xslt not working when xml has xmlns="urn" in root element.

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  • Lee
    #1

    xslt not working when xml has xmlns="urn" in root element.

    Hello guys, I am new to XML and working on a XSLT to transforn yahoo
    shopping search result to html. my problem is the return XML contain
    xmlns in root element, here is the sample xml:

    <?xml version="1.0" encoding="UTF-8"?>
    <?xml-stylesheet type="text/xsl" href="aproducts earch.xslt"?>
    <ProductSearc h xmlns:xsi="http ://www.w3.org/2001/XMLSchema-instance"
    xmlns="urn:yaho o:aprods" xsi:schemaLocat ion="urn:yahoo: aprods
    http://api.shopping.ya hoo.com/shoppingservice/v2/aproductsearch. xsd">
    ............... ....
    </ProductSearch>


    I am testing my xslt file:


    <?xml version="1.0" encoding="utf-8"?>
    <xsl:styleshe et version="1.0"
    xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
    <xsl:output method="html" encoding="utf-8" omit-xml-
    declaration="ye s"
    indent="yes"/>


    <xsl:template match="/">
    <HTML>
    <BODY>
    <TABLE BORDER="2">
    <TR>
    <TD>From</TD>
    <TD>To</TD>
    </TR>
    <xsl:for-each select="Product Search/
    Products/Product">
    <TR>
    <TD>
    <xsl:value-of
    select="Catalog/PriceFrom"/>
    </TD>
    <TD>
    <xsl:value-of
    select="Catalog/PriceTo"/>
    </TD>
    </TR>
    </xsl:for-each>
    </TABLE>
    </BODY>
    </HTML>
    </xsl:template>


    </xsl:stylesheet>


    if I remove the xmlns="urn:yaho o:aprods" from the XML, then the xslt
    works fine, otherwise, nothing shows up. I don't know what is the
    problem of my xslt file.


    Thanks a lot!

    Tags: None
    • p.lepin@ctncorp.com
      #2
      Re: xslt not working when xml has xmlns=&quot;urn &quot; in root element.

      On Apr 3, 9:09 pm, "Lee" <lee.jenkins... @gmail.comwrote :
      <?xml version="1.0" encoding="UTF-8"?>
      <?xml-stylesheet type="text/xsl"
      href="aproducts earch.xslt"?>
      <ProductSearc h
      xmlns:xsi="http ://www.w3.org/2001/XMLSchema-instance"
      xmlns="urn:yaho o:aprods"
      xsi:schemaLocat ion=
      "urn:yahoo:apro dshttp://api.shopping.ya hoo.com/shoppingservice/v2/aproductsearch. xsd">
      ............... ...
      </ProductSearch>
      >
      <?xml version="1.0" encoding="utf-8"?>
      <xsl:styleshe et version="1.0"
      xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
      <xsl:output method="html" encoding="utf-8"
      omit-xml-declaration="ye s" indent="yes"/>
      <xsl:template match="/">
      <HTML>
      <BODY>
      <TABLE BORDER="2">
      <TR>
      <TD>From</TD>
      <TD>To</TD>
      </TR>
      <xsl:for-each
      select="Product Search/Products/Product">
      <TR>
      <TD>
      <xsl:value-of select="Catalog/PriceFrom"/>
      </TD>
      <TD>
      <xsl:value-of select="Catalog/PriceTo"/>
      </TD>
      </TR>
      </xsl:for-each>
      </TABLE>
      </BODY>
      </HTML>
      </xsl:template>
      </xsl:stylesheet>
      Using tabs or 8 spaces for indentation on the usenet is not
      particularly wise.
      if I remove the xmlns="urn:yaho o:aprods" from the XML,
      then the xslt works fine, otherwise, nothing shows up. I
      don't know what is the problem of my xslt file.
      What did you expect? ProductSearch element in the XML
      document you've provided is really
      {urn:yahoo:apro ds}ProductSearc h, and you're selecting
      {}ProductSearch elements in your for-each. Consider reading
      some introductory material on XML Namespaces overall and on
      using XML Namespaces in XSL Transformations in particular.

      --
      Pavel Lepin

        Comment

        • Martin Honnen
          #3
          Re: xslt not working when xml has xmlns=&quot;urn &quot; in root element.

          Lee wrote:
          <ProductSearc h xmlns:xsi="http ://www.w3.org/2001/XMLSchema-instance"
          xmlns="urn:yaho o:aprods" xsi:schemaLocat ion="urn:yahoo: aprods
          http://api.shopping.ya hoo.com/shoppingservice/v2/aproductsearch. xsd">
          ............... ...
          </ProductSearch>
          <xsl:styleshe et version="1.0"
          xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
          Add
          xmlns:ap="urn:y ahoo:aprods"
          on the xsl:stylesheet element, then use the prefix 'ap' in your XPath
          expressions e.g.
          <xsl:for-each select="Product Search/
          Products/Product">
          <xsl:for-each select="ap:Prod uctSearch/ap:Products/ap:Product">
          <xsl:value-of
          select="Catalog/PriceFrom"/>
          <xsl:value-of select="ap:Cata log/ap:PriceForm">
          <xsl:value-of
          select="Catalog/PriceTo"/>
          <xsl:value-of select="ap:Cata log/ap:PriceTo"/>


          --

          Martin Honnen
          http://JavaScript.FAQTs.com/

            Comment

            • Lee
              #4
              Re: xslt not working when xml has xmlns=&quot;urn &quot; in root element.

              On Apr 4, 4:37 am, Martin Honnen <mahotr...@yaho o.dewrote:
              Lee wrote:
              <ProductSearc h xmlns:xsi="http ://www.w3.org/2001/XMLSchema-instance"
              xmlns="urn:yaho o:aprods" xsi:schemaLocat ion="urn:yahoo: aprods
              http://api.shopping.ya hoo.com/shoppingservice/v2/aproductsearch. xsd">
              ............... ...
              </ProductSearch>
              <xsl:styleshe et version="1.0"
              xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
              >
              Add
              xmlns:ap="urn:y ahoo:aprods"
              on the xsl:stylesheet element, then use the prefix 'ap' in your XPath
              expressions e.g.
              >
              <xsl:for-each select="Product Search/
              Products/Product">
              >
              <xsl:for-each select="ap:Prod uctSearch/ap:Products/ap:Product">
              >
              <xsl:value-of
              select="Catalog/PriceFrom"/>
              >
              <xsl:value-of select="ap:Cata log/ap:PriceForm">
              >
              <xsl:value-of
              select="Catalog/PriceTo"/>
              >
              <xsl:value-of select="ap:Cata log/ap:PriceTo"/>
              >
              --
              >
              Martin Honnen
              http://JavaScript.FAQTs.com/
              Thanks a lot, it works fine now. thanks for the help.

                Comment

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