Incremental number skipping

[Van Dugall]

Hi,

I want to write a program to print all numbers from 1 to 100 except those that end in 7 or are a multiple of 7. So the program should skip printing the numbers 7, 14, 17, 21, 27, etc. This might be easy but I want to know an efficient way to do this any ideas??

Thanks,
Van Dugall

[Dheeraj Joshi]

Have you written any code for this? Any errors you are getting?

Regards
Dheeraj Joshi

[Van Dugall]

Not yet... I am thinking about how to do this. I was thinking about doing a while from 1 to 100 and using if statements (mod 7 == 0) to handle the multples of 7 but how should I handle the numbers that end with 7? Also, what is the best way to skip a number when you are incrementing??

Regards,,
V. Dugall

[jkmyoung]

Hint: numbers that end in 0
n mod 10 = 0

Are you using a for loop?

If so, you could have the print statement at the end. If the number matches a condition, use continue, so that the number skips over the print statement.

[Van Dugall]

this is what I have so far.. but I'm having trouble excluding numbers that end in seven...:(

public class Seven {
	public static void main(String[] args){
		int num;
		for(num = 1; num < 101; num++){
			
			if(num != 0 && num%7 == 0){
				continue;
			}
			System.out.println(""+num);
		}
	  }
}

Regards,
Van Dugall

[jkmyoung]

num != 0
This should always be true and is redundant. Take it out.

Hint2: for numbers that end in 1
num mod 10 = 1