Extraction Of Attribute value

[AwanJohnie]

I have an xml document as shown (not mine but extracted from an
application):

<category defid="468808" name="Global Information Attributes"
versionid="6">
<attributeset attid="1" name="Global Information Attributes">
<attribute attid="3" name="Issue_Dat e"
type="-7">2003-09-30T00:00:00</attribute>
<attribute attid="4" name="Review_Da te"
type="-7">2006-10-30T00:00:00</attribute>
</attributeset>
</category>


I need to write an XSL to extract the values of 10 the Issue_Date (In
this case = 2003-09-30T00:00:00) and Review_Date (In this case =
2006-10-30T00:00:00)

I wrote this in my xsl:

<xsl:value-of select="categor y/attributeset/attribute/@attid=4"/>

It did not give me the desired result. It gave me a value = true.

In addition how can I trim the date to show only "2003-09-30" for
example.

Thanks

[Berislav Lopac]

Re: Extraction Of Attribute value

On 30 Sep 2004 03:01:55 -0700, AwanJohnie wrote:
[color=blue]
> <xsl:value-of select="categor y/attributeset/attribute/@attid=4"/>[/color]


IIRC it should be

<xsl:value-of select="categor y/attributeset/attribute[@attid=4]" />

[Joris Gillis]

Re: Extraction Of Attribute value

to trim the date:

<xsl:value-of select="
substring-before(category/attributeset/attribute[@attid=4],'T')
"/>

[AwanJohnie]

Re: Extraction Of Attribute value

> > <xsl:value-of select="categor y/attributeset/attribute/@attid=4"/>[color=blue]
>
>
> IIRC it should be
>
> <xsl:value-of select="categor y/attributeset/attribute[@attid=4]" />[/color]

Thanks for your feedback but it did not return any value.

Secondly, how can I trim the date if result is obtained?

[Goudvin Emmanuel]

Re: Extraction Of Attribute value

Try

<xsl:value-of select="categor y/attributeset/attribute[@attid='4']"/>

AwanJohnie wrote:
[color=blue]
> I have an xml document as shown (not mine but extracted from an
> application):
>
> <category defid="468808" name="Global Information Attributes"
> versionid="6">
> <attributeset attid="1" name="Global Information Attributes">
> <attribute attid="3" name="Issue_Dat e"
> type="-7">2003-09-30T00:00:00</attribute>
> <attribute attid="4" name="Review_Da te"
> type="-7">2006-10-30T00:00:00</attribute>
> </attributeset>
> </category>
>
>
> I need to write an XSL to extract the values of 10 the Issue_Date (In
> this case = 2003-09-30T00:00:00) and Review_Date (In this case =
> 2006-10-30T00:00:00)
>
> I wrote this in my xsl:
>
> <xsl:value-of select="categor y/attributeset/attribute/@attid=4"/>
>
> It did not give me the desired result. It gave me a value = true.
>
> In addition how can I trim the date to show only "2003-09-30" for
> example.
>
> Thanks[/color]

[AwanJohnie]

Re: Extraction Of Attribute value (Thanks a Zillion)

Goudvin Emmanuel <Emmanuel.Goudv in@voila.fr> wrote in message news:<U8Y6d.266 4$1p.2186@nntps erver.swip.net> ...[color=blue]
> Try
>
> <xsl:value-of select="categor y/attributeset/attribute[@attid='4']"/>
>
> AwanJohnie wrote:
>[/color]
THANKS EVERYBODY.
IT WORKED!!!
THE ACTUAL CODES USED.....

<xsl:value-of select="substri ng-before(category/attributeset/attribute[@attid='3'],'T')"/>