how to pass a variable to xsl and how xsl can recognise it?

[renoua]

hello,
I have this javascript code

function displayResult2(id) 
{
xml=loadXMLDoc("anna.xml");
xsl=loadXMLDoc("c011.xsl");

// code for IE
if (window.ActiveXObject)
  {
  ex=xml.transformNode(xsl);
  document.getElementById("right").innerHTML=ex;
  }
// code for Mozilla, Firefox, Opera, etc.
else if (document.implementation && document.implementation.createDocument)
  {
  var xsltProcessor=new XSLTProcessor();
  xsltProcessor.importStylesheet(xsl);
  resultDocument = xsltProcessor.transformToFragment(xml,document);
 document.getElementById("right").appendChild(resultDocument);
  }
}

and I want to pass the variable id at the c011.xsl
after that.. how c011.xsl can recognize that variable? what's the syntax?
any help would be appreciated :)

[Dormilich]

setting parameters in Mozilla

[renoua]

very usefull article.. thnx!
so, i wrote that line of code :

xsltProcessor.setParameter(null, "id", xsl);

I don't know why i put xsl in the parameters but alternatively it's not working.

I added the xsl param at c011.xsl

<xsl:param name="id"/>

but the xsl if condition does not work :(

<xsl:if test="did/unitid='$id'">
[I]xsl tranformation[/I]
</xsl:if>

maybe the syntax is wrong..
but I don't know how to solve this.. i google it i changed it hundred of times but still failure...

[Dormilich]

try

<xsl:if test="did/unitid/text() = $id">

[renoua]

No, it doesn't work..
I added ' ' but still nothing..

<xsl:if test="did/unitid/text() = '$id'">

maybe the variable from javascript didn't pass successfully?

[Dormilich]

I deliberately omitted the ' '.

further, what does "/did/unitid" return normally, a node or a nodeset?

[renoua]

With or without ' '
I don't see xsl transformation

[Dormilich]

does it work, when you do it manually?

[renoua]

A node,
well when i choose one of 106 unitid, my xml file has,
for example 'L7346'

"/did/unitid='L7346'"
I see the result i want.

[Dormilich]

well, I’ve never done XSLT in JavaScript (for obvious reasons) so I’m not of much help in debugging this. Personally, I prefer server-side XSLT, esp. since AJAX (target.appendCh ild(XHR.respons eXML.documentEl ement);).

[renoua]

well,
I suppose I have made wrong the syntax of this

xsltProcessor.s etParameter(nul l, "id", xsl);

anyway, thank you very very much for your interest and help ! I hope to find a solution asap.. :)

[Dormilich]

now that you mention it, yes. (look at the example provided) the 3rd parameter of .setParameter() is the value of the parameter, where you passed the XSL file.

[renoua]

well yes the syntax was wrong

i corrected the code but

id is a variable but when i write it like that:
xsltProcessor.s etParameter(nul l, "uid", "id")

it passes to c011.xsl like a static text "id" that's why I could not see result the condition was always false


do you know how can i pass it dynamically?
what i Have to write at the 3rd parameter exactly?

[renoua]

I found it i didn't need " ".

so the right syntax is
xsltProcessor.s etParameter(nul l, "uid", id);