Out of bounds exception

[krabina1988]

can anyone here help explain why my code is always getting an outOfBoundsExce ption error??? I want to be the one to do the necessary changes to the code, I just need some explanation. Here is my code.

import java.io.*;

public class Comp
{
    public static void main(String args[]) throws IOException
    {
        BufferedReader buff = new BufferedReader(new InputStreamReader(System.in));
        String input;

        System.out.print("Enter Input String: ");
        input = buff.readLine();

        char [] in = input.toCharArray();

        for(int i=0;i<in.length;i++)
        {
           while(!(in[i]==' '))
           {
               System.out.print(in[i]);
               i++;
           }
           System.out.print("\n");           
        }
    }
}

[krabina1988]

its supposed to work like string tokenizer without using the actual library. the delimiter I am using is white space/" ".

[xunter]

can anyone here help explain why my code is always getting an outOfBoundsExce ption error??? I want to be the one to do the necessary changes to the code, I just need some explanation. Here is my code.

import java.io.*;

public class Comp
{
    public static void main(String args[]) throws IOException
    {
        BufferedReader buff = new BufferedReader(new InputStreamReader(System.in));
        String input;

        System.out.print("Enter Input String: ");
        input = buff.readLine();

        char [] in = input.toCharArray();

        for(int i=0;i<in.length;i++)
        {
           while(!(in[i]==' '))
           {
               System.out.print(in[i]);
               i++;
           }
           System.out.print("\n");           
        }
    }
}

You can't use an increment of the "i" variable. It will increment itself because you are using a "for" loop.
So a reason is the line "i++;" in the "while" block.

[krabina1988]

I tried removing the i++ in the while block...the result is an infinite loop. I added that i++ so that it will be able to print a word one character at a time using the while loop.if the char at i is " " then the next character if it is a letter will be printed on the next line. example: if your input is "xx y" it is supposed to display:

xx
y

[xunter]

I tried removing the i++ in the while block...the result is an infinite loop. I added that i++ so that it will be able to print a word one character at a time using the while loop.if the char at i is " " then the next character if it is a letter will be printed on the next line. example: if your input is "xx y" it is supposed to display:

xx
y

Ok. You should use a "split" method like below:

void main(String[] args) {
String inputString = "some string";
String[] words = inputString.split(" ");
for (int i=0; i<words.length; i++) {
System.out.println(words[i]);
} 
}

/*
Out:
some
string
*/

[ddyer]

the "while" loop must also end on i>=in.length

[krabina1988]

@xunter that would work..but I'm going to expand the program a bit further, say you have "int x=1;" it should out put

int
x
=
1
;

so my delimiter would not only be " " but it should also catch say "x=1;" its output should be the same when my input is "x = 1 ;"

[krabina1988]

@xunter that would work..but I'm going to expand the program a bit further, say you have "int x=1;" it should out put

int
x
=
1
;

so my delimiter would not only be " " but it should also catch say "x=1;" its output should be the same when my input is "x = 1 ;"

[krabina1988]

I tried while(!(in[i]==' ')&&(i<in.lengt h))...its not working.can a while loop have multiple conditions???

[krabina1988]

thank you guys...I got the output I wanted. I just used
while((i<in.len gth)&&!(in[i]==' ')) instead of while(!(in[i]==' ')&&(i<in.lengt h))