Copying without namespace?

[Andre-John Mas]

Hi,

I have some code that looks as follows:

<xsl:for-each select="$pageMe taData/*">
<xsl:choose>
<xsl:when test="local-name() = 'meta'">
<xsl:copy-of select="."/>
</xsl:when>
<xsl:otherwis e>
<meta content="{.}" name="{local-name()}"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>

The problem is that it copies the namespace when it does so (it
appears to be implied, rather than declared). So this:

<meta content="abc" name="dc.creato r"/>

becomes this in the final output:

<meta xmlns="http://www.myco.com/datalist" content="yuri"
name="dc.creato r"/>

How do I copy the element and not have the namespace in the result?
Note that I only want to apply this here, and not globaly to all
cases.

Andre

[Pavel Lepin]

Re: Copying without namespace?


Andre-John Mas <andrejohn.mas@ gmail.comwrote in
<4d1e8b09-6641-497e-a194-f87f9b905c8e@s1 2g2000prg.googl egroups.com>:

<xsl:for-each select="$pageMe taData/*">
<xsl:choose>
<xsl:when test="local-name() = 'meta'">
<xsl:copy-of select="."/>
</xsl:when>
<xsl:otherwis e>
<meta content="{.}" name="{local-name()}"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>

Awful.

The problem is that it copies the namespace when it does
so (it appears to be implied, rather than declared).

"Implied rather than declared"? What do you mean?

So this:
>
<meta content="abc" name="dc.creato r"/>
>
becomes this in the final output:
>
<meta xmlns="http://www.myco.com/datalist" content="yuri"
name="dc.creato r"/>

And what is the problem - the fact that your resulting meta
element is in http://www.myco.com/datalist namespace, or
the fact that this namespace is explicitly declared as the
default namespace on this element?

How do I copy the element and not have the namespace in
the result?

You can't. You can only create an element with the same
name, but not in a namespace.

I would recommend posting a minimal complete example of your
problem, since it's not really clear to me what your
problem is. Reading some introductory materials on XML
Namespaces might be advisable as well.

--
When all you have is a transformation engine, everything
looks like a tree.

[Johannes Koch]

Re: Copying without namespace?

Pavel Lepin schrieb:

Andre-John Mas <andrejohn.mas@ gmail.comwrote in
<4d1e8b09-6641-497e-a194-f87f9b905c8e@s1 2g2000prg.googl egroups.com>:

> <xsl:for-each select="$pageMe taData/*">
> <xsl:choose>
> <xsl:when test="local-name() = 'meta'">
> <xsl:copy-of select="."/>
> </xsl:when>
> <xsl:otherwis e>
> <meta content="{.}" name="{local-name()}"/>
> </xsl:otherwise>
> </xsl:choose>
> </xsl:for-each>

>
Awful.
>

>The problem is that it copies the namespace when it does
>so (it appears to be implied, rather than declared).

>
"Implied rather than declared"? What do you mean?
>

>So this:
>>
><meta content="abc" name="dc.creato r"/>
>>
>becomes this in the final output:
>>
><meta xmlns="http://www.myco.com/datalist" content="yuri"
>name="dc.creat or"/>

>
And what is the problem - the fact that your resulting meta
element is in http://www.myco.com/datalist namespace, or
the fact that this namespace is explicitly declared as the
default namespace on this element?
>

>How do I copy the element and not have the namespace in
>the result?

>
You can't. You can only create an element with the same
name, but not in a namespace.
>
I would recommend posting a minimal complete example of your
problem, since it's not really clear to me what your
problem is.

I guess, the problem is that DTDs are not namespace-aware and so the
result of the transformation is not DTD-valid.

--
Johannes Koch
In te domine speravi; non confundar in aeternum.
(Te Deum, 4th cent.)

[Pavel Lepin]

Re: Copying without namespace?


Johannes Koch <koch@w3develop ment.dewrote in
<47c7da46$0$580 $6e1ede2f@read. cnntp.org>:

Pavel Lepin schrieb:

>Andre-John Mas <andrejohn.mas@ gmail.comwrote:

>>So this:
>>>
>><meta content="abc" name="dc.creato r"/>
>>>
>>becomes this in the final output:
>>>
>><meta xmlns="http://www.myco.com/datalist"
>>content="yuri " name="dc.creato r"/>

>>
>And what is the problem - the fact that your resulting
>meta element is in http://www.myco.com/datalist
>namespace, or the fact that this namespace is explicitly
>declared as the default namespace on this element?

>
I guess, the problem is that DTDs are not namespace-aware
and so the result of the transformation is not DTD-valid.

I think someone should start a "Let the DTDs go!" movement,
would be about time. Hmm, maybe I could, but... hold on for
a second... Yep. That's my natural laziness kicking in.
Never mind.

--
When all you have is a transformation engine, everything
looks like a tree.

[Johannes Koch]

Re: Copying without namespace?

Pavel Lepin schrieb:

Namespace prefix declaration
alone shouldn't break XHTML validation I believe.

It breaks XHTML DTD validation, because the XHTML DTDs allow the xmlns
"attribute" on the html element only.

--
Johannes Koch
In te domine speravi; non confundar in aeternum.
(Te Deum, 4th cent.)

[Joseph Kesselman]

Re: Copying without namespace?

Andre-John Mas wrote:

but how do you exclude an anonymous namespace:
xmlns=""

The default namespace declaration is generally not generated into the
output unless it is required, meaning that the parent element is in a
different default namespace. I'd have to take another look at your
specific example to see whether that's what's going on, but if it is
then the proper answer is "if you don't want to change default
namespaces, don't output an element that's in a different default
namespace than its parent."

--
Joe Kesselman / Beware the fury of a patient man. -- John Dryden