Can I verify ip address 192.168.120.1

[vikas251074]

I have developed form for assigning ip address to computers, printers, routers, switch, camera and ip phone. When a user enter ip address like 192.168.120.1, Here, there are four parts of ip address 192, 168, 120 and 1. Can I verify each part within the range of 0-255? How can this be verified?
And also that all four part must be entered.

Thanks and regards,
Vikas

[veenna]

First store that ip address in one variable 'str'

try this function

<script type="text/javascript">
function SplitStr(thiss)
{
var str=thiss.value;
var i=0;
var dot= new Array();
	dot=str.split('.');

for(i=0;i<=dot.length-1;i++)
{
if(dot[i]<=0 || dot[i]>=255)
{
alert('num should be between 0 to 255');
}
}
}
</script>

call this function like:

<input type="text" name="txtIp" id="txtIp" onblur="SplitStr(this);"/>

[vikas251074]

Yes madam, you are great.

It is working fine. Here only little modification requires. If found out of range, then cursor should remain on same field. So I added line

document.myform.vlan_first_ip.focus();

after the alert message.

But due to adding above line, I can not use splitstr() for two more fields which goes through the same process.

I don't want to create more than one function which have same process but different fields. Can I do this?

Thanks and regards,
Vikas

[veenna]

vikas,


I think instead of this line

document.myform.vlan_first_ip.focus();

you can give thiss.focus(); after alert message.



regards
Veenna

[vikas251074]

No madam, this is not working.

Thanks and regards,
Vikas

[vikas251074]

if first ip = 192.168.120.1 is given by user, then last ip can automatically assigned as 192.168.120.255 .

For this I have written following code, but value is not assigned.

function firstip(temp){
  var str=temp.value;
  var i=0;
  var dot= new Array();
  dot=str.split('.');
  for(i=0;i<=dot.length-1;i++){
    if(dot[i]<=0 || dot[i]>=255){
      document.myform.first_ip.focus();
      alert('IP should be in the range 0 to 255');
    }
  }
  document.myform.last_ip.value = temp.substr(0, temp.lastIndexOf('.'))+255;
}

[veenna]

Vikas,


Are sure that the user will enter .1 in first ip

if yes, you can directly use

var str1=str.substring(0,str.lastIndexOf('.'));
document.getElementById('Text1').value =str1 + '.' + 255;

[vikas251074]

I tried this, but not working. Value is not assigned to last_ip. Even alert message is also not displaying.
The function where code is written is follows -

function firstip(temp){
  var str=temp.value;
  var i=0;
  var dot= new Array();
  dot=str.split('.');
  for(i=0;i<=dot.length-1;i++){
    if(dot[i]<=0 || dot[i]>=255){
      alert('IP should be in the range 0 to 255');
    }
  }
  var str1 = str.substring(0, lastIndexOf('.'));
  alert(str1);
  document.getElementById('lastip').value = str1 + '.' + 255;
}

And where the function is called is as follows -

	    <table>
	      <tr>
		    <td align="right" style="width:125px ">VLAN Name :</td>
		    <td align="left"><input type="text" style="width:250px " name="vlan_name" id="vlan_name" onkeyup="capital(this);"/></td>
		  </tr>
		  <tr>
		    <td align="right" style="width:125px ">VLAN First IP :</td>
		    <td align="left"><input type="text" style="width:100px " name="first_ip" id="first_ip" onchange="firstip(this);"/></td>
          </tr>
          <tr>
            <td align="right" style="width:125px ">VLAN Last IP :</td>
		    <td align="left"><input type="text" style="width:100px " name="last_ip" id="last_id"/></td>
          </tr>
          <tr>
            <td align="right" style="width:125px ">VLAN Subnet Mask :</td>
            <td align="left"><input type="text" style="width:100px " name="subnet_mask"/></td>
          </tr>
        </table>

Thanks and regards,
Vikas

[acoder]

Notice on line 12, you have:

<td align="left"><input type="text" style="width:100px " name="last_ip" id="last_id"/></td>

The "last_id" should obviously be "last_ip". A good old typo.

[vikas251074]

Thanks for find such an error. Still it is not assigning value to 'last_ip' field.

Now I changed to code like this

function firstip(temp){
  var str=temp.value;
  var i=0;
  var dot= new Array();
  dot=str.split('.');
  for(i=0;i<=dot.length-1;i++){
    if(dot[i]<=0 || dot[i]>=255){
      alert('IP should be in the range 0 to 255');
    }
  }
  var str1 = str.substring(0, lastIndexOf('.'));
  document.getElementById('last_ip').value = str1 + '.' + 255;
}

And calling portion of HTML script are -

    <table>
 <tr>
    <td align="right" style="width:125px ">VLAN Name :</td>
    <td align="left"><input type="text" style="width:250px " name="vlan_name" id="vlan_name" onkeyup="capital(this);"/></td>
  </tr>
  <tr>
    <td align="right" style="width:125px ">VLAN First IP :</td>
    <td align="left"><input type="text" style="width:100px " name="first_ip" id="first_ip" onchange="firstip(this);"/></td>
  </tr>
  <tr>
    <td align="right" style="width:125px ">VLAN Last IP :</td>
    <td align="left"><input type="text" style="width:100px " name="last_ip" id="last_ip"/></td>
  </tr>
  <tr>
    <td align="right" style="width:125px ">VLAN Subnet Mask :</td>
    <td align="left"><input type="text" style="width:100px " name="subnet_mask"/></td>
  </tr>
</table>

Thanks and regards,
Vikas

[vikas251074]

Yes sir, I got it. Thanks everybody for help.
Error was in line no. 11 of function description.

var str1 = str.substring(0, lastIndexOf('.'));

silly mistake was 'str' was not added to lastIndexOf('.' )

Thanks and regards
Vikas

[acoder]

Yes, it should've been str.lastIndexOf . I'm sure your error console would've told you that, i.e. that lastIndexOf is undefined. Remember to check if you've got errors.

Glad you've got it working.

[vikas251074]

Can I check first three parts of IP address like 192.168.120 if exist in oracle table, If yes, then how?

Thanks and regards,
Vikas

[acoder]

That would have to be done using server-side code (ASP in your case). JavaScript cannot directly access an Oracle database, though you can use Ajax to make a request to an ASP script.

[vikas251074]

But sir I have to verify IP address without submitting form from oracle database, so how can I use ASP.