504 error

[freddieMaize]

Hi all,

I used the below,

InputStream in = new URL ("http://127.0.0.1/search?q=travel") .openStream () ;

I'm getting the below,
[HTML]java.io.IOExcep tion: Server returned HTTP response code: 504 for URL: http://127.0.0.1/search?q=travel[/HTML]

I've also set the proxies. Also, for your information, when i just chang the url to yahoo.com, its working fine.

Any inputs would help me.

Thanks,
fREDDIE

Out of the box question: I started a thread under networking. Is there a way to move it to somewhere else? May be here??

[JosAH]

Do you have a web server or servlet container etc. running on your local host on
your default port (80)?

kind regards,

Jos

[freddieMaize]

Do you have a web server or servlet container etc. running on your local host on
your default port (80)?

Hi JosAH, i'm actually using those in a standalone java program. So no servlets or web servers are in picture. Sorry i forgot to tell this in the first post.

fREDDIE

[JosAH]

Hi JosAH, i'm actually using those in a standalone java program. So no servlets or web servers are in picture. Sorry i forgot to tell this in the first post.

But then it can never work because you explicitly state that you want to use the
http protocol on your local host (default port 80). There is nothing listening on
that port. If you change your url to point to the yahoo site it works because
yahoo does have such a server available.

kind regards,

Jos

[freddieMaize]

But then it can never work because you explicitly state that you want to use the
http protocol on your local host (default port 80). There is nothing listening on
that port. If you change your url to point to the yahoo site it works because
yahoo does have such a server available.

I would again apologies. Oh god why am i doing this.

The actual url that i used was something like below,

InputStream in = new URL ("http://Anothermachine/search?q=travel") .openStream () ;

To make sure that i dont show up the ip of the server machine that i use (just to be on the safer side) i gave localhost. My mistake.

fREDDIE

[r035198x]

The same question that you were asked by Jos holds for that other machine of yours. If there is a server running there then make sure there are no security restrictions blocking access to the port you are trying to get to.

[freddieMaize]

The same question that you were asked by Jos holds for that other machine of yours. If there is a server running there then make sure there are no security restrictions blocking access to the port you are trying to get to.

Hi, But the url is accessible from my machine if i use it in the address bar. That is how we check if the server is up right? Kindly correct if i'm wrong.

I'll put it in simple terms. If a url works in my browser then obviously i should be able to use that url in my application right?

fREDDIE

[r035198x]

Hi, But the url is accessible from my machine if i use it in the address bar. That is how we check if the server is up right? Kindly correct if i'm wrong.

I'll put it in simple terms. If a url works in my browser then obviously i should be able to use that url in my application right?

fREDDIE

OK then. It's purely a timing out issue then. When you try from the browser, you put exactly the same url as the one in the code right?

[freddieMaize]

OK then. It's purely a timing out issue then. When you try from the browser, you put exactly the same url as the one in the code right?

Exactly the same. In fact i used ctrl+c and ctrl+v.

[r035198x]

Exactly the same. In fact i used ctrl+c and ctrl+v.

Just trying to eliminate another doubt with your proxy ...

Instead of openStream(), try using openConnection( aProxy).getInpu tStream();
For the aProxy part, first try Proxy.NO_PROXY. If that doesn't work then try creating a Proxy object using your proxy settings and use that instead.

[freddieMaize]

Just trying to eliminate another doubt with your proxy ...

Instead of openStream(), try using openConnection( aProxy).getInpu tStream();
For the aProxy part, first try Proxy.NO_PROXY. If that doesn't work then try creating a Proxy object using your proxy settings and use that instead.

:( Unfortunatly that is also resulting the same. Below is the code with the latest changes,

System.getProperties().put("proxySet", "true");
	System.getProperties().put("proxyHost", "proxy");
	System.getProperties().put("proxyPort", "80"); 

        URL yahoo = new URL("http://172.16.1.21/search?q=travel");
        URLConnection yc = yahoo.openConnection();
        BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream()));

I'm wondering why this 504 is comming.

fREDDIE

[r035198x]

Try setting the proxy like I suggested without setting any System properties. See my post above again.

[freddieMaize]

Try setting the proxy like I suggested without setting any System properties. See my post above again.

The below is what you were trying to say right?

SocketAddress addr = new InetSocketAddress("myProxy", 80);
	Proxy proxy = new Proxy(Proxy.Type.HTTP, addr);
	
	URL url = new URL("http://ServerMachine/search?q=travel");
	URLConnection yc = url.openConnection(proxy);
	BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream()));

I initally tried with no proxy also, but then it dint work.

At end of all these attempts i'm still facing the same 504 error.

r035198x, is there anything else i'm missing from what you suggested?

fREDDIE

[freddieMaize]

I initally tried with no proxy also, but then it dint work.

OOPSSSS.... its working... working when i use Proxy.NO_PROXY. .. Thanks man.

fREDDIE

[freddieMaize]

I initially tried with no proxy also, but then it dint work.

OOPSSSS.... its working... working when i use Proxy.NO_PROXY. .. Thanks man.

...without setting any System properties...

By the way, any simple reason or explanation for why it was not working with System properties and why it was working with Proxy.NO_PROXY. Just to know i'm asking

fREDDIE

sorry for the typo