I thought [:alnum:] was sufficient.
Does it really make a difference in this example ?

[Hermann Peifer]

Re: printing XML file with XSLT code

Jürgen Kahrs wrote:

Hermann Peifer schrieb:
>

>>The following script in XMLgawk does it:
>>>
>>@load xml
>>XMLCHARDATA { data = $0 }
>>XMLSTARTELE M { for (i in XMLATTR) print XMLSTARTELEM "_" i "="
>>XMLATTR[i] }
>>XMLENDELEM && data ~ /[:alnum:]/ { print XMLENDELEM "=" data }
>>>
>>It produces the output you wanted (except for a change in sequence).

>>
>[:alnum:] delivers correct results with the given test data, but I
>guess you meant:
>XMLENDELEM && data ~ /[[:alnum:]]/ ...

>
No, I thought [:alnum:] was sufficient.
Does it really make a difference in this example ?

[:alnum:] is treated as list of characters: 'a', 'l', 'm', 'n', 'u', and ':', whereas [[:alnum:]] is treated as a character class. The former will match 'Hello', but not 'HELLO', whereas the latter will match both. However, this doesn't make any difference with the given test data.

To make your script a bit more generic and robust (in case of empty elements), I would go for:

$ cat hermann.awk
@load xml
XMLCHARDATA { data = $0 }
XMLSTARTELEM { data = ""; for (i in XMLATTR) print XMLSTARTELEM "_" i "=" XMLATTR[i] }
XMLENDELEM && data !~ /^[[:space:]]*$/ { print XMLENDELEM "=" data }

See below the different results for this sample data:

$ cat file1
<?xml version="1.0" encoding="UTF-8"?>
<abc>
<def>
<mno>2008-06-11-13:15:59</mno>
<pqr stu="World">Hel lo</pqr>
<a1>.,-?(){}[]</a1>
<a2>ABC</a2><a3/>
</def>
<ghi>
<jkl vwx="12345678" </jkl>
</ghi>
</abc>

$ xgawk -f hermann.awk file1
mno=2008-06-11-13:15:59
pqr_stu=World
pqr=Hello
a1=.,-?(){}[]
a2=ABC
jkl_vwx=1234567 8

$ xgawk -f juergen.awk file1
mno=2008-06-11-13:15:59
pqr_stu=World
pqr=Hello
a2=ABC
a3=ABC
jkl_vwx=1234567 8

[=?ISO-8859-1?Q?J=FCrgen_Kahrs?=]

Re: printing XML file with XSLT code

Hermann Peifer schrieb:

Jürgen Kahrs wrote:

>Hermann Peifer schrieb:
>>

>>>The following script in XMLgawk does it:
>>>>
>>>@load xml
>>>XMLCHARDAT A { data = $0 }
>>>XMLSTARTEL EM { for (i in XMLATTR) print XMLSTARTELEM "_" i "="
>>>XMLATTR[i] }
>>>XMLENDELEM && data ~ /[:alnum:]/ { print XMLENDELEM "=" data }
>>>>
>>>It produces the output you wanted (except for a change in sequence).
>>>
>>[:alnum:] delivers correct results with the given test data, but I
>>guess you meant:
>>XMLENDELEM && data ~ /[[:alnum:]]/ ...

>>
>No, I thought [:alnum:] was sufficient.
>Does it really make a difference in this example ?

>
[:alnum:] is treated as list of characters: 'a', 'l', 'm', 'n', 'u', and
':', whereas [[:alnum:]] is treated as a character class. The former
will match 'Hello', but not 'HELLO', whereas the latter will match both.

Thanks for the reminder.

You know both languages equally well (XSL and XMLgawk).
Would you prefer the XSL solution that was posted here ?

[Hermann Peifer]

Re: printing XML file with XSLT code

On Jun 12, 10:53 pm, Jürgen Kahrs <Juergen.KahrsD ELETET...@vr-web.de>
wrote:

You know both languages equally well (XSL and XMLgawk).
Would you prefer the XSL solution that was posted here ?

My rule of thumb is:

Big files (say: 100+ MB), with a flat, regular structure -XMLgawk
Small files with many optional and/or empty elements -XSL

Hermann

[Joseph J. Kesselman]

Re: printing XML file with XSLT code

Hermann Peifer wrote:

Big files (say: 100+ MB), with a flat, regular structure -XMLgawk
Small files with many optional and/or empty elements -XSL

Depends in part the XSLT processor, of course. Some handle large
documents better than others.

