2 variables in 1 "if" (new to java)

[brodyvon]

so the program wants me to output the a word based on what the punctuation the user used to end the sentence.
This is what i have so far, i know its really bad...

public class punctuation
{
    public static void main(String[] args)
    {
        int sentence, length, even=%2, odd=%1;
		char question=?, exclamation=!, other=.;
       
        System.out.println("Enter a sentence.");
        sentence = SavitchIn.readLineInt(); 
		int length = sentence.length()
		
		if ( length == even , question)
			System.out.println("YES");
		else (sentence%1 == odd, question)
			System.out.println("NO");
		if (exclamation)
			System.out.println("WOW");
		if (other)
			System.out.println("You always say" + sentence);
		
        System.out.println("Press enter key to end program.");
        String junk;
        junk = SavitchIn.readLine();
    } 
}

[Dheeraj Joshi]

Above code do not make any sense it is not a valid java code.

even=%2

% is not allowed when you declare and initialize the variables.
You can do find modulo of an declared variable.

int even=10;
even = even%2;

char question=?;

char variables must be enclosed within the single quotes.

char question='?';

if ( length == even , question)

You can not compare the integer and character values like above.

And what is SavitchIn? Are you using any custom API's?

SavitchIn.readLineInt();

Is this a wrapper for System class API's?

I suggest you read the JAVA syntax and programing basics to fine tune the program. So that it would at least compile.

Regards
Dheeraj Joshi

[brodyvon]

Thanks for the help really appreciate it.