Math.random and Arrays

[jca613]

this what i got so far. i understand arrays and Math.random i think,but i need to use Math.random and arrays to make 100 random integers between 1 -9 what am i doing wrong? and what am i missing


import java.util.*;

import javax.swing.JOp tionPane;
public class hw_7 {

public static void main(String[] args){
Scanner input=new Scanner(System. in);
int Random =input.nextInt( );
int[] anArray;

anArray = new int[10];
int random =(( int)(Math.rando m()*10)+99);
anArray[0] = 0;
anArray[1] = 1;
anArray[2] = 2;
anArray[3] = 3;
anArray[4] = 4;
anArray[5] =5;
anArray[6] = 6;
anArray[7] = 7;
anArray[8] = 8;
anArray[9] = 9;
System.out.prin t(anArray);





}

}

[jkmyoung]

anArray = new int[10];
Only holds 10 integers. You said you want 100.

int random =(( int)(Math.rando m()*10)+99);
This generates a random number from (99 - 109).

Example:
anArray[0] = ( int)(Math.rando m()*9);

[jca613]

public class hw_7{

public static void main(String[] args){
int[] anArray = new int[100];
for(int index =0; index <anArray.length ; index++){
anArray[index] = (int) (Math.random()* 10);
}
for(int element = 0; element < anArray.length; element++) {
System.out.prin tln("anArray[" + element + "]\t" + anArray[element]);
}
}
}

that is what i got so far now. count the occurrences of the digits. my output should look something liek this

Digit:
0 1 2 3 4 5 6 7 8 9
Count:
8 13 8 12 6 12 9 10 10 12


but what can i ad to my code to make it look like that?

[jkmyoung]

How are you going to store those count numbers? Figure out a way to store the counts.

Then you can loop through your array, setting the storage accordingly.

[jca613]

i honestly i have no idea.my brain is like frying trying to figure this out. do i do something like make another loop array? and put char, then count digitis.