[Hermann Peifer]

Re: printing XML file with XSLT code

On Jun 13, 3:55 pm, "Joseph J. Kesselman" <keshlam-nos...@comcast. net>
wrote:

Hermann Peifer wrote:

Big files (say: 100+ MB), with a flat, regular structure -XMLgawk
Small files with many optional and/or empty elements -XSL

>
Depends in part the XSLT processor, of course. Some handle large
documents better than others.

Of course. Reality is not as black and white as my rule of thumb
suggests. Would you have any pointer to some helpful XSLT processor
comparison/benchmarking?

BTW, another rule of thumb is:

Transformation: XML to text, with regex string processing -XMLgawk
Transformation: XML to XML (in my context usually: XML to KML) -XSL

Hermann

[Joseph J. Kesselman]

Re: printing XML file with XSLT code

Hermann Peifer wrote:

Of course. Reality is not as black and white as my rule of thumb
suggests. Would you have any pointer to some helpful XSLT processor
comparison/benchmarking?

Most of what I've been doing has been using the W3C/NIST XPath and XSLT
conformance suites (pointed to from http://www.w3.org/QA/TheMatrix),
test sets such as the DataPower (now IBM) XSLTMark kernels (described at
http://www.xml.com/pub/a/2001/03/28/xsltmark/), or customer datasets
(which for obvious reasons I can't share).

I do know that the XSLT processor in the DataPower product can recognize
at least some cases where a document can be processed in a streaming
manner rather than reading it all into memory at once. That depends on
the nature of the stylesheet, of course; I'm not sure exactly where the
current limits are. But when this optimization works, it permits
handling huge documents and reduces latency, both of which are good
things. Websearch on "DataPower streaming" finds some discussion of this.

I don't think Apache Xalan has any true streaming capability yet, though
we've wanted it for many years. However, Xalan's internal data model
(DTM) is considerably more space-efficient than a standard Java DOM,
which improves its ability to handle large documents. (We had a version
of DTM which reduced overhead to only 16 bytes per XML node -- but
compressing things that far cost us some performance and imposed some
limitations we didn't like, so we had to let it grow a bit.)

I haven't used XMLgawk. But part of the point of XML is precisely that
adopting a shared (and relatively simple) syntax eases the task of
writing useful and reusable tools, and there's certainly a large amount
of "let a thousand flowers bloom" built into that assumption. I prefer
to stick to the W3C's standardized tools as much as possible, both to
push those to improve and for best portability of my work, but if
another tool does something XSLT really can't, or does it far better
than the copy of XSLT you have available to you, I'm not going to tell
you not to use it.

[Hermann Peifer]

Re: printing XML file with XSLT code

Joseph J. Kesselman wrote:

Hermann Peifer wrote:

>Of course. Reality is not as black and white as my rule of thumb
>suggests. Would you have any pointer to some helpful XSLT processor
>comparison/benchmarking?

>
Most of what I've been doing has been using the W3C/NIST XPath and XSLT
conformance suites (pointed to from http://www.w3.org/QA/TheMatrix),
test sets such as the DataPower (now IBM) XSLTMark kernels (described at
http://www.xml.com/pub/a/2001/03/28/xsltmark/), or customer datasets
(which for obvious reasons I can't share).
>
I do know that the XSLT processor in the DataPower product can recognize
at least some cases where a document can be processed in a streaming
manner rather than reading it all into memory at once. That depends on
the nature of the stylesheet, of course; I'm not sure exactly where the
current limits are. But when this optimization works, it permits
handling huge documents and reduces latency, both of which are good
things. Websearch on "DataPower streaming" finds some discussion of this.
>
I don't think Apache Xalan has any true streaming capability yet, though
we've wanted it for many years. However, Xalan's internal data model
(DTM) is considerably more space-efficient than a standard Java DOM,
which improves its ability to handle large documents. (We had a version
of DTM which reduced overhead to only 16 bytes per XML node -- but
compressing things that far cost us some performance and imposed some
limitations we didn't like, so we had to let it grow a bit.)
>
I haven't used XMLgawk. But part of the point of XML is precisely that
adopting a shared (and relatively simple) syntax eases the task of
writing useful and reusable tools, and there's certainly a large amount
of "let a thousand flowers bloom" built into that assumption. I prefer
to stick to the W3C's standardized tools as much as possible, both to
push those to improve and for best portability of my work, but if
another tool does something XSLT really can't, or does it far better
than the copy of XSLT you have available to you, I'm not going to tell
you not to use it.

Thanks for the information.

I can't remember that I ever came across something that XSLT really can't do, but string processing is obviously not a strength of XSLT 1.0. I read that this improved with version 2.0, but I don't have any own experience. For transforming large XML documents into text format, which in my context often includes some regex based string processing: XMLgawk continues to be my favourite tool.

Hermann