Submission of a form using javascript....

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  • phpuser123
    New Member
    • Dec 2009
    • 108
    #1

    Submission of a form using javascript....

    I want to submit my form using javascript but the prob I am facing here is when using this method,the form is being submitted irrespective of the return value of onsubmit .My script is .....
    Code:
    <html>
<script type="text/javascript">
function chk(){

	document.formname.submit();
}
</script>
<body>
<form name="formname" action="from.html" onsubmit="return false" method="get">
<input type="text" name="firstbox">

<button onclick="chk()">Submit</button>
</form>
</body>
</html>
    Any help willl be deeply appreciated...T hanks
    Last edited by gits; Dec 14 '09, 06:16 PM. Reason: added code tags
    Tags: htmlform, javascript
    • gits
      Recognized Expert Moderator Expert
      • May 2007
      • 5390
      #2
      that is correct ... what do you want to achieve?

      kind regards

        Comment

        • phpuser123
          New Member
          • Dec 2009
          • 108
          #3
          RE:Need help on sessions

          the prob I am facing is that although the onsubmit has a return value of false,it is being submitted.When I am using <input type="submit" value="submit"> to submit the form,the form is nt submitted since the onsubmit holds a value of false..Why this difference? And what cn I do so that the form is not submitted with the javascript?

            Comment

            • gits
              Recognized Expert Moderator Expert
              • May 2007
              • 5390
              #4
              just don't call the submit()-method when the form shouldn't be submitted ... a simple if-else would do the job in your chk()-function

              kind regards

                Comment

                • acoder
                  Recognized Expert MVP
                  • Nov 2006
                  • 16032
                  #5
                  ...or avoid the use of chk() and make a call to your validation function onsubmit:
                  Code:
                  onsubmit="return validate()"
                  Also note that button by default is a submit button. Perhaps you meant to use an input button (input type="button"). Alternatively, set the button type to "button".

                  One more thing: the submit is prevented when the user clicks on the submit button, not when the form is submitted using JavaScript via submit().

                    Comment

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