Get Correct IP Address

[thesti]

hello,

i'm developing a J2SE VoIP app. i used the InetAddress.get LocalHost() to get the address of the local machine.

it works in xp, but not in Ubuntu. in Ubuntu it gives me "127.0.1.1" , which is listed in /etc/hosts file.

after some search, some advice to use

NetworkInterface.getNetworkInterfaces();

to get list of the available interfaces. but when i println

NetworkInterface iface = en.nextElement();
System.err.println(iface.getInterfaceAddresses());

i get this output

[/fe80:0:0:0:216:36ff:feac:d855%2/64 [null], /192.168.1.2/24 [/192.168.1.255]]

the mac address, then the ip address. how to get only the "192.168.1. 2" part?

i've tried using

iface.getInetAddresses()

but i get the following output

java.net.NetworkInterface$1checkedAddresses@1884a40

another consideration is, which interface address should i use? i can check if it's a loopback interface since NetworkInterfac e has the isLoopback method.

but sometimes, a machine has two or more NIC with one connected to the local network and the other one to the internet. if the user chooses to connect to a local server, i should choose the interface connected the LAN. and the same thing apply if the user wants to connect to a public server in the internet, i should choose the address connected to the internet.

how to determine this?

Thank you.

[chaarmann]

[/fe80:0:0:0:216:36ff:feac:d855%2/64 [null], /192.168.1.2/24 [/192.168.1.255]]

the mac address, then the ip address. how to get only the "192.168.1. 2" part?

Why not use a regular expression to grab it from this String?